similar to: Select subset with specific distribution parameters.

Apologies for the novice question, but this is likely beyond my google searching range.. I am trying to create a table from the summaries of a file. The 2 column data table looks like; Harry 335/335 Harry 124/506 Harry 124/506 Dick 133 Tom 335/335 Tom 335/335 with 1000 unique values in col 1, 300 unique in col 2. The 'summary' doesn't seem

I hope that somebody can help me with this - I think very simple - issue...? I am running a package that only accepts one line at a time, but I would like to run this package on a dataframe of >500 lines. Dataframe "d" is a single column: APPLES PEARS AUBERGINES KUMQUATS I would like to read one line of my dataframe "d", individually into a new frame "f", then

Dear list, I'm making my current code more generic and would like some advise. The basic problem is subset and the name of the column to be compared for selection. What I've come up with is > data(mammals) > set <- bottompremolars" > subset(mammals, eval(parse(file="",text=set)) > 2) This seems a bit odd. Is there a nicer way? /Fredrik

Hi, I'd like to select one row in a data frame per subset which is maximal for a particular value. I'm pretty close to the solution in the sense that I can easily select the maximal values per subset using "aggregate", but I can't really figure out how to select the rows in the original data frame that are associated with these maximal values. library(stats) # this

I would like to be able to grab x and y columns out of a dataframe and then grab all of the columns that are not equal to x or y. I am sure that I am missing something easy. ftbr_UTM_downstream <- (structure(list(site = c("Jennie_Creek_Main_Stem", "Wolf_Pit_Creek_Main_Stem", "Little_Rockfish_Main_Stem_North", "Big_Muddy_Creek_Main_Stem",

Hi, I have a data frame with columns as follows: tree species (independent variable) and several dependent variables (e.g. carbon, nitrogen, phosphorus). Each row represents one tree sample. Some tree samples are unique species in the data frame while other species were replicated (i.e. rows 1,2,3 may be identical for the "tree species" column but have different values for the

This is an example of two months of data from a twenty four month data set that I would like to apply this too. These data are subsets of the same stations throught time, but differing ones were included on different sampling dates. I would like to subset these data and then put them together as a big matrix with the by column being RiverMile. What is the easiest way to proceed as this is a

This is what I would like to do and it works just fine. Is there a way to shorten this code so I don't have to subset a subset of a subset? d<-subset(subset(subset(subset(x, River.Mile<=202), River.Mile>3), Lagrangian=="Yes"), EventType=="Regular") Stephen -- Let's not spend our time and resources thinking about things that are so little or so large that

I've looked long and hard for this, but maybe I am missing something... There is a nice module that displays histograms reflected in the y axis, i.e. http://addictedtor.free.fr/graphiques/RGraphGallery.php?graph=136 but is it possible to reflect in the x-axis, so to have two datasets, one pointing up and one down rather than left and right? I haven't been able to find a way to plot this

Hi All, Is it possible to use the subset() function to select data based on multiple values of a single variable from a data frame. My actual data set is much bigger and would like to illustrate with following dataset > df = data.frame(x = c('a','b','c','d','e','f','g','h','a','a','b','b'), y =

Hello, I've been using a pre-release version of R v 2.8.0 for Windows for the last couple months. I think that there have been consistent problems with subsetting data sets, but I had usually been able to find work-arounds or was unable to confirm this as a bug. I think now I have, and would love advice on what to do if I've made some error. The data set in question ("c") has

taxa <- (structure(list(Date = structure(c(4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L), .Label = c("2006/04", "2006/05", "2006/07", "2006/10", "2006/12", "2007/02", "2007/04", "2007/06", "2007/08", "2007/10", "2007/12", "2008/01"), class =

d <- structure(list(Site = structure(c(8L, 12L, 7L, 6L, 11L, 5L, 10L, 4L, 3L, 2L, 1L, 9L, 8L, 12L, 7L, 6L, 11L, 5L, 10L, 4L, 3L, 2L, 1L, 9L, 8L, 12L, 7L, 6L, 11L, 5L, 10L, 4L, 3L, 2L, 1L, 9L, 8L, 12L, 7L, 6L, 11L, 5L, 10L, 4L, 3L, 2L, 1L, 9L, 8L, 12L, 7L, 6L, 11L, 5L, 10L, 4L, 3L, 2L, 1L, 9L, 8L, 12L, 7L, 6L, 11L, 5L, 10L, 4L, 3L, 2L, 1L, 9L, 8L, 12L, 7L, 6L, 11L, 5L, 10L, 4L, 3L, 2L, 1L, 9L,

Hello, Is it possible to get all "par" content calculated for "plot" without actually plotting anything? I'm missing an option "plot=FALSE" ... "type="n"" will still open a device and draw the axes ... Thanks, Joh

Hi, all, This might be a stupid question. Is there a single command in R that can revert parameters to default? It is much appreciated. Best wishes, Art Roberts University of Washington

I have a model Q=K*A*(R^r)*(S^s) A, R, and S are data I have and K is a curve fitting parameter. I have linearized as log(Q)=log(K)+log(A)+r*log(R)+s*log(S) I have taken the log of the data that I have and this is the model formula without the K part lm(Q~offset(A)+R+S, data=x) What is the formula that I should use? Thanks for all of your help. I can provide a subset of data if necessary.

Hi, I have a dataset with many variables and observations. The variable Group has two levels: C and P, the Month variable has four levels: 0, 1, 2 and 3. I want to extract a subset of the variable Weight, considering only 1 and 3 levels for Months of the Group variable. I tried the command subset but it did not work. Any suggestions? Thanks, -------------------------------------- Silvano

I am receiving this error running a command on a multi-row data-frame. The data is strings of text (each with new line separator, no spaces, no numerical characters). Error in FUN(X[[1L]], ...) : STRING_ELT() can only be applied to a 'character vector', not a 'integer' I can run single text string into the same command, and so the issue seems to be how the package deals with the

Dear group, Here is a list : l <- list("100415", "100416", "100419", "100420", "100421", "100422", "100423", "100426", "100427", "100428", "100429", "100430", "100503", "100504", "100505", "100506", "100507",

Hello, my series of dates look like [1] "2012-05-30 18:30:00 UTC" "2012-05-30 19:30:00 UTC" [3] "2012-05-30 20:30:00 UTC" "2012-05-30 21:30:00 UTC" [5] "2012-05-30 22:30:00 UTC" "2012-05-30 23:30:00 UTC" [7] "2012-05-31 00:30:00 UTC" "2012-05-31 01:30:00 UTC" [9] "2012-05-31 02:30:00 UTC"