similar to: How to execute a R script but outputting the result to the screen?

Hi, I am wondering how to pop up the graphics window from Rscript. I run the following code, but I don't see the graphics window, even transiently. Regards, Peng $ Rscript plot.R > x=1:10 > y=1:10 > plot(x,y) >

Hi, In 'example(barplot)' running in R, I see 'Hit <Return> to see next plot:', then R waits for my input. I am wondering how to wait for a user response in Rscript. Regards, Peng

read.table terminates the program if the input file is empty. Is there way to let the program continue and return me a NULL instead of terminating the program? $ Rscript read_empty.R > read.table("empty_data.txt") Error in read.table("empty_data.txt") : no lines available in input Execution halted $ cat read_empty.R read.table("empty_data.txt") $ cat

Hi, Right now, I hardcode the file name in the script. But when I change the script name, I have to change the file name in the script to make sure the file name inside the script is synchronized with the script name. I am wondering if there is an automatic way to get the script file name in a script. Regards, Peng $ Rscript get_file_name.R > print('get_file_name.R') [1]

Hi, $ cat commandArgs.R args=commandArgs(trailingOnly=TRUE) args[1]+10 I have the above code. But the following command line gives me an error. I am wondering what is the correct way to convert a string to a vector? $ Rscript commandArgs.R 1:3 > args=commandArgs(trailingOnly=TRUE) > args[1]+10 Error in args[1] + 10 : non-numeric argument to binary operator Execution halted Regards, Peng

Hi, I run the following script. I don't understand why the second 'length(args)' does not show anything but the first one shows '0'. Is it because the command 'q()' affects anything in the if-statement. However, if I change the second 'length(args)' to 'print(length(args))', the script will print the length of 'args'. Can somebody let me know

Hi, See the code below. 'x' is a frame. x$C1 are all numbers 1, 2 and 3. 'as.matrix(x)' convert x$C1 to strings "1", "2" and "3". I'm wondering how to maintain that the first column of 'as.matrix(x)' still numbers. Regards, Peng $ cat read.csv "C1","C2" "1","x" "2","y"

I don't understand why I can not close 'f'. This may be very simple, but I don't see why. Could somebody let me know? $ cat gzfile.csv "","V1","V2","V3","V4","V5" "1",1,5,9,13,17 "2",2,6,10,14,18 "3",3,7,11,15,19 "4",4,8,12,16,20 $ Rscript gzfile.R > f =

Hi, I know that I can use the following script to get the command line options for an R script. But the output shows two many irrelevant arguments. For example, I only want to pass "a", "b" and "c" to the script. The first 5 elements in the variable 'args' are not what I want. I am wondering what is the correct way to pass command line options to an R script.

Hi, I am wondering if some experienced users would help put the ready-to-run code of the examples in the manuals. It would help new users learn R faster by putting all the examples in an ready-to-run R script file. Can somebody help do so sometime and post the code along with the pdf manuals? http://cran.r-project.org/manuals.html Regards, Peng

Hi, I run the following command and try to save the commands that have been run in the script. But it seems that no history is recorded. Is it because that the history is not recorded in Rscript? Regards, Peng $ Rscript savehistory.R > f=tempfile() > f [1] "/tmp/Rtmp7WBjGG/file327b23c6" > history() Error in savehistory(file) : no history available to save Calls: history ->

> > but doesn't emit optnone and nounwind attributes > s/nounwind/noinline On Mon, Jan 28, 2019 at 11:35 AM Jakub (Kuba) Kuderski < kubakuderski at gmail.com> wrote: > As far as I understand, gllvm doesn't run LTO pipeline or any cross-module > optimization, and the optimization level provided is only used to compile > each Translation Unit separately. > If you

I have the following code. I'm wondering why summary() doesn't show F value and Pr? Rscript multi_factor.R > a=3 > b=4 > c=5 > d=6 > e=7 > > A=1:a > B=1:b > C=1:c > D=1:d > E=1:e > > X=matrix(nr=a*b*c*d*e,nc=5) > colnames(X)=LETTERS[1:5] > > for(i_a in 1:a-1) { + for(i_b in 1:b-1) { + for(i_c in 1:c-1) { + for(i_d in 1:d-1) { +

Hi, I'm learning the tutorial. http://llvm.org/docs/tutorial/ I'm wondering if there is already a git repository of the examples in the tutorial so that I don't have to copy the code from the webpage. Thanks! -- Regards, Peng

Hi, x=matrix(1:60,nr=6) I can refer the last 2 rows by x[5:6,] If I don't know the total number of rows is 6, is there a way to refer the last 2 rows? Regards, Peng

Please see the following example. I can not write '"' to a csv file successfully. Could somebody let me if it is possible to write '"' to a csv file with the default setting of write.csv? my_home$ Rscript main_quote.R > x=rbind( + "\"A\"" + , "\"B\"" + ) > x [,1] [1,] "\"A\"" [2,]

Hi, > x=c(rep(1,3),rep(3,2)) > x [1] 1 1 1 3 3 > duplicated(x) [1] FALSE TRUE TRUE FALSE TRUE > As shown in the above code, 'duplicated' doesn't return 'F' for the first '1' and first '3' in 'x'. I am wondering if there is a function that can return an indicator for any element whether it appears in a vector twice or more. Regards, Peng

Hi, I don't quite understand what are the return values of aov. I know that it has 'coefficients'. But I need to know what all the other return values are. Can somebody let me know how to figure them? Value: An object of class 'c("aov", "lm")' or for multiple responses of class 'c("maov", "aov", "mlm",

Hi, I am wonder if there is a function similar 'apply' but it could accept multiple arguments? For example, I have the following matrix. x=matrix(1:6,nr=2) y=matrix(1:6,nr=2) I want to find a function that can be used to compute the linear regression for each pair of rows in the two matrices? multiple_apply(x,y,1,function(u,v){lm(u ~ v)} That is, I wound like something like the above

I did a sanity check and run some of the bitcode I complied with gllvm and it seems to work fine under lli. The only issues is to make sure you load all the (external) libraries the bitcode needs. I highly suggest you run a debug version of lli under a debugger and see what exactly happens. On Mon, Jan 28, 2019 at 12:45 PM Peng Yu <pengyu.ut at gmail.com> wrote: > It seems that it does