Displaying 20 results from an estimated 110 matches similar to: "package quantreg behaviour in weights in function rq,"
2012 Aug 22
1
Error in if (n > 0)
I've searched the Web with Google and do not find what might cause this
particular error from an invocation of cenboxplot:
cenboxplot(cu.t$quant, cu.t$ceneq1, cu.t$era, range=1.5, main='Total
Recoverable Copper', ylab='Concentration (mg/L)', xlab='Time Period')
Error in if (n > 0) (1L:n - a)/(n + 1 - 2 * a) else numeric() :
argument is of length zero
I do
2006 Jun 13
2
Garch Warning
Dear all R-users,
I wanted to fit a Garch(1,1) model to a dataset by:
>garch1 = garch(na.omit(dat))
But I got a warning message while executing, which is:
>Warning message:
>NaNs produced in: sqrt(pred$e)
The garch parameters that I got are:
> garch1
Call:
garch(x = na.omit(dat))
Coefficient(s):
a0 a1 b1
1.212e-04 1.001e+00 1.111e-14
Can any one
2011 Apr 18
1
time dependent hazard ratios
Hi, I am new to time-dependent Cox model to estimate time dependent hazard
ratios. Let me use aml dataset from survival package:
> aml3<-survSplit(aml2,cut=c(5,10,20),end="time",start="start",
event="status",episode="i")
If I want to esimate hazard ratio for each of the time intervals 0-5, 5-10,
10-20 and >=20, would the following calculate
2009 Mar 17
2
bigglm() results different from glm()
Dear all,
I am using the bigglm package to fit a few GLM's to a large dataset (3
million rows, 6 columns). While trying to fit a Poisson GLM I noticed
that the coefficient estimates were very different from what I obtained
when estimating the model on a smaller dataset using glm(), I wrote a
very basic toy example to compare the results of bigglm() against a
glm() call. Consider the
2006 Mar 08
1
RES: survival
Dear Thomas,
The head of my dataset
> head(wsuv)
parcel sp time censo treatment
species
1 S8 Poecilanthe effusa ( Hub. ) Ducke. 1 1 1 1
2 S8 Poecilanthe effusa ( Hub. ) Ducke. 1 1 1 1
3 S8 Poecilanthe effusa ( Hub. ) Ducke. 1 1 1 1
4 S8 Poecilanthe effusa ( Hub. ) Ducke. 1 1 1
2011 Mar 03
1
Applying function to multiple data
Dear R helpers,
I know R language at a preliminary level. This is my first post to this R
forum. I have recently learned the use of function and have been successful
in writing few on my own. However I am not able to figure out how to apply
the function to multiple sets of data.
# MY QUERY
Suppose I am having following data.frame
df = data.frame(k = c(1:8), ratings = c("A",
2009 Jul 03
2
bigglm() results different from glm()
Hi Sir,
Thanks for making package available to us. I am facing few problems if
you can give some hints:
Problem-1:
The model summary and residual deviance matched (in the mail below) but
I didn't understand why AIC is still different.
> AIC(m1)
[1] 532965
> AIC(m1big_longer)
[1] 101442.9
Problem-2:
chunksize argument is there in bigglm but not in biglm, consequently,
2013 Jan 14
1
ginv / LAPACK-SVD causes R to segfault on a large matrix.
Dear R-help list members,
I am hoping to get you help in reproducing a problem I am having That is
only reproducible on a large-memory machine. Whenever I run the following
lines, get a segfault listed below:
*** caught segfault ***
address 0x7f092cc46e40, cause 'invalid permissions'
Traceback:
1: La.svd(x, nu, nv)
2: svd(X)
3: ginv(bigmatrix)
Here is the code that I run:
2010 Jun 24
1
help in SVM
HI, GUYS,
I used the following codes to run SVM and get prediction on new data set hh.
dim(all_h)
[1] 2034 24
dim(hh) # it contains all the variables besides the variables in all_h
data set.
[1] 640 415
require(e1071)
svm.tune<-tune(svm, as.factor(out) ~ ., data=all_h,
ranges=list(gamma=2^(-5:5), cost=2^(-5:5)))# find the best parameters.
bestg<-svm.tune$best.parameters[[1]]
2010 Jun 08
1
GEE: estimate of predictor with high time dependency
Hi,
I'm analyzing my data using GEE, which looks like below:
> interact <- geeglm(L ~ O + A + O:A,
+ data = data1, id = id,
+ family = binomial, corstr = "ar1")
> summary(interact)
Call:
geeglm(formula = lateral ~ ontask + attachment + ontask:attachment,
family = binomial, data = firstgroupnowalking, id = id, corstr = "ar1")
Coefficients:
2009 Nov 11
2
Error in lm() function
Hi all,
I wanted to have a seasonality study like whether a particular month has
significant effect as compared to others. Here is my data :
0.10499 0 0 1 0 0 0 0 0 0 0 0
0.00259 0 0 0 1 0 0 0 0 0 0 0
-0.06015 0 0 0 0 1 0 0 0 0 0 0
0.10721 0 0 0 0 0 1 0 0 0 0 0
0.03597 0 0 0 0 0 0 1 0 0 0 0
0.10584 0 0 0 0 0 0 0 1 0 0 0
0.02063 0 0 0 0 0 0 0 0 1 0 0
-0.03509 0 0 0 0 0 0 0 0 0 1 0
-0.03485 0 0 0
2011 Apr 29
1
question of VECM restricted regression
Dear Colleague
I am trying to figure out how to use R to do OLS restricted VECM regression. However, there are some notation I cannot understand.
Please tell me what is 'ect', 'sd' and 'LRM.dl1 in the following practice:
#OLS retricted VECM regression
data(denmark)
sjd <- denmark[, c("LRM", "LRY", "IBO", "IDE")]
sjd.vecm<-
2009 Oct 26
1
explalinig the output of my linear model analysis
Hi,
I am new in statistics and i manage to make the linear model analysis but i
have some difficulties in explaining the results. Can someone help me
explalinig the output of my linear model analysis ? My data are with 2
variables habitat (e,s) and treatment (a,c,p) with multiple trials within.
Thank you in advance
Call:
lm(formula = a$wild ~ a$habitat/a$treatment/a$trial)
Residuals:
Min
2000 Jun 16
0
glm under R versions 1.0.1 and 1.1.0
I have fitted a number of models with receipt of social assictance
(toim1) during a year (values 0 or 1) with a number of covariates.
The data include sampling weights which I use in the models. Using the
exact same data, glm() under 1.0.1 and 1.1.0 give different results in
many (but not all) of the models. I have re-installed 1.0.1 to check
this and I found now mention in the NEWS file that
2003 Nov 19
2
Difference in ANOVA results - R vs. JMP/Minitab
Hi,
I ran a small data set from a factorial experiment through R, Minitab
and JMP... the result from R is significantly different from what
Minitab or JMP give... The data set is at the following link:
http://www.personal.psu.edu/nug107/Uploads/2x3_16repsANOVA.txt
The first 5 columns are the factors and the next three are responses.
In particular, for the response beta11MSE, two of the
2009 Aug 11
1
Selecting/Accessing the last vector in a list of a list of data.frames
Hello Again R Folks:
I?m trying to clean up some code. Suppose I have an object like this:
> str(test)
List of 2
$ G:List of 2
..$ cls:'data.frame': 101 obs. of 2 variables:
.. ..$ V1: num [1:101] -0.0019 -0.0019 -0.00189 -0.00188 -0.00186 ...
.. ..$ V2: num [1:101] 0.000206 0.000247 0.000288 0.000329 0.000371 ...
..$ rob:'data.frame': 101 obs. of 2
2005 Nov 28
3
glm: quasi models with logit link function and binary data
# Hello R Users,
#
# I would like to fit a glm model with quasi family and
# logistical link function, but this does not seam to work
# with binary data.
#
# Please don't suggest to use the quasibinomial family. This
# works out, but when applied to the true data, the
# variance function does not seams to be
# appropriate.
#
# I couldn't see in the
# theory why this does not work.
# Is
2006 Aug 12
6
params not getting POSTed
I have a situation where no params are being sent when the form is
submitted.
After the rendering this is the html that I get...
<form action="/stats/new" method="post">
Height: <input id="stat_height_ft" name="stat[height_ft]" size="5"
type="text" />ft </p>
Weight: <input id="stat_weight_lbs"
2008 Aug 19
0
R-code: for those who like a challenge; HELP
I'll try to be more clear, but will have to give much more info. Here we go....
As part of my Masters in Public Health I writing a dissertation reviewing the mortality trend of internally displaced persons in camp settings in Sub Saharan Africa. I have 50 surveys with
- crude mortality rate (cmr), CMR lower confidence interval(cmrlci), CMR upper confidence interval(cmruci),
- recall period
2004 Sep 16
1
cor() fails with big dataframe
Hello,
I have a big dataframe with *NO* na's (9 columns, 293380 rows).
# doing
memory.limit(size = 1000000000)
cor(x)
#gives
Error in cor(x) : missing observations in cov/cor
In addition: Warning message:
NAs introduced by coercion
#I found the obvious workaround:
COR <- matrix(rep(0, 81),9,9)
for (i in 1:9) for (j in 1:9) {if (i>j) COR[i,j] <- cor (x[,i],x[,j])}
#which works fine,