similar to: using chron vector with boxplot

Hi, I've been using the chron package to convert excel time into month/day/year and h:m:s formats, specifically for use as axis labels. I've come across something I don't quite understand. ### Here are some excel times: dat = c(39083, 39083.00694, 39083.01389, 39083.02083, 39083.02778, 39083.03472, 39083.04167, 39083.04861, 39083.05556, 39083.0625 ) ### I create

Hi, I have a list made up of character strings with each item a different length (each item is between 1and 6 strings long). Is there a way to convert a "ragged" list to a matrix such that each item is its own row? Here is a simple example: a=list(); a[[1]] = c("a", "b", "c"); a[[2]] = c("d", "e"); a[[3]] = c("f",

I have a matrix containing means and CIs (lower and upper in two columns, so three columns for every data point) for several points. I have to build a graph of these means accompained by the CIs (as wiskers). No problems with making the graph of means, but I don't know how to introduce CIs. Can anybody advise? -- View this message in context:

Hello, I have a dataset which consists of 9 columns (variables) and 35 rows (observations). I am doing a simple linear regression of one variable on the other. There are some observations that are outliers and I would like to remove them based on another variable (it's a unique, numeric variable). How do you tell R to remove multiple rows (observations) based on a variable value?

Hi, I'm fairly new to R, so hopefully this is an easy question... On a plot, I would like to have the y label read: "Response(phi)" with phi = the greek character. From old posts I've found this: title(ylab=expression(paste("Response (", phi, ")"))) This displays nicely, but in the default font. I would like to use font=6 (which is the font of the other

Hi all, hope you having a nice day, I ahve this weird results with identical (probably I am not understanding correctly what it does ...) I have these two data frames and I issue : > identical(temp, temp1) [1] FALSE However, these data frames are Nx2 and when I issue: > identical(temp[,2], temp1[,2]) [1] TRUE > identical(temp[,1], temp1[,1]) [1] TRUE and the results from str >

Hi, I've used Samba several years without any problems. Last week I added a new disk to my system, and Samba started to behave very strange. It's slow in terms of establish a connection and time to list directories. I've tried to resolve the problem without success. No other daemon has problems, both ftp and http works fine as well as internal communication. Below I've attached

Hi all! I just finished an install of icecast/iceS but I'm having problems. I followed the documentation provided here: http://melmoth.dyndns.org/stream/doc/ to the letter and this is the problem I'm having: Everything seems to function (icecast runs, iceS runs) and it generates messages such as: [root@icecast stream]# bin/ices conf/ices-playlist.xml [2003-06-04 06:43:17] INFO

g'day R guru's. Could someone help me out with 2 'chron' questions please (I've been using the 'date' package but I need time handling)? The doco doesn't cover everything and I'm too green to understand all the code. When my chron object is printed using 'print' the output is not in the format requested by the default attributes. What am I doing

I am running a simple R program, its skeleton is enclosed below. The program reads about 80 files with about 5000 lines with coloumns of data. After an unpredictable and variable number of loops for run to run, it exits with segmentation fault or alternatively with the error Error in names<-.default(*tmp*, value = fnames) : Unimplemented feature in duplicate Removing the call to

Hi all, I'm just getting started in R so bear with my newbness. I am trying to create a very simple histogram of logins by time, with data coming in from a MYSQL query. the raw data looks like this: "id" "user_id" "experience_given" "created_at" "ip_aton" "1" XXXXXXX 2445626 0 "2010-01-21 00:00:01" 1123632036 "2"

dear r folks i am a bit puzzled about how to use chron as an index xts and why it differs from zoo. in this example, why can i index zoo but not xts x<-1:23 time.of.day <- times(paste(x,":0:0",sep=""),format="h:m:s") day <- dates("4/8/90") period <- chron(dates=day,times=time.of.day) xts(1:23,period) zoo(1:23,period) i suspect it might be to

Hello all, I don' like to have ( ) around my datetime, when send the csv file to somebody. How to remove it? >library(chron) >mydate <- c("2009-05-03","2009-06-07") >mytime <- c("10:30:00","10:20:00") >mydatetime <- chron(dates=mydate,times=mytime,format=c("y-m-d","h:m:s")) >write.csv(mydatetime)  

Another beginner's question. Still trying trying to read and and plot a simple tds-value vs time. input file: onedat date time tds 1997-12-29 13:35:00 411 > onedat<-read.table("onedat",header=T) attach(onedat) > x<-chron(dates=as.vector(date),times=as.vector(time), format=c("y-md","h:m:s")) > x [1] (97-12-29 13:35:00) See my problem? Chron

I have installed the chron library, but it does not seem to work: > chron("04/06/98") Error in .C(NAME = "to_lower", strings = as.character(str), nstrings = as.integer(n)) : C/Fortran function not in load table > chron(17894) Error in .C(NAME = "to_lower", strings = as.character(str), nstrings = as.integer(n)) : C/Fortran function not in load table > I am

I'm not too familiar with chron, but I don't think it should drop the month and day in the second example following example: > chron(20000, format="y/m/d") [1] 124/10/04 > chron(20000, format="yy/m/d") [1] 2024 Paul Gilbert -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-devel mailing list -- Read

Times series of rain and discharge in hydrologic - stations has above 95 years of daily records. In the temporal series over "serie" dataframe, using chron's object: > library(chron) # load chron library > length(serie$data) [1] 27182 > serie$data[length(serie$data)] [1] (85-12-31 00:00:00) # 1985-dez-31 00:00:00hs >

Due to the following lines in parse.format: else if (nf == 3) { sep <- "" fmt <- substring(format, first = 1:3, last = 1:3) } If a format code has 3 characters, it will not use a separator: > library(chron) > mytime = times('7:15:00') > format(mytime,'h:m') [1] "0715" - Phil Spector

Dear, According to the documentation, the parameters given in "dates" are passed to the function "chron". When trying this out, it turns out that this apparently doesn't happen, eg: > dates("20100101",format="Ymd",out.format="day mon year") [1] 01/01/10 > chron("20100101",format="Ymd",out.format="day mon

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