similar to: problem with "ls" command

Dear all, I have data in the following format : X-axis Y-axis <0 10% 0-20 20% 20-40 30% 40-60 40% ......... and so on. I want to plot a bar graph of the above. Also I would want to add a trendline passing either through the center of each bar or through the top. Is it also possible to get the r-squared and p-values for

Dear all, I have recently installed R on a Red Hat Enterprise Linux (RHEL5) system. But I am unable to load R and it is giving the following error : */usr/local/lib/R/bin/exec/R: error while loading shared libraries: libreadline.so.5: cannot open shared object file: No such file or directory* I have checked for the presence of the above mention library and found that the library

Hi all, I am trying to construct a frequency distribution graph i.e. suppose there is a variable *"k"* and it takes a range of values. What I want to do is to plot *"P(k)" *(probability/frequency of finding a specific value of *"k"*) vs *"k"*.I would like to get a smooth curve between "P(k) vs k". I have already tried

Dear all, I have this directory structure : Dir1 Dir2 Dir3 Dir4 ......................... A.xml D.xml G.xml B.xml E.xml H.xml C.xml F.xml I.xml Within each of these directories (Dir1, Dir2 etc) there are a num of xml files (A.xml, B.xml etc). What I want to do is to enter into the first directory read all the xml files do certain operations

Hi all, Presently I have R-2.6 version installed on my system. Because of this I am unable to install certain packages.Will an "updatepackages()" command help or would I have to uninstall the older version of R and then install the newer versions ? Can anyone help me out ? Thanks in advance. Anupam Sinha [[alternative HTML version deleted]]

Dear R-users, I am using R(a package igraph) to calculate certain topological features of networks. When I try to draw a plot between these features I get an error. Following is the code I am using : *> plot(met_eco_deg,met_eco_bet) > lmout<-lm(met_eco_bet ~ met_eco_deg) > abline(lmout) Error in int_abline(a = a, b = b, h = h, v = v, untf = untf, ...) : plot.new

Hi all, I am new to R. How does one go about fitting a trend-line to a scatter plot? Any help is appreciated. Thanks and regards, Anupam [[alternative HTML version deleted]]

Dear all , I am trying to install a package by name 'netmodels' keep on getting the following error : > install.packages("netmodels") Warning in install.packages("netmodels") : argument 'lib' is missing: using '/usr/lib64/R/library' also installing the dependency ‘VGAM’ trying URL

Greetings all, I would like to append a 4 digit number suffix to the names of my files for later use. What I am using now only produces 1 or 2 or 3 or 4 digits. ############ for (i in 1:1000) { temp <- (kegg [i,]) temp <- merge (temp, subrichcdt, by="gene") file.name <- paste ("kegg.subrichcdt.", i, ".txt", sep="")

i don't know perl,but on server site,they give soap:lite using perl , go to--->http://www.kegg.jp/kegg/soap/doc/keggapi_manual.html i want to download data from kegg server ,using R only, how to proceed? & what is mean by SOAP client driver ? also go to http://soap.genome.jp/KEGG.wsdl -- View this message in context:

My conception of how NAMESPACE and methods in R-2.7.0 resolved a generic 'func' to a func-method was to search as follows: In 2.7.0: func --> NAMESPACE, including Imports: (and other details) --> .GlobalEnv, and eventually Depends: since these are on search() In R-devel it seems like func --> NAMESPACE, including Imports: (and other details) --> ?? but not

As far as I know, the following should work. Can anybody tell me if/where I am going wrong? > packageDescription("KEGG", field="Version") [1] "1.6.4" > require(KEGG, version="1.6.4") Loading required package: KEGG [1] FALSE Warning message: There is no package called 'KEGG', version 1.6.4 in: library(package, character.only = TRUE, logical

Hi, I'm using GAGE/pathview to analyze my RNA-seq and phospho-protein data. The following error occurs after this command line below: >pv.out.list <- sapply(path.ids2[1:3], function(pid) pathview( gene.data = cnts.d, pathway.id = pid, gene.idtype="SYMBOL",kegg.native = F, same.layer = T, species = "hsa", kegg.dir = "test", out.suffix = "up"))

Thanks, John. However, loess.smooth() is producing a very different curve compared to the one that results from applying predict() on a loess(). I am guessing they are using different defaults. Correct? On Thu, 23 Mar 2023 at 20:20, John Fox <jfox at mcmaster.ca> wrote: > Dear Anupam Tyagi, > > You didn't include your data, so it's not possible to see exactly what >

Thanks! You are correct, the graphs look very similar, except ggplot is scaling the text font to make it more readable. Is there a way to scale down the x-axis labels, so they are readable? On Fri, 7 Jul 2023 at 12:02, PIKAL Petr <petr.pikal at precheza.cz> wrote: > Hallo Anupam > > I do not see much difference in ggplot or lattice, they seems to me > provide almost identical

Hallo Anupam I do not see much difference in ggplot or lattice, they seems to me provide almost identical results when removing theme part from ggplot. library(ggplot2) library(lattice) ggplot(TrialData4, aes(x=Income, y=Percent, group=Measure)) + geom_point() + geom_line() + facet_wrap(~Measure) xyplot(Percent ~ Income | Measure, TrialData4, type = "o", pch = 16, as.table =

In the browser the link downloads immediately, in less than a second. I let the command run in R for five minutes, using R Studio. Nothing happened. On Fri, 9 Aug 2024 at 17:54, Ivan Krylov <ikrylov at disroot.org> wrote: > ? Thu, 8 Aug 2024 12:43:23 +0530 > Anupam Tyagi <anuptyagi at gmail.com> ?????: > > > In open.connection(con, "rb") : > > URL

Okay. Here is a modification that does four single line plots. at_df<-read.table(text= "Income MF MF_None MF_Equity MF_Debt MF_Hybrid Bank_None Bank_Current Bank_Savings Bank_NA $10 1 3.05 29.76 31.18 36.0 46.54 24.75 25.4 3.307 $25 2 2.29 28.79 32.64 36.27 54.01 24.4 18.7 2.891 $40 3 2.24 29.51 34.31 33.94 59.1 25.0 29 13.4 $75 4 1.71 28.90 35.65 33.74 62.17 24.61 11.48 1.746

On Thu, 6 Jul 2023 at 15:21, Anupam Tyagi <anuptyagi at gmail.com> wrote: > > Btw, I think "lattice" graphics will provide a better solution than > "ggplot", because it puts appropriate (space saving) markers on the axes > and does axes labels well. However, I cannot figure out how to do it in > "lattice". You will need to convert Income to a

Btw, I think "lattice" graphics will provide a better solution than "ggplot", because it puts appropriate (space saving) markers on the axes and does axes labels well. However, I cannot figure out how to do it in "lattice". On Thu, 6 Jul 2023 at 15:11, Anupam Tyagi <anuptyagi at gmail.com> wrote: > Hi John: > > Thanks! Below is the data using your