similar to: by-group processing

Hi, is there a simpler way to count the number of elements in a vector that are not NA than this: countN <- function (v) { return (Reduce(function (x, y) x + y, ifelse(is.na(v), 0, 1))) } ? - Godmar

Dear all, I'm a relative new user of R and I have a problem with merging a collection of matrices. All matrices in this collection have the same dimension (532 rows and 532 columns), but can differ in the row and columns names. I'd like to merge these matrices in such a way that the resulting matrix only contains unique row- and column-names and that in case of a match between the row or

Dear R People: I am looking at the ctime attribute of two different files. It contains the year, month, day, time of creation and time zone. Is there a way to determine the difference between the ctimes of two files, please? I looked in the chron package and nothing seemed to work. Thanks in advance, Sincerely, Erin -- Erin Hodgess Associate Professor Department of Computer and

Simple question: Why doesn't the following work? Or what 'R' rule am I missing? tclass <- "Testing 1 2 3" if(tclass == "Testing 1 2 3") { cat("Testing", tclass, "\n") } else { cat(tclass, "\n") } I get an error 'else' is unexpected. Thank you. Kevin

Dear R People: I have several vectors, sa1, sa2,...sa27 of varying lengths. I want to produce one vector xener[1:27] which has the minimum of each sa[i]. I'm trying to set up a loop and use the assign statement, but here are my results: > for(i in 1:27) { + xener[i] <- min(assign(paste("sa",i,sep=""))) + } Error in assign(paste("sa", i, sep =

I've created a short program to print a table of learning curve factors. However, I cannot figure out how to format the table to: 1) Get rid of the [1]s in the first column and replace it with the values of N. 2) Line up the first row with the factors (decimal fractions). Thanks for any help. The complete program and output is as follows: > Lc<-seq(0.70,0.95,0.05) #Specify learning

I'm looking for something along the lines of which ( table ( x ) == max ( table ( x ) ) ) to find the most common level of one factor by several other factors. For instance, I've got > X <- data.frame ( + x = factor ( sample ( c ( "A" , "B" , "C" , "D" ) , 20 , r = T ) ) + , z1 = factor ( sample ( c ( "Before" ,

Dear all, I have about 30,000 matrix (512x512), with values from 1 to N. Each value on a matrix represent a habitat patch on my matrix (i.e. my landscape). Non-habitat are stored as ZERO. No I need to change each 1-to-N values for the same random number. Just supose my matrix is: mymat<-matrix(c(1,1,1,0,0,0,0,0,0,0,0, 0,0,0,0,2,2,2,0,0,0,0, 0,0,0,0,2,2,2,0,0,0,0, 3,3,0,0,0,0,0,0,0,4,4,

I'm trying to install the Hmisc package, however it doesn't appear in the list after "utils:::menuInstallPkgs()". Any help? -- David

Hi I'm new to R and would like to implement a SAS-like macro variable in R. What I'd like to do is take the simple R code below and change the "=TEF" to different letters to refer to different companies' data for download. # DOWNLOADS FILES FROM YAHOO INTERNET

I have two dataframes, the first column of each dataframe is a unique id number (the rest of the columns are data variables). I would like to figure out how many times each id number appears in each dataframe. So far I can use: length( match (dataframeA$unique.id[1], dataframeB$unique.id) ) but this only works on each row of dataframe A one-at-a-time. I would like to do this for all of

Is there any way to have Sexpr span multiple lines? -- David ? ----------------------------------------------------- David Huffer, Ph.D. Senior Statistician CSOSA/Washington, DC david.huffer at csosa.gov -----------------------------------------------------

Sometimes I write code like this: > qf.a <- subset(qf, pubid %in% c(104, 106, 107, 108)) > qf.b <- subset(qf, !pubid %in% c(104, 106, 107, 108)) and I get a little worried that maybe I've remembered the precedence rules wrong, so I change it to > qf.a <- subset(qf, pubid %in% c(104, 106, 107, 108)) > qf.b <- subset(qf, !(pubid %in% c(104, 106, 107, 108))) and pretty

For scalix on Centos the Scalix forum provides instructions for convincing Scalix that Centos is Redhat: http://www.scalix.com/community/viewtopic.php?t=516&highlight=centos I am up to the point of getting Java JDK1.4.2 installed. I did a: yum list|grep "java" and got: gcc-java.i386 3.4.4-2 installed java-1.4.2-gcj-compat.noarch

Hi. CENTOS 7.6.1810, fresh install - use this as a base to create/upgrade new/old machines. I was trying to setup two disks as a RAID1 array, using these lines mdadm --create --verbose /dev/md0 --level=0 --raid-devices=2 /dev/sdb1 /dev/sdc1 mdadm --create --verbose /dev/md1 --level=0 --raid-devices=2 /dev/sdb2 /dev/sdc2 mdadm --create --verbose /dev/md2 --level=0 --raid-devices=2

Dear R users, I am trying to write myself a loop in order to produce a set of 20 length frequency plots each pertaining to a factor level. I would like each of these plots to be available on the same figure, so I have used par(mfrow = c(4, 5)). However, when I run my loop below, it produces 20 plots for each factor level and only displays the last factor levels LF plots. I'm fairly new to

Dear R helpers, I think that this may be a bit of a math question as the more I consider it, the harder it seems. I am trying to come up with a way to work out the minimum distance between line segments. For instance, consider 20 random line segments: x1 <- runif(20) y1 <- runif(20) x2 <- runif(20) y2 <- runif(20) plot(x1, y1, type = "n") segments(x1, y1, x2, y2)

Hello, I use rsync to copy personal data to various different machines for backup purposes and enjoy the robustness of the copy process. I was wondering if it was possible to add the option for rsync to copy the creation date and time as well as the modification time. This is really just a request for 'completeness'. When copying personal files it's useful to know when the orginal

So SAMBA no longer supports print driver downloads. That is about the only conclusion that I can come to at this point. I've not been able to get Windows printer driver downloads to work right since Samba 2.2.2. No one but printer admins displays the correct settings for printers, everyone else gets the original printer defaults that they cannot change. I've tried this with

Dear R users, I have two coloumns of data, say x and y, referring to a list of points in 2D space. I am trying to develop a code that will give me the distances (using Pythagoras) between consecutive points (xi,yi) and (xi+1,yi+1). So far I have come up with the following: for (i in 1:length(x)) d<-sqrt((x[i+1]-x[i])^2+(y[i+1]-y[i])^2) For example, if I use the two points (note, I have