similar to: matrix merge problem

Dear List, I would like to create several graphs of similar data. I have x and y values for several different individuals (in this case fish). I would like to plot the x and y values for each fish separately. I can do it using a for loop, but I think I should be using "apply". Please let me know what I am doing wrong, or if there is a "better" way to do this. What I have

I have read a frequency table in to R called "temp." I now want to create a histogram table from it, but I obviously first have to expand the data - to the sample size of 100. I want to use the command rep(), but I'm not sure how to go about it..I tried using the code: temp1<-rep(temp$Chest,100) hist(temp1) But this creates a v. odd histogram so I know it must be wrong!

Dear R-users, I have very recently started learning about object-oriented programming in R. I am far from being an expert in programming, although I do have an elementary C++ background. Please take a look at these lines of code. > some.data = data.frame(V1 = 1:5, V2 = 6:10) ; > p.plot = ggplot(data=some.data,aes(x=V1, y=V2)) ; > class(p.plot) ; > [1] "ggplot" My

Dear R-specialists, I am trying to create a Makefile that will first convert all my .Rnw files into .tex files and then, that will run the LaTeX compiler to produce a pdf document. This issue has been discussed before. Hence, I've basically adapted a Makefile I found at http://n4.nabble.com/R-Sweave-R-and-complex-latex-projects-td810020.html#a810023 to make it compatible with a Windows

Dear R-users, I am preparing graphs for an upcoming article using the different functions of the ggplot2 package and I've been having problems with the legend background. It doesn't seem to scale when the text size is increased. Here's the mandatory reproducible example: library(ggplot2) repFrame <- data.frame(A= 1:10, B= rnorm(1:10), groupNum = rep(c("First group",

Dear R-users, I recently began using the ggplot2 package and I am still in the process of getting used to it. My goal would be to plot on the same grid a number of curves derived from two distinct datasets. The first dataset (called molten.data) looks like this : Column names : Perc, Week, Weight P10 21 333.3554 P90 21 486.0480 P10 22 452.6347 P90 22 563.8263 P10 23 575.0960 P90

Dear R-users, I would have another question about the ggplot() function in the ggplot2 package. All the examples I've read so far in the documentation make use of a single neatly formatted data.frame. However, sometimes, one may be interested in plotting on the same grid information or objects derived from two totally different datasets and customize both displays. I still cannot tell how

I have two matrixes, red: a 123 c 200 d 400 e 650 g 127 f 100 and blue: a 10 b 20 c 30 d 40 e 50 f 60 g 70 is there any easy way to get the next matrix: a 10 123 b 20 0 c 30 200 d 40 400 e 50 650 f 60 100 g 70 127 i.e. to add in the third column of blue the [,2] values of red corresponding to the file with same [x,1] value of blue, adding a cero in the case that there is no [x,1]

Dear Contributors: I have the next matrix: "X" "Y" "Z" 1 2 526 2 5 723 3 10 110 4 7 1110 5 9 34 6 8 778 7 1 614 8 4 876 9 6 249 10 3 14 I want to order the matrix from bigest Z (1110) to lower Z (14). Then I want to asign a color scale vector from blue ( bigest Z) to orange

hi Juan, It is not so elegant, but work fine. I know that our colleagues can do it on a simple line. z<-c(526,723,110,1110,34,778,614,249,14) v1<-NULL v2<-NULL for (i in 1:(length(z)-1)) { for (j in i:length(z)) { v1<-rbind(v1,z[i]) v2<-rbind(v2,z[j]) } } df<-data.frame(cbind(v1=v1,v2=v2)) names(df)<-c("v1","v2") df$ratio<-df$v1/df$v2 Kind regards,

Hi all, I want to make a vector with the third column of a matrix, but only for the 2+3n rows of the matrix, with n being an entire number from 0 to a million. How can I do that in an easy way? Thanks in advance, Juan Pablo [[alternative HTML version deleted]]

Hi all, I have the next matrix: a b c 1 2 23 2 3 42 3 0 54 4 5 23 5 0 22 6 7 21 7 1 20 8 9 19 I want to filter the rows with the values of b higher than 1 in a way that leaves me the next matrix: a b c 1 2 23 2 3 42 4

Hi all, Is there an easy way to generate an object wich will be the same matrix, but ordered by de cfp value? The data frame consists of numeric columns: "Block" "X" "Y" "cfp" "yfp" "ID" 0 524 244 213.41795 7.18482109 1 0 556 270 65.383904 9.568372661 2 0 528 316 40.789474

Dear gentlemen, Can you explain me why the following happens (any OS I think, and even on 64 bits)? > sum(1000:1205)^2 [1] 51581223225 > sum(1000:1205)*sum(1000:1205) [1] NA Warning message: In sum(1000:1205) * sum(1000:1205) : NAs produced by integer overflow Best, Pierre -- Pierre Lafaye de Micheaux Adresse courrier: D?partement de Math?matiques et Statistique Universit? de

Hi, I installed package 'lars' earlier tonight and did not get any sort of error message. ### ** building package indices ... ** testing if installed package can be loaded Loaded lars 0.9-8 * DONE (lars) ### However, when I try to load it, I get ### > library(lars, lib.loc = "~/R/x86_64-redhat-linux-gnu-library/2.11") Error : .onLoad failed in loadNamespace() for

Dear R-users, I've recently switched to Ubuntu and I've decided to use Kate to edit my R code. I really like how Kate allows one to simply pipe their code to the terminal. However, I would find it even better if I could actually get the Kate console to display error messages (or any console outputs in fact) in red and my input in a different color. The instance of xterm that Ubuntu

Dear Contributors: I have two vectors x and z, and I want to display the histograms of both vectors in the same graph, x in red bars, z in blue bars. If you have any clue on how to do that, I will be very glad to hear it!!!!!! Thanks in advance again, Juan Pablo Fededa [[alternative HTML version deleted]]

Dear Contributors: I have the next vector: "Z" 526 723 110 1110 34 778 614 249 14 I want to generate a vector containing the ratios of all the values versus all the values of the z vector. I mean a vector containing the values of 526/723, 526/110, and so on, 723/723, 723/110, and so on, and so on. Is this doable in a simple way?? Thanks in advance again, Juan Pablo Fededa

Hello How to compare  two statistical histograms? How i can know if these histograms are equivalent or not??   Regards [[alternative HTML version deleted]]

Dear R users, I am having trouble devising an efficient way to run a loess() function on all columns of a data.frame (with the x factor remaining the same for all columns) and I was hoping that someone here could help me fix my code so that I won't have to resort to using a for loop. (You'll find the upcoming lines of code in a single block near the end of the message.) Here's a