similar to: Simple Plot with Grid's Viewport

I have a data that looks like this: http://dpaste.com/88561/plain/ And I intend to create multiple density curve into one plot, where each curve correspond to the unique ID. I tried to use "sm" package, with this code, but without success. __BEGIN__ library(sm) dat <- read.table("mydat.txt"); plotfn <- ("~/Desktop/flowgram_superimposed.pdf"); pdf(plotfn);

Dear all, I have a simple plot using "gridBase" like this. The problem occurs whenever I execute this code there is always a blank page created before the actual plot. How can we disable that blank page? I am using: R version 2.7.2 (2008-08-25) and gridBase version: 0.4-3 __ BEGIN__ library(grid) library(gridBase) opar <- par(no.readonly=TRUE) par(opar) grid.newpage()

Hello all, I'm trying to write a function that produces a main plotting region with several square plots along the right side. Ideally the size of right side plots will scale only with the height of the entire plot, yet never overlap with another secondary plot. The following two snippets get close, however, as I resize the plot horizontally the right side plots (green squares) get smaller

Dear all, For example I want to process set of files. Typically Perl's idiom would be: __BEGIN__ @files = glob("/mydir/*.txt"); foreach my $file (@files) { # process the file } __END__ What's the R's way to do that? - Gundala Viswanath Jakarta - Indonesia

Hi, With the following codes, I attempt to convert the data.frame into a matrix. However I notice that data.matrix function doesn't seem to work. __ BEGIN__ dat <- read.table("mydata", comment.char = "!" , na.strings = "null"); # Select n-genes by random sample # n = 1 nosamp <- 1 geneid <- sequence(nrow(dat)) geneid.samp <- sample(geneid,nosamp)

Hi all, I have the following named list: > print(y) $`200052_s_at` [1] -1066.975 -1063.893 -1062.815 -1062.121 -1059.004 $`200071_at` [1] -959.823 -953.980 -953.886 -948.781 -974.890 $`200084_at` [1] -1135.804 -1132.863 -1128.197 -1128.633 -1125.890 What I want to do is to iterate this name list and process its members. To do that I attempt the following code (but failed): __BEGIN__ ny

Hi, How can I partitioned an example vector like this > print(myvector) [1] 30.9 60.1 70.0 73.0 75.0 83.9 93.1 97.6 98.8 113.9 into the following pairwise partition: PAIR1 part1 = 30.9 part2 = 60.1 70.0 73.0 75.0 83.9 93.1 97.6 98.8 113.9 PAIR2 part1 = 30.9 60.1 part2 = 70.0 73.0 75.0 83.9 93.1 97.6 98.8 113.9 .... PAIR9 part1 = 30.9

Dear all, I found that printing with 'cat' is very slow. For example in my machine this snippet __BEGIN__ # I need to resolve to use this type of loop. # because using write(), I need to create a matrix which # consumes so much memory. Note that "foo, bar, qux" object # is already very large (>2Gb) for ( s in 1:length(x) ) {

I get the following error message followed by instability in R after the error message: Error: Cannot pop the top-level viewport (grid and graphics output mixed?) Have reduced something much more complex in my code to a simple test case. I run the following and then resize the window: X = seq (1,10) Y = X^2 opar <- par(no.readonly=TRUE, mar = c(2.5, 3.1, 1, 2)) grid.newpage()

Hi, Currently I have a density plot generated with this snippet. Is there a way I can add a line curve on top of it? I mean in one figure __BEGIN__ myhist <- hist(x col="blue", main = "Density Plot", xlab = "Exp Level", ) __END__ - Gundala Viswanath Jakarta - Indonesia

Dear grid-expeRts, The goal: I would like to construct a plot (matrix) with grid and gridBase, which consists of four "sub-plots". The sub-plots should have a square plotting region as one would force with par(pty="s") in base graphics. The problem: I don't get a square plotting region, not even by specifying pty="s" in par(). Indeed, if you display the grid

Hi all, I have the following data in which I want to parse and store them in a list __DATA__ > print(comp.ll) [1] "\tGene 11340 211952_at RANBP5 k= 1 LL= -970.692 " [2] "\tGene 11340 211952_at RANBP5 k= 2 LL= -965.35 " [3] "\tGene 11340 211952_at RANBP5 k= 3 LL= -963.669 " [4] "\tGene 12682 213301_x_at TRIM24 k= 1 LL= -948.527 "

Dear all, Does R has any function/package that can pack and unpack string into bit size? The reason I want to do this in R is that R has much more native statistical function than Perl. Yet the data I need to process is so large that it required me to compress it into smaller unit -> process it -> finally recover them back again into string with new information. In Perl the

Hi, Suppose I have the following data frame. __BEGIN__ > library(MASS) > data(crabs) > crab.pca <- prcomp(crabs[,4:8],retx=TRUE) > crab.pca$rotation PC1 PC2 PC3 PC4 PC5 FL 0.2889810 0.3232500 -0.5071698 0.7342907 0.1248816 RW 0.1972824 0.8647159 0.4141356 -0.1483092 -0.1408623 CL 0.5993986 -0.1982263 -0.1753299 -0.1435941 -0.7416656 CW

Hi all, I'm trying to generate a plot containing a scatterplot, with marginal densityplots for x and y. However, when I try to generate a vertical densityplot, I get the message "warning: can't clip to rotated viewport", and nothing shows up. I'm probably misunderstanding how viewports are meant to be used, so if someone could give me a hint, I'd be most grateful. my

Am just feeling my way into the grid library, and cannot figure out how to define the plot limits. 3/5 of the example polygons below plot in the default 0-1 range viewport. But when I try to redefine the viewport the polygons plot in the same places. I also get the same result without employing push/pop. (As you can see from the scale I'm trying to introduce, I want to plot map polygons.)

Hi, I have the following dataset (simplified for example). __DATA__ 300.35 200.25 104.30 22.00 31.12 89.99 444.50 22.10 43.00 22.10 200.55 66.77 Now from that I wish to do the following: 1. Compute variance of each row 2. Pick top-2 row with highest variance 3. Store those selected rows for further processing To achieve this, I tried to: a) read the table and compute variance for each row,

The following code, though not brilliant, works on an A4 page. It might look odd on other devices of a very different size. =============X8------- cut here ---------------------------- require(grid) wide <- 15 vps <- grid.layout(nrow = 3, ncol = 4, widths = unit(rep(1, 4), rep("null", 4)), heights = unit(c(99, 1, 99),

I am setting up base plots -- one in viewport A and and one in B. This part works fine. But if I go back to A after having done B and add horizontal lines it seems to not use the correct coordinates. How do I tell it to resume using A's coordinates? I am already using par(fig = gridFIG()) but it seems that that's not enough to reestablish them. What happens is that when I go back to

I am setting up base plots -- one in viewport A and and one in B. This part works fine. But if I go back to A after having done B and add horizontal lines it seems to not use the correct coordinates. How do I tell it to resume using A's coordinates? I am already using par(fig = gridFIG()) but it seems that that's not enough to reestablish them. What happens is that when I go back to