Displaying 20 results from an estimated 10000 matches similar to: "plot lines at 0,0 axis"
2009 May 15
2
Additional points to scatter plot show up at wrong place
Hi everyone,
I have a problem with adding points to scatter plots.
The plot is drawn with the scatterplot() function from the car library:
scatterplot(data[,2] ~ data[,1],
data=data,smooth=F,reg.line=F,xlim=c(0.5,1),ylim=c(0.5,1),ylab="ML",xlab="Freq",cex.lab=1.9,cex.axis=1.8)
after that, I draw one line with abline(0,1,col="gray20") which works
perfectly fine.
2002 Aug 26
1
(CAR) Scatterplot and problems (?) with abline
Network Blitz
I'm trying to generate a graph to summarize Interest Rate Parity. This
involves a scatterplot of x against y where the x and y limits are set
so to center the graph on 0,0 and then adding each axis line and a 45
degree line. Using CAR's scatterplot (sample code below) everything
except the axes plot fine:
scatterplot( Interest.Rate.Dif ~ ForPrm| profit,
2006 Oct 12
3
Extrapolated regression lines
Dear list members,
When I create a simple scatterplot with a regression line (se below) the
line is automatically extrapolated outside the range of data points. Why
is this and how can I prevent R from extrapolating the regression line?
Thank you in advance,
Johan
model<-lm(Herb~Para)
plot(Para,Herb)
abline(model)
2012 May 19
3
Q - scatterplot, plot function & trellis linear regressions???
Hi R-listers,
Q1) What is the difference between the scatterplot and plot function?
Q2) I am able to make a graph with the scatterplot function:
scatterplot(DevelopIndex ~ Veg,
+ data = Turtle,
+ xlab = "Vegetation border (m)",
+ ylab = "Embryonic development index")
And have been successful. But I do not know if the lines are for:
2012 Aug 14
1
Graphing question(basic)
Hi,
plot(xc, yc, type="l", ylim=c(0,50), xlim=c(0,50), lwd=2, xlab="M",
ylab="seconds")
abline(a=-think, b=cpustime, lty="dashed", col="red")
abline( 2.2, 0, lty="dashed", col = "red")
This draws a response time curve an asymptote and a horizontal line. How
do I draw a line from the intersection of the asymptote and
2010 Dec 22
1
problems with abline in a time line scatterplot
Hello R-Users
i'm stuck with the following problem:
i want to add a trend line to a scatterplot. the x axis is a time line.
well it doesnt work, it seems that the function abline is not able
to handle the fact, that i used the column Date as a factor.
this is the script:
data<-read.table('DO_hapa_all_morning.txt',header=T,as.is=2)
attach(data)
names(data)
2010 Feb 23
2
scatterplots in car package
Hi, using scatterplot in 'car' package.
There are 4 plots to be pictured together (ignore data used):
library(car)
par(mfrow=c(3,1))
ts.plot(rnorm(100))
ts.plot(rnorm(100))
scatterplot(rnorm(100),rnorm(100),boxplot="",smooth=T) # scatter with
non-parametric fit
problem is that the last one comes 'always' separate.
Is there any way to solve it?? of course can use
2004 Jul 19
3
why won't rq draw lines?
I've been trying to draw quantile linear regression lines across a scatterplot of my data using
attach(forrq)
plot(PREGNANT,DAY8,xlab="pregnant EPDS",ylab="postnatal EPDS",cex=.5)
taus <- c(.05,.1,.25,.75,.9,.95)
xx <- seq(min(PREGNANT),max(PREGNANT),100)
for(tau in taus){
f <- coef(rq(DAY8~PREGNANT,tau=tau))
yy <-
2005 Jun 02
4
plot/lm/abline
Hi,
when I run
> plot.default(z1, z2, xlab = "x", ylab = "y", main = "xxxx", pch = "+")
> abline(lm(z1 ~ z2))
then the plot is plotted perfectly (scatterplot), however, the lm()
function doesnt appear on the plot. What could be wrong?
(Yesterday it worked perfectly, with the lm() line.)
Running R 2 on OS X.
Mathias Hunsk??r Furevik
Norway
2009 Mar 11
4
R-help: grep in for loop using index - doesn't work
Hi everyone
I am trying to use grep in a for loop to compare a string value. It works
if I use
the actual index value but when I use the for loop index, it doesn't work.
Any suggestions plz.
Here is the code:
data <- read.table(file="Sigmoid.csv", head=FALSE, sep=",");
c1 <- data$V1
c2 <- data$V2
c3 <- data$V3
c1data <- data.frame(c1);
c2data <-
2012 Dec 18
3
Regression line does not show on scatterplot
Hello,
I have done a scatterplot and now would like to add its regression line but it does not show.
Below, the code I have used.
lm3 <- lm(data$S_pH_KCl2.5_BCx~data$B_OleicoPF_BCx_per)
plot(data$S_pH_KCl2.5_BCx, data$B_OleicoPF_BCx_per)
abline(lm3)
I have been able to do the complete operation using the software STATISTICA but it would be great to do it with R.
If you require more details
2010 Oct 01
2
How to generate scatterplot - with a twist
Hi. I would like to make a scatterplot where all of the points are evenly
spaced from each other - however, they are all the same size and occupy the
entire graph. For example:
x = rep(c(1:10), 10)
y = rep(c(10:1), each = 10)
plot(x, y, pch = 0)
Gives me a scatter plot with 100 square points each evenly spaced between
each other. But these points don't fill up the entire space and if I try
2007 Jul 19
2
Trend lines on a scatterplot matrix
I'm using pairs() to generate a scatterplot matrix;
pairs(~ Fuzzy.gray.white.ratio+Fuzzy.gw.t.score+AgeWhenTested+signal_mean.noise,
data=datam,subset=status=="control",main="Controls",
labels=c("G/W","Peak Separation","Age","S/N"))
How can I add regression lines to the plots?
2011 Nov 23
2
lines and points in xyplot()
Given the following data, I want a scatterplot with the data points and the predictions from the regression.
Sigma <- matrix(c(1,.6,1,.6), 2)
mu <- c(0,0)
dat <- mvrnorm(5000, mu, Sigma)
x <- dat[,1] * 50 + 200
y <- dat[,2] * 50 + 200
fm <- lm(y ~ x)
### This gives the regression line, but not the data
xyplot(y ~ x,
type = c('g', 'p'),
2004 Mar 19
5
asp=1 and aspect ratio
Hi everyone
I want a square scatterplot with abline(0,1) going exactly through the
SW and NE corners. By "square" I mean that the plotting region is
exactly square, and that the axis limits are identical.
x <- 1:20
y <- x+rep(c(-1,1),10)
lims <- range(c(x,y))
None of the following do this:
plot(x,y) ; abline(0,1) #not square
plot(x,y,asp=1);abline(0,1) #diagonal
2010 Sep 20
2
invalid 'row.names' length error when running scatterplots or plot in R Commander
Hello,
I teach statistics and use R Commander for teaching. I have 2 students
out of 169 that can't get scatterplots or plot to work. I have had them
update packages, restart R/R Commander/their computers and even
reinstall R/R Commander. One is using Windows 7 on a new pc and the
other is a pc user (not sure the OS). They are both using R2.11.1 and R
Commander 1.6-0.
The data look like
2008 Sep 10
4
re flecting a line
Suppose x and y are numeric vectors of the same length.
plot(x,y) #scatterplot
lmObj1 <- lm(y~x) # best fit line
abline(lmObj1) # good
lmObj2 <- lm(x~y) #get best fit but with axes interchanged
abline(lmObj2) # not what I want. I want the correct line, drawn on the same
graph, but with
# response and predictor variables interchanged
One way to proceed would be to
2012 Sep 28
1
blank plot----how do I make symbols appear
Hi,
I am trying to create a scatterplot, coding each point to one of 5
populations. I was successful when I did this for one set of data, yet
when I try plotting other data a blank plot appears (although the axes are
labelled and I can fit the regression lines from each population). I have
tried a variety of things to fix this but nothing seems to work.
I can plot the points if I do not
2006 Oct 31
2
Put a normal curve on plot
I would like to be able to place a normal distribution surrounding the
predicted values at various places on a plot. Below is some toy code
that creates a scatterplot and plots a regression line through the data.
library(MASS)
mu <- c(0,1)
Sigma <- matrix(c(1,.8,.8,1), ncol=2)
set.seed(123)
x <- mvrnorm(50,mu,Sigma)
plot(x)
abline(lm(x[,2] ~ x[,1]))
Say I want to add a normal
2009 Jul 23
2
param:qsec in ggplot2
Hii
i have been trying to do a scatter plot with ggplot2, like the plot 6 here
(http://had.co.nz/ggplot2/geom_point.html) .. where the points size vary
with values
> p + geom_point(aes <http://had.co.nz/ggplot2/aes.html>(size = qsec))
but am not sure how to setup the parameter - qsec
could anyone please give some pointers on how to define that
thanks
Mo.
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