search for: zz

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2009 Jun 08
2
help to speed up loops in r
Hi i am using a script which involves the following loop. It attempts to reduce a data frame(zz) of 95000 * 41 down to a data frame (averagedreplicates) of 95000 * 21 by averaging the replicate values as you can see in the script below. This script however is very slow (2days). Any suggestions to speed it up. NB I have also tried using rowMeans rather than adding the 2 values and dividing b...
2009 Nov 04
4
unexpected results in comparison (x == y)
...ences to vector Z and selecting only (xj - xk), omitting (xk - xj) # and (xj - xj) i.e. diagonal vector Z = rep(0, ((i[1]*i[1])-i[1])/2) nn <- 1 for (j in 1:i[1]) { for (k in 1:i[1]) { if (j > k) { Z[nn] <- abs(Y[j,k]) nn <- nn + 1 } } } nn <- nn - 1 # sorting Z ascending to ZZ, to determine double entries with same difference ii <- 0 ZZ <- sort(Z) # here the problem occurs: ZZ[1:10] ZZ[4] ZZ[5] ZZ[4] == ZZ[5] mode(ZZ[4]) mode(ZZ[5]) length(ZZ[4]) length(ZZ[5]) attributes(ZZ[4]) attributes(ZZ[5]) ----------------------------------------------- I get: > ZZ[1:1...
2009 May 15
2
Help with loops
Hi I am trying to create a loop which averages replicates in my data. The original data has many rows. and consists of 40 column zz[,2:41] plus row headings in zz[,1] I am trying to average each set of values (i.e. zz[1,2:3] averaged and placed in average_value[1,2] and so on. below is my script but it seems to be stuck in an endless loop Any suggestions?? for (i in 1:length(average_value[,1])) { average_value[i] <- i^100;...
2009 May 15
1
Fw: Help with loops(corrected question)
...t Patel <amitrhelp at yahoo.co.uk> > Subject: Help with loops > To: r-help at r-project.org > Date: Friday, 15 May, 2009, 12:17 PM > Hi > I am trying to create a loop which averages replicates in > my data. > The original data has many rows. and consists of 40 column > zz[,2:41] plus row headings in zz[,1] > I am trying to average each set of values (i.e. zz[1,2:3] > averaged and placed in average_value[1,2] and so on. > below is my script but it seems to be stuck in an endless > loop > Any suggestions?? > > for (i in 1:length(zz[,1])) { >...
2002 May 20
1
how does one apply Western Electric / AT&T rules to R plots?
I have searched for info on how to apply the Western Electric rules for process control, to data and plots I have in R, but I have not been able to learn how. Any help would be greatly appreciated. Thank you, sjcrauhut at agere.com 05/20/02 -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read
2006 Nov 03
1
mbox sync: Expunged message reappeared in mailbox
...ning, one user on my dovecot server is receiving hundreds of copies of old email. This is a short excerpt from my dovecot.log showing the problem: > dovecot: Nov 03 05:27:02 Info: pop3-login: Login: > user=<howard at obfusca.ted>, method=PLAIN, rip=::ffff:81.44.31.210, > lip=::ffff:zz.zz.zz.zz, TLS > dovecot: Nov 03 05:27:02 Info: POP3(howard at obfusca.ted): Disconnected: > Logged out top=0/0, retr=0/0, del=0/0, size=0 > dovecot: Nov 03 05:32:01 Error: POP3(joyce at obfusca.ted): mbox sync: > Expunged message reappeared in mailbox > /var/mail/vhosts/obfusca.ted/j...
2010 Jun 22
4
seek() and gzfile() on 32-bit R2.12.0 in linux
...9;t appear in the 64-bit installation. I realize that seek() has been difficult in the past, and I don't want to open old wounds, but is this a known problem? Is this easily fixable? I have a package that relies on seek() when accessing gzipped files. Using the 32-bit installation... *> zz <- file("ex.data", "w") # open an output file connection > cat("TITLE extra line", "2 3 5 7", "", "11 13 17", file = zz, sep = "\n") > cat("One more line\n", file = zz) > close(zz) > blah...
2004 Jan 26
5
conditional assignment
Hi all I want to conditionally operate on certain elements of a matrix, let me explain it with a simple vector example > z<- c(1, 2, 3) > zz <- c(0,0,0) > null <- (z > 2) & ( zz <- z) > zz [1] 1 2 3 why zz is not (0, 0, 3) ????? the null <- assignment is to keep the console silent in the other hand, it curious that null has reasonable values > null [1] FALSE FALSE TRUE Thanks in advance Ulisses...
2008 Jan 16
3
replace numbers in a column conditional on their value
Dear R help, I have a data frame column in which I would like to replace some of the numbers dependent on their value. data frame = zz AveExpr t P.Value FC 7.481964 7.323950 1.778503e-04 2.218760 7.585783 12.233056 6.679776e-06 2.155867 6.953215 6.996525 2.353705e-04 1.685733 7.647513 8.099859 9.512639e-05 1.674742 7.285446 7.558675 1.463732e-04 1.584071 6.405605 3.344031 1.276812e-02 1.541569 I wo...
2008 Jul 30
1
model mix problem. FALSE CONVERGENCE
...sultats=NULL Res=NULL i=0 while(i!=length(ions)) { i=i+1 myion=toto[,i] mixed=lme(myion ~ v1*v2, random= ~ 1 | Subject/v1,method="REML") ## effet al?atoire sujet(v1) #summary(mixed) #anova(mixed) zz=anova(mixed) Res <- data.frame(ions[i],toto1[i,2:(dim(toto1)[2]-n)],t(zz[-1,4]),toto1[i,c((dim(toto1)[2]-n+1):dim(toto1)[2])]) Resultats <- rbind(Resultats,Res) } if (i!=length(ions)) { while(i!=length(ions)) { i=i+1 myion=...
2005 Jul 10
0
Time out not working from php agi...
...ame or address 2005-06-28 20:26:13 DEBUG[19094] chan_h323.c: Placing outgoing call to 880178034593@xx.xx.xx.xx:1720, 101 2005-06-28 20:26:13 VERBOSE[19094] logger.c: -- Called 880178034593@xx.xx.xx.xx:1720 2005-06-28 20:58:41 DEBUG[19094] channel.c: Didn't get a frame from channel: IAX2/User@zz.zz.zz.zz:4569-13 2005-06-28 20:58:41 DEBUG[19094] channel.c: Bridge stops bridging channels IAX2/User@zz.zz.zz.zz:4569-13 and H323/ 2005-06-28 20:58:41 DEBUG[19094] app_dial.c: Exiting with DIALSTATUS=ANSWER. 2005-06-28 20:58:41 VERBOSE[19094] logger.c: callcard.php: >> GET VARIABLE ANSWEREDT...
2005 Aug 29
4
ttda on R 2.1.1: error
Hello, I'm trying to use the package ttda, wich is involved in text analysis, for my own data about answers in a company survey. I've installed it, as well as ispell, but when trying to use an example: > zz <- file("stupid.txt", "w") # build a data file > cat("{comment - stupid data file} \n" , file = zz) > cat("<uci=1> Hush-a-bye, baby, \n" , file = zz) > cat(" in the tree top. \n"...
2002 Oct 17
4
Multiple colors in plots/lookup function
Hello, I'd like to do something like: n<-100 zz<-cbind(rnorm(n),rnorm(n),floor(runif(n)*3+1)) colors<-c("red","green","blue") plot(zz,col=colors(zz[3])) and have a matrix of scatterplots colored by class. The above does not work, of course, but I'm not sure exactly what function I'm looking for....
2005 Jun 02
1
Wishlist: more flexible handling of tick labels in axis.Date (PR#7913)
...te" if (d < 7) if (missing(format)) format <- "%a" if (d < 100) { z <- structure(pretty(z), class = "Date") if (missing(format)) format <- "%b %d" } else if (d < 1.1 * 365) { zz <- as.POSIXlt(z) zz$mday <- 1 zz$mon <- pretty(zz$mon) m <- length(zz$mon) m <- rep.int(zz$year[1], m) zz$year <- c(m, m + 1) z <- .Internal(POSIXlt2Date(zz)) if (missing(format)) format <- "%b"...
2013 Apr 15
2
Remove Rows Based on Factor
...hat I am getting. I am hoping that this is a simple syntax phenomenon that somebody else knows off the top of their head. My apologies for not providing a reproducible example but I think that the information given will allow someone to give me a hint. I want to delete the rows of the data frame ZZ where Index is earlier that Jan 1 of 2007. That Index column is a factor. When I tired a couple of different methods, I got the error shown below. Can anybody tell me what I am doing wrong? I would really appreciate it. --John Sparks > str(ZZ) 'data.frame': 1584 obs. of 7 variab...
2013 Apr 08
2
cbind for list of zoo objects
Can someone explain why this happens when one of the list elements is named 'all'? > zz <- list( zoo(1:10,1:10), zoo(101:110,1:10), zoo(201:210,1:10) ) > names(zz)<-c('test','bar','foo') > do.call(cbind,zz) test bar foo 1 1 101 201 2 2 102 202 3 3 103 203 4 4 104 204 5 5 105 205 6 6 106 206 7 7 107 207 8 8 108 208...
2007 Nov 09
1
make check-all fails on F8
...; "ls()" "pi" "# last line" > source("testIO.R", echo=TRUE) > #line 1 > 2+3 [1] 5 > ls() [1] "z" > pi [1] 3.141593 > unlink("testIO.R") > > ## ======== LF file, incomplete final line > zz <- file("testIO.R", "wt") > cat(z, file=zz, sep="\n") > cat("5+6", file=zz) > close(zz) > readLines("testIO.R") [1] "#line 1" "2+3" "ls()" "pi" "# last line&quot...
2001 Oct 09
3
Unlisting while preserving object types?
Hi A toy example is probably the least ambiguous way of explaining what I'm trying to do. > library(ts) > zz<-list(a=rnorm(100),b=rt(100,3)) > zz.spec<-lapply(zz,spectrum,plot=F) > summary(zz.spec) Length Class Mode a 15 spec list b 15 spec list I'm looking for an elegant way to fetch components of the sub-lists a and b of zz.spec; e.g. to make a matrix with columns a$spec an...
2006 Aug 31
2
cumulative growth rates indexed to a common starting point over n series of observations
What is the R way of computing cumulative growth rates given a series of discrete values indexed . For instance, given a matrix of 20 observations for each of 5 series (zz), what is the most straight forward technique in R for computing cumulative growth (zzcum) ? It seems for the solution I'm after might be imbedding the following cum growth rate calc as a function into a function call to apply, mapply, ...? zz = rnorm(100) dim(zz) = c(20,5) zz zzcum=matr...
2004 Mar 17
9
Frequency table
...site search. I am trying to construct a frequency table. I guess this should be done with table. Or perhaps factor and split. Or prop.table. cut? findInterval? Argh! Please correct me if what I am looking for is not called a "frequency table". Perhaps it's called grouped data. > zz$x9 [1] 65 70 85 65 65 65 62 55 82 59 55 66 74 55 65 56 80 73 45 64 75 58 60 56 60 [26] 65 53 63 72 80 90 95 55 70 79 62 57 65 60 47 61 53 80 75 72 87 52 72 80 85 [51] 75 70 84 60 72 70 76 70 79 72 69 80 62 74 54 58 58 69 81 84 I (think) I want it to look like: 40-49 2 50-59 15 60-69 20 70-...