search for: zmm14

Thank You, It means vmovdqa64 zmm22, zmmword ptr [rip + .LCPI0_0] # zmm22 = [8,9,10,11,12,13,14,15] zmm22 will contain 64 bit constant values which are indexes here zmm22=8, 9, 10, 11, 12,13,14,15. not the values loaded from these locations. and zmm2 contains constant 4000. so, vpmuludq zmm14, zmm10, zmm2 ; will multiply the indexes values with 4000, as for array b the stride is 4000. zmm14= 3200, 3600, 40000, ............28000. now as you said vpsrlq zmm15, zmm10, 32 ; will shift zmm10(=zmm22) each 64 bit element by 32bit so zmm15=? (can you compute the value of zmm15 here)?...