Displaying 3 results from an estimated 3 matches for "zjoanna2013".
2013 Mar 29
3
if clause in data frame
...final1)
#? m1 n1 x1 y1 flag
#1? 4? 4? 0? 0??? 0
#2? 4? 4? 0? 1??? 0
#3? 4? 4? 0? 2??? 0
#4? 4? 4? 0? 3??? 0
#5? 4? 4? 0? 4??? 0
#6? 4? 4? 1? 0??? 1
Also, just by looking at your code, you have "flag" and "flap".
A.K.
________________________________
From: Joanna Zhang <zjoanna2013 at gmail.com>
To: arun <smartpink111 at yahoo.com>
Sent: Friday, March 29, 2013 10:56 AM
Subject: if clause in data frame
Why the if clause code not working here?
final<-data.frame()
? ?for (m1 in 4:10) {
? ? ? ?for (n1 in 4:10){ ?
? ? ? ? ? ?for (x1 in 0: m1) {
? ? ? ? ? ? ? for (...
2013 Mar 10
0
max row
...<- 0.10
c2<- 0.10
One possible problem is that:
dim(res5)
#[1] 513? 20
res6<-aggregate(.~m1+n1+m+n,data=res5[,c(1:6,9:12,21:24)] ,max)
#Error in `[.data.frame`(res5, , c(1:6, 9:12, 21:24)) :
?# undefined columns selected
A.K.
________________________________
From: Joanna Zhang <zjoanna2013 at gmail.com>
To: arun <smartpink111 at yahoo.com>
Sent: Saturday, March 9, 2013 10:38 PM
Subject: Re: max row
I think something is wrong with EN, it should not be integer. Let me check.
On Sat, Mar 9, 2013 at 9:36 PM, arun <smartpink111 at yahoo.com> wrote:
In the example set...
2013 Feb 01
29
cumulative sum by group and under some criteria
Thank you very much for your reply. Your code work well with this example.
I modified a little to fit my real data, I got an error massage.
Error in split.default(x = seq_len(nrow(x)), f = f, drop = drop, ...) :
Group length is 0 but data length > 0
On Thu, Jan 31, 2013 at 12:21 PM, arun kirshna [via R] <
ml-node+s789695n4657196h87@n4.nabble.com> wrote:
> Hi,
> Try this:
>