search for: ziparch

Hello, is there a way to pass a connection to a file in a zipped archive as argument (instead of a file name of unzipped file) to shell command "cut". In general, is it possible to pipe output of a R function to a shell command? How? I want to do something like: z = unz("zipArchive.zip", "fileASCII.ASC") # open connection open(z) # cut lines of the ASCII file in zipped archive at specific postions and send results to another file. shell("cut -c2-3,5-8 z > test2.dat") Anupam.

...I'm using decided to use a zip archive as a means of batching together a collection of picture files for a bulk upload. Apache is reporting the following PHP error when the bulk upload feature is used: [Sun Nov 16 22:05:38 2008] [error] [client 192.168.0.192] PHP Fatal error: Class 'ZipArchive' not found in /var/www/fraud/html/davesBlog/sites/all/modules/photos/photos.module on line 1375, referer: http://davenjudy.org/davesBlog/node/39/photos The PHP code at line 1375 in photos.module is an unremarkable instantiation of the zip archive handling object. Some Google searches...

Hello, I am trying to use R to download a bunch of .csv files such as: http://biocache.ala.org.au/ws/occurrences/download?q=Banksia+ericifolia I have tried the following and neither work: a<- getURL(" http://biocache.ala.org.au/ws/occurrences/download?q=Banksia+ericifolia") Error in curlPerform(curl = curl, .opts = opts, .encoding = .encoding) : embedded nul in string: and