search for: zinter_pa_c

Displaying 5 results from an estimated 5 matches for "zinter_pa_c".

2017 May 05
6
lm() gives different results to lm.ridge() and SPSS
Hi, Here is (I hope) all the relevant output from R. > mean(s1$ZDEPRESSION, na.rm=T) [1] -1.041546e-16 > mean(s1$ZDIVERSITY_PA, na.rm=T) [1] -9.660583e-16 > mean(s1$ZMEAN_PA, na.rm=T) [1] -5.430282e-15 > lm.ridge(ZDEPRESSION ~ ZMEAN_PA * ZDIVERSITY_PA, data=s1)$coef ZMEAN_PA ZDIVERSITY_PA ZMEAN_PA:ZDIVERSITY_PA -0.3962254 -0.3636026
2017 May 05
1
lm() gives different results to lm.ridge() and SPSS
...observing is from fitting different models. In R, you fitted: > > res <- lm(DEPRESSION ~ ZMEAN_PA * ZDIVERSITY_PA, data=dat) > summary(res) > > The interaction term is the product of ZMEAN_PA and ZDIVERSITY_PA. This is not a standardized variable itself and not the same as "ZINTER_PA_C" in the png you showed, which is not a variable in the dataset, but can be created with: > > dat$ZINTER_PA_C <- with(dat, scale(ZMEAN_PA * ZDIVERSITY_PA)) > > If you want the same results as in SPSS, then you need to fit: > > res <- lm(DEPRESSION ~ ZMEAN_PA + ZDIVERS...
2017 May 05
0
lm() gives different results to lm.ridge() and SPSS
...The difference you are observing is from fitting different models. In R, you fitted: res <- lm(DEPRESSION ~ ZMEAN_PA * ZDIVERSITY_PA, data=dat) summary(res) The interaction term is the product of ZMEAN_PA and ZDIVERSITY_PA. This is not a standardized variable itself and not the same as "ZINTER_PA_C" in the png you showed, which is not a variable in the dataset, but can be created with: dat$ZINTER_PA_C <- with(dat, scale(ZMEAN_PA * ZDIVERSITY_PA)) If you want the same results as in SPSS, then you need to fit: res <- lm(DEPRESSION ~ ZMEAN_PA + ZDIVERSITY_PA + ZINTER_PA_C, data=dat...
2017 May 05
1
lm() gives different results to lm.ridge() and SPSS
...ls. In >>R, you fitted: >> >> res <- lm(DEPRESSION ~ ZMEAN_PA * ZDIVERSITY_PA, data=dat) >> summary(res) >> >> The interaction term is the product of ZMEAN_PA and ZDIVERSITY_PA. This >>is not a standardized variable itself and not the same as "ZINTER_PA_C" >>in the png you showed, which is not a variable in the dataset, but can >>be created with: >> >> dat$ZINTER_PA_C <- with(dat, scale(ZMEAN_PA * ZDIVERSITY_PA)) >> >> If you want the same results as in SPSS, then you need to fit: >> >>...
2017 May 05
0
lm() gives different results to lm.ridge() and SPSS
...dels. In >>R, you fitted: >> >> res <- lm(DEPRESSION ~ ZMEAN_PA * ZDIVERSITY_PA, data=dat) >> summary(res) >> >> The interaction term is the product of ZMEAN_PA and ZDIVERSITY_PA. This >>is not a standardized variable itself and not the same as "ZINTER_PA_C" >>in the png you showed, which is not a variable in the dataset, but can >>be created with: >> >> dat$ZINTER_PA_C <- with(dat, scale(ZMEAN_PA * ZDIVERSITY_PA)) >> >> If you want the same results as in SPSS, then you need to fit: >> >> res...