search for: yz

...hed ps). Thanks by the help, Cezar Freitas. #Example: #data scores<-c(2.0, 0.0, 5.0, 5.0, 5.0, 2.0, 0.0, 5.0, 2.5, 4.0, 5.0, 0.0, 5.0, 0.0, 2.0, 5.0, 5.0, 2.0, 3.0, 3.0) q<-summary(scores) gra<-hist(scores, breaks=((0:11)/2-.2), plot=FALSE) yy<-ceiling(max(gra$counts)/10)*10 yz<-yy/12 #plot via postscript postscript("test.ps", width=3, height=3, horizontal=FALSE, family="Times", paper="special") hist(scores, breaks=((0:11)/2-.2), xlim=c(-1,6), ylim=c(-yz,yy), main="scores", ylab="Freq", xlab="math", cex....

Dear R People: Hope you're having a nice day. Here is a character vector: > yz [1] "pexp(3.2,rate=1)" > str(yz) chr "pexp(3.2,rate=1)" > And I would like to evaluate that vector. I tried: > eval(as.expression(yz)) [1] "pexp(3.2,rate=1)" > But that doesn't work. Any suggestions would be most welcome. I have a feeling that it...

...med only when operand Op1 ( (X/Y) in this case) has only one use in future. The code snippet is shown below. if (match(Op1, m_OneUse(m_FDiv(m_Value(X), m_Value(Y)))) && (!isa<Constant>(Y) || !isa<Constant>(Op0))) { // Z / (X / Y) => (Y * Z) / X Value *YZ = Builder.CreateFMulFMF(Y, Op0, &I); return BinaryOperator::CreateFDivFMF(YZ, X, &I); } It would be great if someone explains if there is any issue (correctness/performance-wise) if we avoid the m_OueUse check. What if we perform the transformation even if there are multiple uses...

...core of 0.79 has been converted into 1.08; is this correct?) FisherZ(lm(v2~v1)$coefficients[2]) > v1 > 1.081667 lm(v2~v1)$coefficients[2] > v1 > 0.7938164 # apply test v1_v2 = FisherZ(lm(v2~v1)$coefficients[2]) v1_v3 = FisherZ(lm(v3~v1)$coefficients[2]) paired.r(v1_v2, v1_v3, yz=NULL, length(v1), n2=NULL, twotailed=TRUE) > Call: paired.r(xy = v1_v2, xz = v1_v3, yz = NULL, n = length(v1), n2 = NULL, > twotailed = TRUE) > [1] "test of difference between two independent correlations" > z = NaN With probability = NaNWarning messages: > 1: In log((...

Is there a simple way to decompose the upper triangle of a correlation matrix to a linear list; For example: X Y Z X 1 2 3 Y 2 1 4 Z 3 4 1 so you get a list like: xy 2 XZ 3 YZ 4 I suspect you can do it with a matrix transformation, but that beyond me at present. Many thanks Mark _________________________ Department of Molecular and Human Genetics, Baylor College of Medicine,

...nly >> one use in future. The code snippet is shown below. >> >> if (match(Op1, m_OneUse(m_FDiv(m_Value(X), m_Value(Y)))) && >> (!isa<Constant>(Y) || !isa<Constant>(Op0))) { >> // Z / (X / Y) => (Y * Z) / X >> Value *YZ = Builder.CreateFMulFMF(Y, Op0, &I); >> return BinaryOperator::CreateFDivFMF(YZ, X, &I); >> } >> >> It would be great if someone explains if there is any issue >> (correctness/performance-wise) if we avoid the m_OueUse check. What if >> we perfo...

...ion exists which will determine if any two selected points are on different axes, i.e, if the one of the points is on x and the other on y or z, not elsewhere on the x axis. Put another way, I need to determine if the triangle formed by the two points and the origin lies in the xy, xz or yz planes. This might be as simple as testing if any particular value is zero, i.e. if the x coordinate is zero, then the points must be on the z and y axes and the triangle in the yz plane. But, I'm looking for a fairly general solution, one that also returns the appropriate plane as th...

...hing like: my_fun <- function(m) { if( nrow(mat) != ncol(mat) ) { stop("'m' must be a square matrix") } size <- nrow(m) for(x in 1:(size -2)) { for(y in (x+1):(size -1)) { xy <- m[x,y] for(z in (y+1):size ) { xz <- m[x,z] yz <- m[y,z] # do something with xy, xz, yz } } } } I'd like to speed this up since when size gets > a few thousand, I estimate it would take 3yrs to complete the "do something" task. I could implement the "do something" in C and have it called from...

...correct?) > FisherZ(lm(v2~v1)$coefficients[2]) > > v1 > > 1.081667 > lm(v2~v1)$coefficients[2] > > v1 > > 0.7938164 > # apply test > v1_v2 = FisherZ(lm(v2~v1)$coefficients[2]) > v1_v3 = FisherZ(lm(v3~v1)$coefficients[2]) > paired.r(v1_v2, v1_v3, yz=NULL, length(v1), n2=NULL, twotailed=TRUE) > > Call: paired.r(xy = v1_v2, xz = v1_v3, yz = NULL, n = length(v1), n2 = NULL, > > twotailed = TRUE) > > [1] "test of difference between two independent correlations" > > z = NaN With probability = NaNWarning messag...

...lications seem to run fine uder wine, but for any MSDOS-Application FILE, I get the following error: wine: can't exec 'FILE': invalid exe file Protocol error: process 0x806a100: partial recvmsg 0 for fd This happens regardless of winver/dosver (wine is called by 'wine --winver winxyz --dosver x.yz FILE'). What am I doing wrong? Do I need to start some kind of msdos-wrapper instead of the application itself? Thx in advance Sven

...le dataset: library(ROCR) data(ROCR.simple) pred <- prediction(ROCR.simple$predictions, ROCR.simple$labels) perf <- performance(pred, "rec") plot(perf) But R crashes on me on the last line. I'm using R 2.14.1, ROCR 1.0-4. ?Any ideas? Thanks in advance. -- Yang Zhang http://yz.mit.edu/

...hen I supply a trainControl summaryFunction, the data given to it contains only class predictions, so the only metrics possible are things like accuracy, kappa, etc. Is there any way to do this that I'm looking? If not, could I put this in as a feature request? Thanks! -- Yang Zhang http://yz.mit.edu/

...snippet is shown below. >>>> >>>> if (match(Op1, m_OneUse(m_FDiv(m_Value(X), m_Value(Y)))) && >>>> (!isa<Constant>(Y) || !isa<Constant>(Op0))) { >>>> // Z / (X / Y) => (Y * Z) / X >>>> Value *YZ = Builder.CreateFMulFMF(Y, Op0, &I); >>>> return BinaryOperator::CreateFDivFMF(YZ, X, &I); >>>> } >>>> >>>> It would be great if someone explains if there is any issue >>>> (correctness/performance-wise) if we avoid the m...

...I will have a lot of spare time. I will be happy if you assign some work to me. I have learn linux kernel for years but only fix a few small bugs in IP stack. In the past few months, I read some EXT4/VFS codes. I began reading source of btrfs ten days ago and have read it twice now. Regards YZ

Hi, I recompiled my kernel today, and when the btrfs-0.13 option is enabled (CONFIG_BTR_FS=y) I cannot boot on my reiserfs-3.6 partition any more. The kernel says that is cannot mount /dev/sdc6. I can boot the kernel when I recompile it with the same options and CONFIG_BTR_FS=n, and with the same boot options as well. Everything is amd64 on my system (kernel + programs). Here is a screenshot of

...9.8,16),rep(12.4,10),rep(16.3,5), rep(38,5)) DF<-data.frame(ids,years,data,data2) That will give you a dataframe that is a good analog of what I have. i would like to calculate means ( with NA removed na.rm) for each level of years. data data2 5 xx. yy. 6 xx yz 7 ... ,,, 8 .. ... And then things like this: 5-7 : xx yy 8 : xy zz [[alternative HTML version deleted]]

....2)) en este dominio 0<= x <= y <=1 En el ejemplo que hay abajo, se dibuja para 0<=x<=1, 0<=y<=1. ¿Me pueden ofrecer alguna ayudita para dibujarla en el recinto 0<= x <= y <=1 ? Y si además me indican cómo dibujar las proyecciones (curvas de nivel) en los planos XY, YZ y XZ, ¡menudo dibujo quedaría! ¡Gracias! Emilio library(plot3D) x <- seq(0, 1,length.out=50) y <- seq(0, 1,length.out=50) M <- mesh(x, y) surf3D(x = M$x, y = M$y, z = pmin( 1 - abs(M$x-0.7), 1-abs(M$y-0.2) ), colkey=TRUE, bty="g") -- =============...

...is i propose the following tagging and sub-tagging system, which is easy, simple, flexible, detailed for those who want it. Tags are for simple comments, and has the form: TITLE=Title Subtags are for detailed comments, and has the form: ARTIST=COMPOSER=Xz ARTIST=PERFORMER=Yz This way, detailed info about the artist (as most mortal beeings think of it) are available while still beeing part of the simpler standard, which as a bonus also is backwards-compatible with existing players. If a player supports the subtags, it will display them in the detailed form:...

Howdy! I need to calculate partial correlations and I just can't find out how to do that with R. Can anybody help? Ragnar -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or "[un]subscribe" (in the "body", not the subject !)

...ctors "A", "B", "C", "D", etc and Z is a column of n factors "a", "b", "c", etc if i do MyLm<-lm(X~Y*Z - 1) i get all N coefficients for Y-factors, but only n-1 coefficients for Z-factors, and only N*(n-1) coefficients for YZ interaction. Is that how it's supposed to be? I would like to get N coefficients for all factors Y and n coefficients for all factors Z - how can i do that? Thank you very much, Vlad -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read...