search for: yyyi

I am trying, without success, to compile a custom locale for the utf-8 character set. I have issued this command: localedef --no-archive -f UTF-8 -i /usr/share/i18n/locales/en_CA at yyyy-mmm-dd en_CA at yyyy-mmm-dd.utf8 which produces the requisite files without reporting an error but which none-the-less insists on using the iso-8859-1 charset: LC_ALL=en_CA at yyyy-mm-dd locale charmap

The input values could be something like this: 01-Dec-2006 01-December-2006 1-June-2006 Is there an easy to way to get the three variables populated dd, mmm and yyyy for any of the above input values? I tried to look at regex but couldn'' anything simple. Thanks -------------- next part -------------- An HTML attachment was scrubbed... URL:

Hello, I am trying to setup a samba4 AD dc in my network using smb-tool. Everything seems to work except DNS forwarding. If I query for the dc root at dc:~# nslookup dc.local.domain.it I get the correct answer: root at dc:~# nslookup dc Server:???????? aaa.bbb.ccc.ddd Address:??????? aaa.bbb.ccc.ddd#53 Name:?? dc.xxxx.yyyy.it Address: aaa.bbb.ccc.ddd but if I query for an external domain: root

https://bugs.freedesktop.org/show_bug.cgi?id=70130 Priority: medium Bug ID: 70130 Assignee: nouveau at lists.freedesktop.org Summary: unable to compile fragment shader program Severity: normal Classification: Unclassified OS: Linux (All) Reporter: infyquest at gmail.com Hardware: x86 (IA32)

Hi, Presently I have the latest full backup in a 'current' directory and 30 day incrementals in 'YYYY-MM-DD' format directories. Without changing that directory structure I'd like the 'YYYY-DD-MM' directories to contain the full system hardlinked (when applicable) to 'current'. What rsync command-line options could provide me with this? Thanks,

Hello All, I am having a problem with samba's ability to interpret certain files with windows 2k clients. Setup Details: Linux ( RedHat 7.3 ) File Server Win 2k Clients Samba v2.2.3a Kernel 2.4.18 statically compiled. Problem Description: When copying jpegs from a Win2k client which is displaying the JPEGS in thumbnail mode, to the Linux / Samba file server, 3 files are copied as

Hi folks, I have been tormented for some time by Excel's habit of exporting dates to CSV files as mm/dd/yyyy format even if the dates are formatted dd/mm/yyyy in the display. What's worse, if there are dates that are of ambiguous (6/6/2011) and unambiguous (16/6/2011) format in the same column, Excel reformats the unambiguous dates and leaves the ambiguous ones as they were! Yesterday

Hello List, with CentOS 7.2 it is not longer possible to run fail2ban on a Server ? I install a new CentOS 7.2 and the EPEL directory yum install fail2ban I don't change anything only I create a jail.local to enable the Filters [sshd] enabled = true .... ..... When I start afterward fail2ban systemctl status fail2ban is clean But systemctl status firewalld is broken ? firewalld.service -

Hello experts, I have installed Samba3.0.1 for "Account Domain Controller(PDC)" and openLDAP2.2.6 for backend database which stores user accounts. There is Windows2000 Server for "Resource Domain controller" that has a trust relationship with Samba "Account Domain Controller". WINS service is running on "Resource Domain Controller" Windows2000 Server

Dear list, I am trying to evaluate how many elements in a vector equal a certain value. The vectors are the columns of a data.frame, read in using read.table(): > dim(data) [1] 2600 742 > data[1:5,1:5] SNP001 SNP002 SNP003 SNP004 SNP005 1 GG AA TT TT GG 2 GG AA TC TT GG 3 GG AC CC TT GG 4 AG AA TT TT GG 5

Dear R-WinEdit users, I got a simple question, but somehow I cannot find the answer, although I have tried a lot! I got an ASCII-file and I want to import it into R, so that every character is defined by [i;j]. The rows are not of the same length. the file looks like the following shortened abstract example: name: xxxxx xxxx age: 9.9.99 record number: 999 title: xxxxx xxxx xxx keywords: xxx xx

I am reading dates in Excel2007 into R. Here are the functions I used: library(RODBC) channel<-odbcConnectExcel2007("myfile.xlsx") tmp<-sqlFetch(channel,"1",as.is=T) The dates in myfile.xlsx are all in this format: mm/dd/yyyy. But when I read it to R, some columns look like "yyyy-mm-dd 00:00:00", some columns look like "yyyy-mm-dd", and some

Hi, My setup is: Ruby 1.8.6 Rails 2.3.5 activerecord-oracle-adapter (1.0.0.9250) I upgraded Rails and the adapter recently and I just went through hell trying to find a problem while inserting a record in a table. Rails was giving me this error: OCIError (ORA-02289: sequence does not exist): stmt.c:539:in oci8lib.so c:/ruby/lib/ruby/site_ruby/1.8/oci8.rb:753:in `exec''

Hello R Users, How to convert decimal date to date as YYYY.mm.dd.hr.min.sec For example, I have decimal date in one column , and want to convert and write it in equivalent date(YYYY.mm.dd.hr.min.sec) in another next six columns. 1979.000000 1979.020833 1979.041667 1979.062500 Is it possible in R ? Kindly help, Regards, Yogesh -- Dr. Yogesh K. Tiwari, Scientist, Indian Institute

The US water year extends from 01 October yyyy-1 through 30 September yyyy and is referenced by the year starting on the included 01 January yyyy. I'd like to be able to find the annual means for the water year. To do so I've taken the input date-time, which is in the usual format "1991-10-07 10:35:00" changed it by: w$d<-as.POSIXct(w$date.time) Now I can add an

Hello, I have a set of data that has a Date column looks like this: 12/9/2007 12/16/2007 1/1/2008 1/3/2008 1/12/2008 etc. I'd like the date to look something like the follow (so that I could sort by date easily). 20071209 20071216 20080101 20080103 20080112 How to do it? Thank you very much Julia -- View this message in context:

dear kind helper, i would like to know how to find the annual maximun for a table that basicly looks like this: date time measurement1 measurement2 measurement3 mm/dd/yyyy hh:mm:ss m1 m2 m3 there are about 9000 measurements for each year, which makes it quite large... i already tried to subset all rows for a year, to find the maximum within these choosen rows, y <-

Hi, I''m stuck. How do you parse a "dd/mm/yyyy" formatted date string??? I get a date format error. Thanks in advance Greg --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Ruby on Rails: Talk" group. To post to this group, send email to

Hi all, I am using InstantRails with MySQL-Front. Date is stored in format yyyy-mm-dd in database. I want to retrieve and show date in dd-mm-yyyy in my view.rhtml. How can I change it to dd-mm-yyyy form. Please help me out. Thanks -- Posted via http://www.ruby-forum.com/. --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google

Dear anyone who knows more about R than me (so everyone). I have been bashing my head on the keyboard all day trying to do something with my table. I have some data, like so: yyyy-mm Rainfall(mm) 1 1977-02 17.4 2 1977-03 34.0 3 1977-04 26.2 4 1977-05 42.6 5 1977-06 58.6 6 1977-07 23.2 7 1977-08 26.8 8 1977-09 48.4 9