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I am working on a simulation where I need to count the number of matches for an arbitrary pattern in a large sequence of binomial factors. My current code is for(indx in 1:(length(bin.05)-3)) if ((bin.05[indx] == test.pattern[1]) && (bin.05[indx+1] == test.pattern[2]) && (bin.05[indx+2] == test.pattern[3])) return.values$count.match.pattern[1] =

Greetings, I am not familiar with processing text in R. Can someone tell me how to read each line of words as separate elements in a list? FE, I would like to turn: word1 word2 word3 word2 word4 into a list of length two with three character elements in the first list and two elements in the second. I know that this should be easy, but I am a little confused by the text functions. Thanks in

Dear contributors I have tried this experiment: x<-c() for (i in 1:12){ x[i]<-list(cbind(x1[i],x2[i])) #this is a list of 12 couples of time series I am using to perform a test } # that compares them 2 by 2 # ################# #trace statistic test<-data.frame() cval<-array( , dim=c(2,3,12)) for (i in 2:12){ for (k in 1:2){ for (j in 1:3){ result[k,j,i]<-

I have a list of vectors $A "AB" "BC" "CD" $B "GF" "HG" "FH" "FJ" and I want to convert it into a dataframe of form A AB A BC A CD B GF B HG B FH B FJ Just can't quite come up with a nice "R" solution for it. Thanks, Sean

Dear everybody! Is there a command to add elements to an existing list, at best excluding the addition of already included ones? Thank you in advance. Yours, Mag. Ferri Leberl

Dear R users, I have created a function f of n, a and b : f(n,a,b) I would like to apply this function several times to some values of n. a and b are held constant. I was thinking of using lapply. How can I do this ? Thank you very much Randall [[alternative HTML version deleted]]

hi,everybody: I get a list as following. For each element of the list, it has names such as "Var1" and "Freq". May I ask how to remove them? And, may I ask how to make them form a matrix such as like concatinating them? Thank you! The list I got: [[1]] Var1 Freq 1 -5.20726501684368 19 2 1.89099344331540 31 [[2]] Var1

I am looking for a function to flatten a list to a list of only 1 level deep. Very similar to unlist, however I don't want to turn it into a vector because then everything will be casted to character vectors: x <- list(name="Jeroen", age=27, married=FALSE, home=list(country="Netherlands", city="Utrecht")) unlist(x) This function sort of does it: flatlist

Hello I have done resampling from a matrix data with two variables (A,B). After resampling a get a set of lists (see below example for resample size 2). In both lists I have the same two variables (A,B). I want to export this data to an excel file where I have only two columns, one per variable. Thus, stack the data for variable A in a single column and the same for variable B. I have tried to

Dear R helpers: I wonder how to pass more than one argument to the function called by lapply. For example, #R code below --------------------------- indf <- data.frame(id=I(c('a','b')),y=c(1,10)) #I want to add an addition argument cutoff into the function called by lapply. outside.fun <- function(indf, cutoff) { unlist(lapply(split(indf, indf[,'id']),

DeaR useRs: I have a list with 500 elements, in each other there are data.frames and I want to take the first row and the first column of each elements of my list since the first to the 500-th. Thanks and excuse my bad English. --- [[alternative HTML version deleted]]

Hi! I have a data.frame "data" and splitted it. data <- split(data, data[,1]) This is a quite slow procedure; and I do not want to do it again. So, any unsplit and "resplit" is no option for me. But: I have to cbind "variables" to the splitted data from another list, that contains of vectors with matching sizes, so for (i in 1:length(data)) { data[[i]]

Hi Sorry to ask such a basic question. I have a list, each element of which is a vector of two values. What I actually want is a matrix with two columns, and one row per element of the list. Obviously I have tried as.matrix(), and as.vector() but I didn't expect the latter to work. I feel so lame asking this. Any suggestions? Mick

ls is a list of character vectors created by strsplit() I want to concatenate the 1st 4 character elements of each list item as a new vector called file. I admit to being confused about list syntax even after numerous readings. Here's what I tried: ls <- list(c("Focused", "10k", "A12", "t04.tif", "+", "µm"),

Hi all, I'm hoping this question has a simple answer, but I can't find it through searching or trying commands. I have a list of numeric vectors called 'husk'. I'd just like to treat the set of all numbers from all vectors in the list as if it were one large vector, because I'd like to extract information, such as what is the max entry from all the numbers. > husk

Hello I am am new to R and any help with the following would be appreciated: I have a list (example attached) and I would like to create a new list which is a filtered version of this list. I.e I would like a list that only contains elements with this value: Chr 10 : 21853562 - 21855482 Any pointers/tips would be great. Thanks! Nikol -- Bioinformatician/Computer Associate Cambridge Institute

Hi, I've tried to figure this out using Intro to R and help(), to no avail - I am new at this. I'm trying to write a script that will read multiple files from a directory and then merge them into a single new data frame. The original data are in a tree-ring specific format, and so I've first used a function (read.rwl) from the dplR package to read each file, translate each into a