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2012 Feb 25
5
which is the fastest way to make data.frame out of a three-dimensional array?
foo <- rnorm(30*34*12)
dim(foo) <- c(30, 34, 12)
I want to make a data.frame out of this three-dimensional array. Each dimension will be a variabel (column) in the data.frame.
I know how this can be done in a very slow way using for loops, like this:
x <- rep(seq(from = 1, to = 30), 34)
y <- as.vector(sapply(1:34, function(x) {rep(x, 30)}))
month <- as.vector(sapply(1:12,
2009 Nov 30
2
command similar to colSums for rowSums?
Working with an NxMxO sized matrix, currently I can do this in my code:
if (max(colSums(array)) >= number)
But to get an equivalent result using rowSums, I have to do:
for (i in 1:10)
{
if (max(rowSums(array[,,i])) >= number)
}
I'm running both in a much larger loop that loops millions of times, so
speed and such is quite a big factor for me. Currently, the colSums line
uses about