Displaying 6 results from an estimated 6 matches for "yanlinlin82".
2009 Jun 03
2
FW: R.dll Reg.,
From: techzone2020@hotmail.com
To: r-help@stat.math.ethz.ch; r-help-request@stat.math.ethz.ch
Subject: R.dll Reg.,
Date: Wed, 3 Jun 2009 11:57:52 +0530
Sir,
I am working in R language currently.I want to link R.dll with VISUAL BASIC in order to create GUI FRONT END.But i couldnt link because of that file is copyrighted by "R Development Core Team 1995-2008".
Please
2009 Jun 03
2
FW: R.dll Reg.,
From: techzone2020@hotmail.com
To: r-help@stat.math.ethz.ch; r-help-request@stat.math.ethz.ch
Subject: R.dll Reg.,
Date: Wed, 3 Jun 2009 11:57:52 +0530
Sir,
I am working in R language currently.I want to link R.dll with VISUAL BASIC in order to create GUI FRONT END.But i couldnt link because of that file is copyrighted by "R Development Core Team 1995-2008".
Please
2009 May 27
3
Sort matrix by column 1 ascending then by column 2 decending
I've got a matrix with 2 columns and n rows. I need to sort it first
by the values in column 1 ascending. Then for values which are the
same in column 1, sort by column 2 decending. For example:
2 .5
1 .3
1 .5
3 .2
Goes to:
1 .5
1 .3
2 .5
3 .2
This is easy to do in spreadsheet programs but I can't seem to work
out how to do it in R and haven't been able to find a solution
anywhere.
2009 May 18
9
Concatenating two vectors into one
Dear users,
a very simple question:
Given two vectors x and y
x<-as.character(c("A","B","C","D","E","F"))
y<-as.factor(c("1","2","3","4","5","6"))
i want to combine them into a single vector z as A1, B2, C3 and so on.
z<-x*y is not working, i tried several others
2009 Jun 01
1
installing sn package
...Given an arbitrary data frame, it is easy to exclude a column given its index:
df[,-2]. How to do the same thing given the column name? A naive attempt
df[,-"name"] did not work :)
------------------------------
Message: 9
Date: Wed, 27 May 2009 18:51:07 +0800
From: Linlin Yan <yanlinlin82@gmail.com>
Subject: Re: [R] How to write a loop?
Cc: r-help@r-project.org
Message-ID:
<8d4c23b10905270351l5421787bv7a5affdc3d038a02@mail.gmail.com>
Content-Type: text/plain; charset=UTF-8
Why did you use different variable names rather than index of list/data.frame?
On Wed, May 27,...
2009 Sep 11
3
For sending my R package as part of R-project
..., nrow(y))
for (indice in 1:nrow(y)) {
id.match[indice] <- y[indice, x[indice]] } id.match
... works, but it's not that good solution (especially for big data.frame)
Thank you
------------------------------
Message: 93
Date: Fri, 11 Sep 2009 17:19:20 +0800
From: Linlin Yan <yanlinlin82 at gmail.com>
Subject: Re: [R] how to do this?
To: Luca Braglia <braglia at poleis.eu>
Cc: r-help at r-project.org
Message-ID:
<8d4c23b10909110219j20baf199r50f8ad90b667425d at mail.gmail.com>
Content-Type: text/plain; charset=UTF-8
Try this:
> y[matrix(c(seq_along(x), x),...