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2011 Dec 12
3
shorter way of coding
Dear R users,
I am using the code below to generate a fitted value of b. I have about 300 different values for for y (y1, y2, ...y300) which means I will have to write the code below 300 times to generate the 300 different fitted values for y. Is there a short way of doing that ?
Many thanks in advance
Mintewab
library(mgcv)
dat <- read.table("e:/minti's laptop/C/GBG/allround_survey/rainfallGPS.csv", header=T,...