search for: xvalues

...scaled against a new axis scale, thus the two plots are not directly comparable (I need the forecast points to be scaled according to the existing y axis). An example is pasted below. Any ideas on how to achieve this would be much appreciated. Thanking you in advance, George. # Sample dates >xValues = seq.Date(as.Date("1990-01-31"),to=as.Date("1992-12-31"),by="month"); # Sample y value > yValues<-NULL; > yValues[1:length(xValues)]=seq(0.1,length=length(xValues)) # Plot the series as a line > plot(xValues,yValues,type="l"); # Sample forecas...

Hi, I am new to R, and have a quick question regarding an R script that I received from a kind colleague. I am trying to determine the "peak" (maximum value) of the graph that is plotted when executing the following. There is an input file called "rates_values.txt" which begins as: rateValue 0.375693 0 1.71274 0 0 1.02832 0 0.16343 1.02349 0 0 1.47258 0.703522 0.390541

panel.lmline returns intercept and slope of y ~ x subsetted to the combination of conditioning factors given to xyplot in lattice. for instance: xyplot(Xvalues ~ log(Qvalues)|Tfac, data = df7, panel = panel.lmline) I am looking to find the equivalent formulation for lm() proper. If I do this: lmcal <- lm(Xvalues ~ log(Qvalues):Tfac, data = df7) Only one value of the intercept is returned. It appears as all the 'individual' intercepts are su...

Hi, I try to create a vertical line in my plot, which has a xaxis comprising time formated data. This is what I tried: ---------------- y<-152833 x<-strptime(y, format="%H%M%S") abline(v=x, col="red") ---------------- for some reason, it doesn't work and no error msg is displayed... I hope someone can tell me what I do wrong, or maybe an alternative. Thanks

Hi All, I try to do a scatterplot for a bunch of variables. I plot a dependent variable against a bunch of independent variables: -- cut -- graphics::plot( v01_r01 ~ v08_01_up11, data = dataset, xlab = "Dependent", ylab = "Independent #1" ) -- cut -- It is tedious to repeat the statement for all independent variables. Found an alternative, i.e. : -- cut -- mu

...s using barplot. testdata <- scan(, list(group=0,xbar=0,se=0)) 400 0.36038 0.02154 200 0.35927 0.02167 100 0.35925 0.02341 50 0.35712 0.01968 25 0.35396 0.01931 barplot(testdata$xbar, names.arg=as.character(testdata$group), main="a=4.0", xlab="Group", ylab="xbar") xvalues <- c(0.7, 1.9, 3.1, 4.3, 5.5) arrows(xvalues, testdata$xbar, xvalues, testdata$xbar+testdata$se, length= 0.4, angle=90, code=3) The best clue I have so far is Rtips #5.9: http://pj.freefaculty.org/R/Rtips.html#5.9 which is what I based my present solution off of. However, I do not understand...

...uot;A1:D1") r[["Value"]] <- c(1:4) ch <- ex$Charts() ch$Add() ac <- ex$ActiveChart() ac[["ChartType"]] <- xlXYScatterSmoothNoMarkers ac$Location(Where=xlLocationAsObject, Name="Tabelle1") ac$SeriesCollection()$NewSeries() ac$SeriesCollection(1)[["XValues"]] <- r ac$SeriesCollection(1)[["Values"]] <- r #------------------------------------------------------------------- But I don't perfer this way writing calculated values like "c(1:4)" to the Excel Sheet and calling them via "SeriesCollection". I'm...

I need to update a record in a table based on a event that occurs in the View. I believe the update action should occur in the controller. I think I need to call the controller action from the View and pass data that is stored in a Javascript variables as a parameter, but I am not sure how to do it. Can someone show me how I should be doing this? Below is a simplified version of the code I

Dear All, Does anyone know how to get the maximum/minimum value of a function using R, I think there should be an instruction, but i can not find it in help files Thank you in advance for your help :) [[alternative HTML version deleted]]

...half of it. If you reverse this process you get back to the "x-value", which is what the quantile function is doing. qnorm(0.5) Does this help for the last question? Code for superimposing the data: deg.of.free <- 4 hist(rt(n=500, df=deg.of.free), freq=FALSE, breaks=75, xlim=c(-5,5)) xvalues <- seq(from=-5, to=5, length=200) lines(x=xvalues, y=dt(xvalues, df=deg.of.free), col="blue", lwd=3) Finally, just two remarks: 1) Please use a sensible subject line in your message. 2) Is this some kind of homework assignment? (looks like a typical one) Ciao, Roland +++++ This m...

Dear all, I am using the following code to write the plot to an eps format postscript(file="test.eps",horizontal=FALSE)

...ements of type double, string etc but NOT objects (such as a matrix etc). This is not convenient for me in the following situation. I have a function that takes 2 inputs and returns a vector: testfun <- function (x,y) seq(x,y,1) I have a data.frame defined as follows: testframe<-data.frame(xvalues=c(2,3),yvalues=c(4,5)) I would like to apply testfun to every row of testframe and then create a new column in the data.frame which holds the returned vectors as objects. Why do I want this? Because the returned vectors are an intermediate step towards further calculations. It would be great to ke...

...orresponding the fitted model's sigma mu nu by agebins. Q: How do it generate these parameters as in L M S per Cole and Green 1992? Here are my working codes. Name of fitted model is gamlssfit > Agebin<-seq(6,36,6) >centmatx <-centiles.pred(gamlssfit,xname="agemos",xvalues=Agebin,cent=c(10,25,50,75,90)) Although I got matrix of the percentiles by agebins, I want to obtain the L M S/sigma mu nu corresponding to the same agebins. Any help here will be appreciated. Thanks, Y Addo -- View this message in context: http://r.789695.n4.nabble.com/GAMLSS-Question-tp3...

Hello, I'm very new to R, and have managed to plot xy graphs, but can't seem to plot a matrix properly. The first column is my time points, and the following columns 2-4 are the replicates of my experiment. I've tried using row.names=1 to make the first column the value for that row (whereas before I had 1-31 sequence) and then my 1st column) but I can't work out how to tell it

...) - 1) x_new <- cbind(V1Binario,V2Binario) x_new <- cbind(x_new,V3Binario) x_new <- cbind(x_new,V4Binario) x_new <- cbind(x_new,V5Binario) nam_ori <- colnames(x_new) col_nam <- paste("V", 1:ncol(x_new), sep = "") colnames(x_new) <- col_nam library(RSNNS) xValues <- x_new xTargets <- x[, 6] xTargetsDecoded <- decodeClassLabels(xTargets) x_nn <- splitForTrainingAndTest(xValues, xTargetsDecoded, ratio=0.15) set.seed(432) model <- mlp(x_nn$inputsTrain, x_nn$targetsTrain, size=3, learnFuncParams=c(0.1), maxit=10, inputs...

Suppose I create an R program called myTest.R with only one line like the following: type <- as.integer(readline("input type (1: type1; 2: type2)? ")) Then I'd like to run myTest.R in batch mode by constructing an input file called answers.R with the following: source("myTest.R") 1 When I ran the following at the terminal: R CMD BATCH answer.R output.Rout it failed

Estimados Les consulto por redes neuronales, hay diversos artículos como los siguientes (el último tienen un error actualmente). Pero mi pregunta va un poco por otro lado. http://www.r-bloggers.com/build-your-own-neural-network-classifier-in-r/ http://www.r-bloggers.com/classification-using-neural-net-in-r/ Básicamente se puede calcular un valor, por ejemplo doblar 2,4 grados a la derecha, luego 1

It''s been a few days since I posted my last two emails (of which, no one replied to) so I''ve gone ahead and coded a working slider class as well as a ''resizeable'' class that allows a user to drag and resize the element. I also linked these two together as I want to have slider behavior that can resize the resizeable element. The end result is both the

...ical analysis with R" (so maybe I'm not so off-topic after all), also unequivocal, e.g.: http://www.nbn.ac.za/Education/11-stats-2004/R1.8/r_workshop.pdf Example: Plotting functions Assume that you were to plot a function by hand. One possibility of doing it is to 1. Select some xvalues from the range to be plotted 2. Compute the corresponding y = f(x) values 3. Plot x against y 4. Add a (more or less) smooth line connecting the (x; y)points ... plot(x, y) # plots x against y (However, in R itself, "?plot" is discretely silent about what is "a...

On Thu, Jul 17, 2014 at 4:45 PM, Alp Toker <alp at nuanti.com> wrote: > > On 18/07/2014 02:21, David Blaikie wrote: >> >> Are people OK with/prefer the use of owning smart pointers in APIs? > > > I think smart pointers are great to use for storage, or as struct members > where there's actually a clear need for ownership. Just by virtue of getting > rid of