search for: xtb

I have created a function to do something: i <- factor(sample(c("A", "B", "C", NA), 793, rep=T, prob=c(8, 7, 5, 1))) k <- factor(sample(c("X", "Y", "Z", NA), 793, rep=T, prob=c(12, 7, 9, 1))) mytable <- function(x){ xtb <- x btx <- x # do more with x, not relevant here cat("The table has been created, see here:\n") print(xtb) list(table=xtb, elbat=btx) } tbl <- table(i, k) mytable(tbl) # (1) z <- mytable(tbl) # (2) str(z) # (3) (1) Wanted: outputs the string and the table prop...

...tor(rep(rep(c("Control","Treatment"),each=100),2)) mu <- rep(rep(1:2,each=100),2) response <- rnorm(400,mean=mu) xmpldata <- data.frame(time=time,treatment=treatment,response) mod <- lm(response~time*treatment,data=xmpldata) yhat <- fitted(mod) xtb <- with(xmpldata,xtabs(yhat ~ time+treatment)) print(xtb) > treatment > time Control Treatment > Post 94.10501 201.99112 > Pre 101.63792 210.04248 Is that (something like) what you want? cheers, Rolf Turner P.S. You said: "I usually use GUI software&...

...ot;,"Treatment"),each=100),2)) > mu <- rep(rep(1:2,each=100),2) > response <- rnorm(400,mean=mu) > xmpldata <- data.frame(time=time,treatment=treatment,response) > mod <- lm(response~time*treatment,data=xmpldata) > yhat <- fitted(mod) > xtb <- with(xmpldata,xtabs(yhat ~ time+treatment)) > > print(xtb) > > > treatment > > time Control Treatment > > Post 94.10501 201.99112 > > Pre 101.63792 210.04248 > > Is that (something like) what you want? > > cheers, > > Ro...

Dear Contributors, thanks for collaboration. I am trying to reorganize data frame, that looks like this: n1.Index Date PX_LAST n2.Index Date.1 PX_LAST.1 n3.Index Date.2 PX_LAST.2 1 NA 04/02/07 1.34 NA 04/02/07 1.36 NA 04/02/07 1.33 2 NA 04/09/07 1.34 NA 04/09/07

Hi, I do not want to make a plot, I try to make an output table in R, (in GUI like Stata this is trivially easy task) with regard to SO OP question. As I mentioned, in paper I would not do this, but out of curiosity I use R this time trying to create it. If in R this is trivial task as well, could you please show how to do it ? After googling a lot I did not find solution. regards, Jacek niedz.,

Hi, consider the following two dataframes: x1=c("232","3454","3455","342","13") x2=c("1","1","1","0","0") data1=data.frame(x1,x2) y1=c("232","232","3454","3454","3455","342","13","13","13","13")

...o do something: > > i <- factor(sample(c("A", "B", "C", NA), 793, rep=T, prob=c(8, 7, 5, > 1))) > k <- factor(sample(c("X", "Y", "Z", NA), 793, rep=T, prob=c(12, 7, 9, > 1))) > mytable <- function(x){ > xtb <- x > btx <- x > # do more with x, not relevant here > cat("The table has been created, see here:\n") > print(xtb) > list(table=xtb, elbat=btx) > } > tbl <- table(i, k) > mytable(tbl) # (1) > z <- mytable(tbl) # (2) > str(z) # (3)...

I have trouble finding definitive information about this. I am considering the use of SME 7.5.1 (centOS based) for my server needs, but I do want to use ZFS and I thus far I have only found information about the ZFS-Fuse implementation and unclear hints that there is another way. Phoronix reported that http://kqinfotech.com/ would release some form of ZFS for the kernel but I have found nothing.

Dear all, I'm looking for primary help at aggregating table() results and at writing a loop (if useful) My dataset ( http://goo.gl/gEPKW ) is composed of 23k rows, each one representing a point in the space of which we know the land cover over 10 years (column y01 to y10). I need to analyse it with a temporal sliding window of 5 years (y01 to y05, y02 to y06 and so forth) For each period