search for: xmlelementsbytagnam

...long character array (>500k characters) that need to split by '\n' resulting in an array of about 60k numbers. The help on strsplit says to use perl=TRUE to get better formance, but still it takes several minutes to split this string. The massive string is the return value of a call to xmlElementsByTagName from the XML library and looks like this: ... 12345 564376 5674 6356656 5666 ... I've to read about a hundred of these files and was wondering whether there's a more efficient way to turn this string into an array of numerics. Any ideas? thanks a lot for your help and kind regards,...

...arsing the xml tree; -vectorizing the parsing (i.e., replacing loops like "for(node in group.of.nodes) {...}" by "sapply(group.of.node, function(node){...}") I gained another 5 seconds by making small changes to the functions used (like replacing 'getNodeset' by 'xmlElementsByTagName' when I don't need to navigate to the children nodes). Now I am blocked at around 35 seconds and I would still like to cut this time by a 5x, but I have no clue what to do to achieve this gain. I'll try to expose as briefly as possible the relevant structure of the xml file I am parsin...

Dear, I want to read XML documents, add child nodes to some elements and store everything back as an XML document. I've tryed the following: doc <- xmlTreeParse("file.xml") QTListNode<-xmlElementsByTagName(xmlRoot(doc)[[1]],"tagname") append.xmlNode(QTListNode[[1]],newXMLNode(name ="Norm", attrs = NULL)) saveXML(doc, file = "out.xml", compression = 0, indent=T) This doesn't seem to work. Can anyone help? Thanks, Steffen

Dear All, I have a question regarding best practise in setting up a XML parser within R. Because I have files with more than 100 MB and I'm only interested in some values I think a SAX-like parser using xmlEventParse() will be the best solution. Unfortunately the values I'm looking for, to construct some higher "mass spectrum", are distributed over different lines: as