Displaying 1 result from an estimated 1 matches for "xcomb".
Did you mean:
comb
2006 Dec 13
1
combinations of m objects into r groups
...quot;,"0110","0101","0011")
m<-length(r)
for (k in 1:trunc(m/2)){
a <- subsets(k, m)
for (i in 1:dim(a)[1]){
sub <- rep(2, m)
b <- a[i,]
for (j in 1:length(b)){
sub[b[j]]=1
}
r <- data.frame(r, sub)
}
}
names <- c("xcomb")
for (i in 1:(dim(r)[2]-1)) {
names <- c(names,paste("c",i,sep=""))
}
names(r) <- names
Any suggestions?
Thanks, Maria
After searching for help I found a