Displaying 3 results from an estimated 3 matches for "x1x3".
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x13
2004 Apr 05
0
Selecting Best Regression Equation : leaps() in R and stepwise() in S+
...-----------------------------
> options(prompt=" R > " )
R > leafbrn1<-read.table("c:\\leafbrn.txt",header=T)
R > leafbrn.data1<-data.frame(leafbrn1)
R > attach(leafbrn.data1)
R > x1sq<-x1^2;x2sq<-x2^2;x3sq<-x3^2;x1x2<-x1*x2;x1x3<-x1*x3;x2x3<-x2*x3;
R > leafbrn <- cbind(leafbrn1,x1sq,x2sq,x3sq,x1x2,x1x3,x2x3)
R > detach(leafbrn.data1)
R > leafbrn.data<-data.frame(leafbrn)
R > attach(leafbrn.data)
R > X<-cbind(x1,x2,x3,x1sq,x2sq,x3sq,x1x2,x1x3,x2x3)
R > Y<-y
-------...
2010 Mar 26
2
R loop help
Hi,
I am tring to write a loop to compute this,
==========================
x1=c(
rep(-1,4),
rep(1,4)
)
x2=c(
rep(c(-1,-1,1,1),2)
)
x3=c(
rep(c(-1,1),4)
)
x1*x2
x1*x3
x2*x3
========================
suppose i have x1,x2,x3
i want to compute their ' two factor interactions', x1x2,x1x3 and x2x3,
I wrote
========================
for(i in 1:2){
for( j in i+1:3){
xij=c()
xij=xi*xj
}
}
========================
it did not seem to recognize xi and xj
is there any suggestion?
it would be wonderful if there exists a single command that i can use
My ultimate aim is to find the 55 x...
2012 Sep 12
3
how to create a substraction matrix (subtract a row of every column from the same row in other columns)
...er represents
a year, and I want each comparison to only be listed once, the difference
between the 1st year the sample was taken and then 2nd year the sample was
taken. (This would probably entail just taking a portion of the matrix.) .
This is what the result would be
difftype value
x1x2
x1x3
x1x4
x1x5
x2x3
x2x4
x2x5
x3x4
x3x5
x4x5
Thank you for any help you can give me.
--
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