search for: women

I got bitten recently by the following behaviour of detach(); > save(file="Junk") > attach("Junk") > search() [1] ".GlobalEnv" "file:Junk" "package:methods" "package:ctest" [5] "package:mva" "package:modreg" "package:nls" "package:ts" [9]

...************************************ mlogl <- function(mu, y, X) { n <- nrow(X) zeta <- X%*%mu llik <- 0 for (i in 1:n) { if (y[i]==1) llik <- llik + log(pnorm(zeta[i,], mean=0, sd=1)) else llik <- llik + log(1-pnorm(zeta[i,], mean=0, sd=1)) } return(-llik) } women <- read.table("~/R/Examples/Women13.txt", header=TRUE) # DATA # THE DATA SET CAN BE ACCESSED HERE # women <- read.table("http://wps.aw.com/wps/media/objects/2228/2281678/Data_Sets/ASCII/Women13.txt", header=TRUE) # I HAVE CHANGED THE NAMES OF THE VARIABLES # J is changed...

...ture (actually, I'm looking to sync *only the files* to the new destination directory). The source files are all subfolders under /backup/Music: ./Adrian Legg/Mrs. Crowe's Blue Waltz/Paddy Goes To Nashville.mp3 ./Adrian Legg/Mrs. Crowe's Blue Waltz/Sour Grapes.mp3 ./Adrian Legg/Wine, Women & Waltz/Divorcee's Waltz.mp3 ./Adrian Legg/Wine, Women & Waltz/Mrs. Crowe's Blue Waltz.mp3 ./Adrian Legg/Wine, Women & Waltz/Nora Handley's Waltz.mp3 ./Adrian Legg/Wine, Women & Waltz/Queenie's Waltz.mp3 ./Adrian Legg/Wine, Women & Waltz/Silent Night.mp3 ./Adrian...

...contributors. Type "?contributors" for a list. Type "demo()" for some demos, "help()" for on-line help, or "help.start()" for a HTML browser interface to help. Type "q()" to quit R. [Previously saved workspace restored] > data(women) > names(women) [1] "height" "weight" > summary(lm(weight ~ height, data = women)) Call: lm(formula = weight ~ height, data = women) Residuals: Min 1Q Median 3Q Max -1.7333 -1.1333 -0.3833 0.7417 3.1167 Coefficients: Error: binary operator applied...

Hello, In the following I tried 3 versions of an example in R help. Only the two first predict command work. After : library(splines) require(stats) 1) fm1 <- lm(weight ~ bs(height, df = 5), data = women) ht1 <- seq(57, 73, len = 200) ph1 <- predict(fm1, data.frame(height=ht1)) # OK plot(women, xlab = "Height (in)", ylab = "Weight (lb)") lines(ht1, ph1) 2) height <- women$height # 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 weight <- women$weight #...

I am wanting to use the "[" operator in an S-chunk, e.g. <<>>= str(women) women$height women[,1] "["(women,1) @ to show the equivalence of three methods of extracting an element from a data.frame. However Sweave returns the last of these as women[1] in the S input chunk How can I force it not to do this and return "["(women,1)

Hello there, I have two groups (men and women) and I know per group how many of them smoke or don't smoke (women 40 of 200; men 100 of 300). I would like to know how I can compare in R if men and women differ significantly in their smoking. However, because there are more men in the sample than women I cannot just compare the number of sm...

...the source of the error is the same.) The problem is technical and concerns the design of poly(), which is why I'm sending this message to r-devel rather than r-help. To illustrate: ------------ snip ------------- > mod.pres <- lm(prestige ~ log(income, 10) + poly(education, 3) + poly(women, 2), + data=Prestige) # Prestige data from car package > predict(mod.pres, newdata=data.frame(education=10, income=6000, women=30)) # works 1 39.66414 > model.frame(delete.response(terms(mod.pres)), data.frame(education=10, income=6000, women=30)) log(income, 10)...

...n the application: http://one.textdrive.com/pipermail/rails/2005-January/001536.html So here''s my situation. I have a table called "divisions" with a column named "format". It''s a varchar, but only the following values are valid: ["open", "womens", "coed"]. Naturally, I want to have an HTML select element on the edit page that contains the valid values, and is set to the current value. It seems like FormOptionsHelper#select should do exactly what I want, so I tried this: <%= select("division", "form...

Hello Group, I am having trouble with the sqldf package on unix. The same code works fine on windows. Silly Example script: # Load the package library(sqldf) # Use the titanic data set data(women) colnames(women) head(women) sqldf('select height, count(*) from women where height is not null group by weight') Unix Output and error: bash-3.00$ R --vanilla <testR.R R version 2.10.1 (2009-12-14) Copyright (C) 2009 The R Foundation for Statistical Computing ISBN 3-900051-07-0 R i...

Dear all, I have 1980~1990 eleven datas, every year have three variables, wage gender(1=female, 2=male) race(1=black, 2=white) My original commands is: fig2b<-reldist(y=mu1990$wage,yo=mu1980$wage,.......) I have three questions: 1. If I want to appoint y=women's wage in 1990 yo=women's wage in 1980 2. If I want to appoint y=women's wage in 1990 yo=men's wage in 1990 3. If I want to appoint y=black women's wage in 1990 yo=white w...

We still have some tickets available for the Women in Compilers and Tools reception that is held the night before the 2018 Euro LLVM Developers’ Meeting in Bristol, UK. Tickets are available here. https://www.eventbrite.com/e/2018-european-llvm-developers-meeting-women-in-compilers-and-tools-reception-tickets-42287427835 This is an evening recept...

...st shot at classifying the names given in the email header as male/female, but ended with a fair number of unknowns. This dataset had 2797 list messages, in 895 questions. 1501 messages were replies to one of those questions by someone not the original querent. Across all messages, 6.5% were from women, 77.8% from men, 15.7% unknown. For new questions, 11.7% were from women, 61.2% from men, 27.0% unknown. Among responses to other people's questions, 2.6% were from women, 92.3% from men, 5.1% unknown. Nine women answered other people's questions, but only two were what I'd consider...

...n hope ... I have data for continuous variables (measures of residents) by a categorical variable in range (1,22), the units in which they live. I want to plot these data with a pair of boxplots one above another with same x-axis (1,22) using par(mfrow=c(2,1)) and then plotting first for the women then for the men. My problem is that some units have only men, some have only women, and some have both. I'd like both plots to have the same x axis and the notched, varwidth boxplots to locate themselves with some gaps so that the units are in the same place on the x axis on each plot....

...labels=TRUE) When I try to import the file, the value labels are not assigned to the rows. This is what I get. ID GENDER 1 1 1 2 2 2 3 3 1 4 4 2 5 5 1 6 6 1 7 7 1 8 8 2 9 9 2 10 10 1 11 11 3 In the .sav file, 1 = Men 2 = Women 3 = user assigned missing. The variable values are attached as a value.labels attribute. If I remove row # 11 (gender = 3), I can import the file as I expect. ID GENDER 1 1 Men 2 2 Women 3 3 Men 4 4 Women 5 5 Men 6 6 Men 7 7 Men 8 8 Women...

...ardless of what kind CoC you have: if it comes to having to enforce it, the community has stopped being open and welcoming. So I think this approach is attacking the problem that you have after you already lost. > After observing what is happening in many other communities in > regards to women in technology, I would be much more likely to > participate in a community that actually has a well thought out and > meaningful code of conduct. First, let me state that I'm fully aware that women are subject to harrassment. It's one of those sad facts in life. Still, I don't...

Is there an easy way to make graphs for the following data. I have pretest and posttest scores for men and women. I would like to form a 'titlted segment' plot for the data. That is, make segments joining the scores, with different types of segments for men and women. Example data: menpre <- c(43,42,26,39,60,60,46) menpost <- c(40,41,36,42,54,58,43) womenpre <- c(46,56,81,56,70,70) womenpo...

Dear users of metafor, I am working on a meta-analysis using the metafor package. I have a excel csv database that I am working with. I am interested in pooling the effect measures for a particular subgroup (European women) in this csv database. I am conducting both sub-group and meta-regression. In subgroup-analyses, I have stratified the database to create a separate csv file just for European women from the original database and conducted the following: women_west<-read.csv("women_west.csv") print(w...

...----------------------------------------- I'm new to R, so perhaps I'm missing something that could be explained to me. If it is decided not to change R's behavior, then at the least I suggest that the example given by help(attach) be extended by appending the following: attach(women) women$height <- height*2.54 ## Don't try to do this either, as it ## will still create a new variable "height" with the original ## values of women$height. I.e., height no longer points to the ## present value of women$height: sd(women$height-height)...

...interested in locating a script to implement a sampling scheme that would basically make it more likely that a particular observation is chosen based on a weight associated with the observation. I am trying to select a sample of ~30 census blocks from each ZIP code area based on the proportion of women in a ZCTA living in a particular block. I want to make it more likely that a block will be chosen if the proportion of women in a patient's age group in a particular block is high. Any ideas are appreciated!