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The subject says it all. Is it possible, code wise, configuration wise, at all - to reverse the order in which the available zap channels are used for *outgoing* calls? Code wise, I looked at the channel structure and it appears as though there is only a next pointer, not a previous pointer, so to 'easily' to this in the code would require a change to the code that reads in zapata.conf?

Hello R-list, How can I row wise solve a function for which the input variables are written in a matrix or a vector and have the calculated output added to the matrix or written in a vector? To specify my case in particular I continue: I would like R to calculate for me a value for ‘t’ which is function of input parameters A and B, which are comprised in a matrix called ‘ddt’ and some other

Dear Fellows, How can I do to proced a step wise regression in R, if it´s possible ? Thanks, Walmir __________________________________________________________________________ Acabe com aquelas janelinhas que pulam na sua tela. AntiPop-up UOL - É grátis! http://antipopup.uol.com.br/ [[alternative HTML version deleted]]

Hello all, I am trying to run a two sample t-test on a matrix which is a 196002*22 matrix. I want to run the t-test, row-wise, with the first 11 columns being a part of the first group and columns 12-22 being a part of the second group. I tried running something like (temp.matrix being my 196002*22 matrix) t.test(temp.matrix[,1:11],temp.matrix[,12:22],paired=TRUE) or somthing like

I'm trying to calculate the row-wise kronecker product A \Box B of two sparse matrices A and B, and am struggling to find a quick way to do this that takes advantage of sparseness. I thought a good idea would be to use "rep" to construct 2 matrices of the same dimension of the end product, and multiply these two together: library(Matrix) A<-Matrix(c(1,0,0,0,0,1,2,0), 2, 4)

Hello, Apologies if this question has already arised, hope you can help me to the find the solution to this or point the place to look at. I have a multidimensional piece-wise regression linear problem, i.e. to find not only the regression coefficients for each "interval" but also the beginning and ends of the intervals. To simplify it to the one dimensional case and two intervals,

I want to try to get a result of element wise addition between a vector and a list. It can be done with "for statement." In order to reducing computing time, I have tried to avoid "for state." If anybody give me an idea, I would apprecite it much. for example, with a & b as below lines, a<- list(c(1,3),c(1,2),c(2,3)) b<-c(10,20,30) I would like to have a list (like

Dear R fans, I am trying to do step-wise linear regression using the F-test to decide which variables to admit. Ewout Steyerberg suggests using the F-test for this purpose. I first build a model using no variables using lm(y ~ 1) and then using one variable that is a strong predictor using lm(y ~ x). When I call var.test on these two models, I do not get a significant p-value—0.07. But a

Dear R helpers I have a data which gives Month-wise and Rating-wise Rates. So the input file is something like month           rating           rate January        AAA             9.04 February      AAA             9.07 .......................................... .......................................... Decemeber     AAA            8.97  January           BBB           11.15 February        

How do I do group wise clustering in R? Hi all, I have N x K data matrix, where N is the number of observations, K is the number of variables. The N observations fall into M categories or groups. Now I want to cluster the groups, instead of the observations, how do I do that? i.e. the clustering would be at the group level... Thanks a lot for your help! [[alternative HTML version deleted]]

Dear R-users, i have a simple problem maybe, but i don't see the solution. i want to find the entry-wise closest element of an vector compared with another. ind1<-c(1,4,10) ind2<-c(3,5,11) for (i in length(ind2):1) { print(which.min(abs(ind1-ind2[i]))) } for ind2[3] it should be ind1[3] 10, for ind2[2] it should be ind1[2] 4 and for ind2[1] it should be ind1[1] 1. but with the

Hi, I am looking for a one-liner code for the following situation say I have a vector r of 0 and 1's, and another vector v of equal length. I want to assign v[i]-1 to v[i] if r[i]=1, for all i. How would I do that using mapply or any other batch processing keywords? thanks. John -- View this message in context:

Hi, Here i have an matrix like this, ABC PQR XYZ MNO ------ ------- ------ -------- 3 6 7 15 2 12 24 15 20 5 1 2 25 50 15 35 i need to get the "MODE" - for each column-wise "VARIANCE" - for

Has anyone seen this? When we print using Samba, the printjob stays in the queue after prints Also in the LPD.conf is set to : save_when_done@ done_jobs=0 done_jobs_max_age=1 We're using Redhat 7.3. Samba 2.2.4-1 Any help would great, Gene Wise

Hi I have a large credit portfolio (exceeding 50000 borrowers). For particular process I need to add up the exposures based on the bands. I am giving a small test data below. rating <- c("A", "AAA", "A", "BBB","AA","A","BB", "BBB", "AA", "AA", "AA", "A", "A",

Dear R helpers, Thanks a lot for your earlier guidance esp. Mr Davind Winsemius Sir. However, there seems to be mis-communication from my end corresponding to my requirement. As I had mentioned in my earlier mail, I am dealing with a very large database of borrowers and I had given a part of it in my earlier mail as given below. For a given rating say "A", I needed to have the bad-wise

Hi all, I want to calculate the row wise mean of groups of columns in a matrix M. All columns belonging to the same group have the same column name. My idea is to create a new vector V containing these column names, but after first removing the duplicates. Then I would calculate the means using for instance rowMean() and by comparing the column names of M with the vector V, getting the indices

dear list, is there any function in R with which i can compute subject-wise means for a single factor level? for instance, i wanna have the mean for each subject for the first level of factor A, how can i get that? is there a straightforward way to solve this problem? kind regards jake [[alternative HTML version deleted]]

Hi, I like my recordings to go to date wise folder i mean to say that for example today is 20070409 so all recordings should go directly to that folder instead of one folder for whole month. and then next day's recordings should go to next date folder. so how can i do that my current monitor context is like... exten => _1NXXNXXXXXX,3,Monitor(gsm,/rec/asterisk/apr07/${CALLFILENAME},mb)

Windows Vista R 2.10 - I know it is old, I will update later today. How might I perform a piece-wise linear regression where two linear segments are separated by a single knot? In addition to estimating the slopes of the two segments (or the slope in one segment and the difference between the slope of the first and second segment), I would like the analysis to select the optimum knot. My first