Displaying 5 results from an estimated 5 matches for "wheat1".
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2003 Aug 06
0
Intermittant IAX Call Failures
...preciated. If more
information is needed to analyze this effectively, please let me know
what you need. Thanks!
Sincerely,
Matthew Farley
------------------------------------------------------------------
My iax.conf entry: (my ip is 208.222.40.227)
register => username:****@216.234.116.177
[wheat1]
type=friend
username=wheat1
password=*****
host=216.234.116.177
auth=plaintext
context=default
----------------------------------------------------------------------
The iax.conf entry at the other end is: (its IP is 216.234.116.177)
[wheat1]
type=friend
host=dynamic
context=wheat1
username=whe...
2013 May 03
1
A problem of splitting the right screen in 3 or more independent vertical boxes:
...e vertical parts
where each pair of the same type of plant, are together in its own block
of boxplot, because each plant has its own unit of measure.
Let's say wheat is measured in ton, tomato in pound and cucumbers as
counts. :-)
x<-rnorm(1000,mean=0,sd=1,main="Right screen")
wheat1<-rnorm(100,mean=0,sd=1)
wheat2<-rnorm(150,mean=0,sd=2)
tomatos3<-rnorm(200,mean=0,sd=3)
tomatos4<-rnorm(250,mean=0,sd=4)
cucumbers5<-rnorm(300,mean=0,sd=5)
cucumbers6<-rnorm(400,mean=0,sd=6)
par(mfrow=c(1,2))
hist(x, main="Left screen OK")
boxplot(wheat1,wheat2,tomatos...
2007 Jul 25
1
how to use "replace" for efficiency
...ncludes "NA"
The dataset is called wheat2
I use the following:
for (i in 1:nrow(wheat2)) {
# Insert NA's if runoff data > rainfall data
if (is.na(wheat2[i,5:7])==FALSE && any(wheat2[i,5:7]>wheat2[i,8])) {
wheat2[i,5:7] <- NA
}
}
I tried this:
wheat1 <- replace(wheat2[,5:7],is.na(wheat2[i,5:7])==FALSE &&
any(wheat2[i,5:7]>wheat2[i,8]),NA)
wheat3 <- cbind(wheat2[1:4],wheat1,wheat2[,8])
> wheat3[5539,] # the culprit row
DateRain Rain StartDate EndDate RO.A RO.B RO.C filtered.Rain
5539 28-Feb-58 0 27-Feb-58 28-F...
2000 Mar 29
1
A "stack" function
...8 6.1 7.5 5.9 5.6
$ Maize : num 5.8 4.7 6.4 4.9 6 5.2
$ Oats : num 8.3 6.1 7.8 7 5.5 7.2
> stack <- function(data)
+ data.frame(values = unlist(data),
+ lev = factor(rep(names(data), lapply(data, length))))
> stack(ex10.09) # try it on the example
values lev
Wheat1 5.2 Wheat
Wheat2 4.5 Wheat
Wheat3 6.0 Wheat
Wheat4 6.1 Wheat
Wheat5 6.7 Wheat
Wheat6 5.8 Wheat
Barley1 6.5 Barley
Barley2 8.0 Barley
Barley3 6.1 Barley
Barley4 7.5 Barley
Barley5 5.9 Barley
Barley6 5.6 Barley
Maize1 5.8 Maize
Maize2 4.7 Maiz...
2000 Feb 29
0
mapping of colornames into hsv: half way done
..."violetred", "#D02090",
"violetred1", "#FF3E96",
"violetred2", "#EE3A8C",
"violetred3", "#CD3278",
"violetred4", "#8B2252",
"wheat", "#F5DEB3",
"wheat1", "#FFE7BA",
"wheat2", "#EED8AE",
"wheat3", "#CDBA96",
"wheat4", "#8B7E66",
"whitesmoke", "#F5F5F5",
"yellow", "#FFFF00",
"yellow1", "#FFFF...