search for: weylandt

http://www.cs.purdue.edu/homes/jv/pubs/ecoop12.pdf A new paper out on R the language -- I'm not all the way through it but it's been an interesting read so far. Thought it might be of interest to the list. Michael Weylandt [[alternative HTML version deleted]]

Hi, I need to run a PCoA (PCO) for a data set wich has both positive and negative values for variables. I  could not find any distancecoefficient other than euclidean distace running for the data set. Are there any other coefficient works with negtive values.Also I cannot get summary out put (the eigen values) for PCO as for PCA.   Thanks. Dilshan [[alternative HTML version deleted]]

Hello everyone, I have a graph and a segment parallel to the x axis at y=-10, x=0, and bars on it. Now the question is, Is there a way to leave the segment there but let the graph axis start from the origin? In this way the segment will be out of the graph Thanks [[alternative HTML version deleted]]

Hi, I am trying to select the first row of a variable with data in long-format, e.g., # sample data id <- c(1,1,1,2,2) value <- c(5,6,7,4,5) dat <- data.frame(id, value) dat How can I select/subset the first 'value' for each unique 'id'? Thanks, AC [[alternative HTML version deleted]]

Hi, I have a question about a special recursive filter problem. What I have: - given variables: x: time series with rather randomly occuring '0' and '1' wait: non negative integer - a working but ineffectiv implementation (see below) How the implementation works (what I want): The filter should drill holes of distance 'wait' between the '1' in x, e.g. x =

can anybody tell me how i can draw x- y- axis and draw x^3 graph using R graph?? i need nice coordinate system with legends and coordinate numberings.. and nice graph of x^3 on it.. it will be nice if you tell me how i can center the graph.. i want the origin (0,0) to be right in the middle of the graph. thank you so much.

Hi, suppose that we have a triangular upper matrix A test <- matrix(ncol = 4, nrow = 4) test[1, ] <- c(NA,1,1,1) test[2, ] <- c(NA,NA,1,1) test[3, ] <- c(NA,NA,NA,1) test[4, ] <- c(NA,NA,NA,NA) I know how quickly set diagonal value diag(test) <- 1. But how quickly set down value i.e. matrix is symmetrical? Is there in r project any quickly function? Thanks, Best Marcin

Hi everyone, I've got a question concerning the function Box.test for testing autocorrelation in my data. My data consist of (daily) returns of several stocks over time (first row=time, all other rows=stock returns). I intend to perform a Box-Ljung test for my returns (for each stock). Since I have about 3000 stocks in my list, I'm not able to perform the test individually for each

Dear All, I am having a very basic error, but somehow do not know how to resolve it. I've read a dataset in .csv into R with two columns - sector, export. When trying to plot the data it says "sector not found" This is the formula. SouthAfrica<-read.csv(c,header=T) > hist(sector$exports,xlab="exports (MtCO2)",main="CO2 Exports") Error in

Hi guys, I am trying to replace all elements of earth that are equal to zero with their corresponding elements in mars. I can do the replace with a bunch of for-loops, but I don't think this is the R way of doing things. my_list <- list( earth=array(c(0,0,45,0,0,45,0,45),dim=c(2,2,2)), mars=array(c(8:1),dim=c(2,2,2))) my_list for (i in c(1:2)) { for (j in c(1:2)) {

Hello, I have a 32 GB RAM Mac Pro with a 2*2.4 GHz quad core processor and 2TB storage. Despite this having so much memory, I am not able to get R to utilize much more than 3 GBs. Some of my scripts take hours to run but I would think they would be much faster if more memory is utilized. How do I optimize the memory usage on R by my Mac Pro? Thank you! Kurinji [[alternative HTML version

Hi, I would like to produce a plot with a symbol on every nth point in a time series data, like the one in the following: http://www.phon.ucl.ac.uk/home/yi/ProsodyPro/EnglishFocus.png x <- seq(-100,1000,25) plot(x,type="l") Could someone help me out with the above example? Thanks.... [[alternative HTML version deleted]]

...?any [1] to be "Are any values true?" rather than "are some" It'd be more consistent with the function name and with ?all, as well as reading more precisely (to my ear at least) Anyway, of no consequence whatsoever, just noticed it when looking something else up. Michael Weylandt [1] http://stat.ethz.ch/R-manual/R-devel/library/base/html/any.html

Hi All, I installed qcc package and the dependency packages. For the first time I can use the function : process.capability.sixpack(). But later when ran the code again I always got the following error: Error: could not find function "process.capability.sixpack". I tried reinstalling the qcc package but didn't help. Does anyone have this kind of experience? Thank you! Regards, Yan

Hi R-helpers I want a function that performs the opposite of lag() with panel data. I have transformed my data before with pdata.frame(mydata, index=c("groupindex", “timeindex")) And then I’ve done lag(mydata, -1) but it doesn’t work. The error message was: Error in rep(1, ak) : invalid ''times'' argument Thank you in advance, Cecília Carmo

Dear Mr/Mrs I need to generate a random data only with (0.23, 0.56, 0.45, 0.85, 0.7) with known mean, SD, correlation length, in a matrix 50*50. I know R coeds but in this case, I could not find to generate only with finite numbers that I have. Please guide me . Best Regards Nooshin [[alternative HTML version deleted]]

Hello, I'm having some issues getting a ggplot figure to show up in the knitr output, when placed in a loop. Specifically, I have a loop inside a knitr chunk : ```{r fitting, warning=FALSE, fig.width=10, fig.height=10, fig.keep='high'} for (t in 1:T) { # do a regression of tgt.vals ~ predictors and compute coeffs and fitted values (fit.vals / fit.adj.vals) plot(

Dear all,  I have a formula of the form y=ax+b I know everything except b. How I can ask R to do fitting to find only the value of b? I already know the lm() but it always return both an intercept point (b) and the a. What should I do ? I would like to thank you in advance for your help B.R Alex [[alternative HTML version deleted]]

Hi I am trying to create n functions where each function is defined in function one step before, i.e. something like ff.k(x) = ff.j(x) - sum(1:j), for j=k-1 Is it possible? If it isn't and I manually create each function then is their a way to call them through a loop? My objective is to calculate something like result.k = ff.k(x1)/ff.k(x2) for k in 2:n Thank you for your time,

Dear All, I have a bunch of data points as follows: x  100 y  200 z  300 ... where 100, 200, 300 are the values. I would like to know the distribution of my data? how can I fit my data into a distribution? Thanks a lot, Andra [[alternative HTML version deleted]]