search for: watermelon

Displaying 12 results from an estimated 12 matches for "watermelon".

2004 Jun 24
0
Ptruvfcc H_y_d_r_0_c_0_d_0_n_e, pain medicati0n available
...the man got back to his own country, the customs officers would not believe his story. They said, 'You sold your new car while you were abroad and bought this old one!' It was only when the man showed them the letter from the circus man that they believed him. There was a farmer who raised watermelons. He was doing pretty well but he was disturbed by some local kids who would sneak into his watermelon patch at night and eat his watermelons. After some careful thought he comes up with a clever idea that he thinks will scare the kids away for sure. So he makes up a sign and posts it in the field....
2004 Oct 18
3
答复: R plot problems
Thank you for your help! I gave you an example, you could run it in R . Maybe you will understand my meaning clearly. x <- data.frame(main.name="AAA", x.name=rep(c("Apply","Watermelon","Lemon","Banana", "Grape","Pineapply","Cherry","Peach","Orange","Mango","Strawberry"),each=5), y.name=(1:55)) plot(x$x.name, x$y.name) I can't find you said package ,whick library should I include...
2008 Sep 26
1
Using functions that contain sums
Hello, I'm trying to perform an integration on a function that contains a sum. Similarly I'm hoping whatever acts as a fix will be good enough to aid in a 2nd case as well but I've already put in a work-around for that situation. My code example is here: watermelon=c(0,1,2,3) w<-function(x){ sum(sin(x-watermelon))} integrate(function(x){w(x)},0,2) integrate(function(x){sin(x)+sin(x-1)+sin(x-2)+sin(x-3)},0,2) the first integral gives an error... the 2nd is what I should get for an answer for the first. Is there a way to get this to work the way that I...
2004 Oct 18
2
答复: 答复: R plot problems
...; Testing Semiconductor Manufactory International(ShangHai) Corporation #18 ZhangJiang Road, PuDong New Area, Shanghai, China Tel: 021-5080-2000 *11754 Email: Ivy_Li at smics.com -----orig--- Hi Ivy, How about x <- data.frame(main.name="AAA", x.name=rep(c("Apply","Watermelon","Lemon","Banana", "Grape","Pineapply","Cherry","Peach","Orange","Mango","Strawberry"),each=5), y.name=(1:55)) par(las=2); plot(x$x.name, x$y.name) Bobby On Mon, 18 Oct 2004 09:36:12 +080...
2010 May 07
1
"Contact header appears incorrect on this invite" Asterisk registering with another PBX
In an attempt to connect our Asterisk 1.6 phone system with another phone system called "Broadsmart", they gave me credentials to register to. Connected to Asterisk 1.6.2.5 currently running on watermelon (pid = 10365) watermelon*CLI> sip show registry Host dnsmgr Username Refresh State Reg.Time {broadsmart_ip}:5060 N {broadsmart_user} 3317 Registered Fri, 07 May 2010 11:21:41 1 SIP registrations. It shows that I a...
2004 Oct 18
1
How to draw x-axis time label.
...:15:27", "2004-08-11 21:38:24", "2004-08-12 14:28:41", "2004-08-18 18:04:47", "2004-08-13 15:23:14", "2004-08-14 02:36:33") Time <- as.POSIXlt(Time) x <- data.frame(main.name="AAA", fruit.name=rep(c("Apply","Watermelon"),each=5), x.name=Time, y.name=(1:10)) plot(as.numeric(x$x.name),as.character(x$y.name),pch=26,) fruit.class <- table(x$fruit.name) color.code <- c(611,552,656,121,451,481,28,652,32,550,90,401,150,12,520,8) for(j in 1:length(fruit.class)) { fruit <- names(fruit.class)[j] lines(sm...
2004 Oct 18
2
答复: How to draw x-axis time label.
...8-11 21:38:24", > "2004-08-12 14:28:41", "2004-08-18 18:04:47", > "2004-08-13 15:23:14", "2004-08-14 02:36:33") > Time <- as.POSIXlt(Time) > x <- data.frame(main.name="AAA", > fruit.name=rep(c("Apply","Watermelon"),each=5), > x.name=Time, y.name=(1:10)) > plot(as.numeric(x$x.name),as.character(x$y.name),pch=26,) > fruit.class <- table(x$fruit.name) > color.code <- > c(611,552,656,121,451,481,28,652,32,550,90,401,150,12,520,8) > for(j in 1:length(fruit.class)) > { > fru...
2006 Apr 14
0
Gruff on Windows
...reference code in question: require ''RMagick'' require ''gruff'' g = Gruff::Line.new g.title = "My Graph" g.data("Apples", [1, 2, 3, 4, 4, 3]) g.data("Oranges", [4, 8, 7, 9, 8, 9]) g.data("Watermelon", [2, 3, 1, 5, 6, 8]) g.data("Peaches", [9, 9, 10, 8, 7, 9]) g.labels = {0 => ''2003'', 2 => ''2004'', 4 => ''2005''} send_data(g.to_blob, :disposition => ''inline'',...
2007 Feb 28
1
hi guys problem with running gruff
...per. first i got two errors when i used this example #!/usr/bin/ruby require ''rubygems'' require ''gruff'' g = Gruff::Line.new g.title = "My Graph" g.data("Apples", [1, 2, 3, 4, 4, 3]) g.data("Oranges", [4, 8, 7, 9, 8, 9]) g.data("Watermelon", [2, 3, 1, 5, 6, 8]) g.data("Peaches", [9, 9, 10, 8, 7, 9]) g.labels = {0 => ''2003'', 2 => ''2004'', 4 => ''2005''} g.write(''my_fruity_graph.png'') when i replaced require ''gruff'' with requ...
2007 Jun 19
0
toilet
...simple tips we can disguise the fact that our hair is being lost just like that! It is possible to tow your own car in a pinch but definitely not recommended, especially if you are going far or fast. Edited by webBikeWorld. I even broke one of my mother's favorite crockery bowls when I rolled a watermelon into it and it flew off the counter one hot summer day. In addition, it's getting increasingly difficult for me to give up my mother language. Sporting wheelchairs are now almost distant cousins of the everyday chair. A clear sign of my ignorance. Some clinics are able to show this on a compute...
2007 Jun 19
0
toilet
...simple tips we can disguise the fact that our hair is being lost just like that! It is possible to tow your own car in a pinch but definitely not recommended, especially if you are going far or fast. Edited by webBikeWorld. I even broke one of my mother's favorite crockery bowls when I rolled a watermelon into it and it flew off the counter one hot summer day. In addition, it's getting increasingly difficult for me to give up my mother language. Sporting wheelchairs are now almost distant cousins of the everyday chair. A clear sign of my ignorance. Some clinics are able to show this on a compute...
2004 Oct 19
0
答复: 答复: 答复: How to draw x-axis time label.
...:15:27", "2004-08-11 21:38:24", "2004-08-12 14:28:41", "2004-08-18 18:04:47", "2004-08-13 15:23:14", "2004-08-14 02:36:33") Time <- as.POSIXlt(Time) x <- data.frame(main.name="AAA", fruit.name=rep(c("Apply","Watermelon"),each=5), x.name=Time, y.name=(1:10)) plot(as.numeric(x$x.name),as.character(x$y.name),pch=26,) fruit.class <- table(x$fruit.name) color.code <- c(611,552,656,121,451,481,28,652,32,550,90,401,150,12,520,8) for(j in 1:length(fruit.class)) { fruit <- names(fruit.class)[j] lines(smo...