search for: water_level

Displaying 6 results from an estimated 6 matches for "water_level".

2024 Apr 07
1
Question regarding reservoir volume and water level
...s to do this in R? > I would be more than happy if anyone could help me. > Sincerely > > > > > > > > Hello, This is a simple rule of three. If you know the level l the argument doesn't need to be named but if you know the volume v then it must be named. water_level <- function(l, v, level = 1240, volume = 7e6) { if(missing(v)) { volume * l / level } else level * v / volume } lev <- 1250 vol <- 14e6 water_level(l = lev) #> [1] 7056452 water_level(v = vol) #> [1] 2480 Hope this helps, Rui Barradas -- Este e-mail foi analisado p...
2024 Apr 07
1
Question regarding reservoir volume and water level
...rite codes to do this in R? > I would be more than happy if anyone could help me. > Sincerely > > > > > > > > Hello, This is a simple rule of three. If you know the level l the argument doesn't need to be named but if you know the volume v then it must be named. water_level <- function(l, v, level = 1240, volume = 7e6) { if(missing(v)) { volume * l / level } else level * v / volume } lev <- 1250 vol <- 14e6 water_level(l = lev) #> [1] 7056452 water_level(v = vol) #> [1] 2480 Hope this helps, Rui Barradas -- Este e-mail foi analisado pe...
2024 Apr 07
2
Question regarding reservoir volume and water level
Dear all; I have a question about the water level of a reservoir, when the volume changed or doubled. There is a DEM file with the highest elevation 1267 m. The lowest elevation is 1230 m. The current volume of the reservoir is 7,000,000 m3 at 1240 m. Now I want to know what would be the water level if the volume rises to 1250 m? or what would be the water level if the volume doubled (14,000,000
2024 Apr 07
1
Question regarding reservoir volume and water level
...rite codes to do this in R? > I would be more than happy if anyone could help me. > Sincerely > > > > > > > > Hello, This is a simple rule of three. If you know the level l the argument doesn't need to be named but if you know the volume v then it must be named. water_level <- function(l, v, level = 1240, volume = 7e6) { if(missing(v)) { volume * l / level } else level * v / volume } lev <- 1250 vol <- 14e6 water_level(l = lev) #> [1] 7056452 water_level(v = vol) #> [1] 2480 Hope this helps, Rui Barradas -- Este e-mail foi analisado pe...
2024 Apr 09
1
Question regarding reservoir volume and water level
...> >>>> >>>> >>> Hello, >>> >>> This is a simple rule of three. >>> If you know the level l the argument doesn't need to be named but if you >>> know the volume v then it must be named. >>> >>> >>> water_level <- function(l, v, level = 1240, volume = 7e6) { >>> if(missing(v)) { >>> volume * l / level >>> } else level * v / volume >>> } >>> >>> lev <- 1250 >>> vol <- 14e6 >>> >>> water_level(l = lev) >&...
2024 Apr 10
1
Question regarding reservoir volume and water level
...gt;>> Hello, > >>> > >>> This is a simple rule of three. > >>> If you know the level l the argument doesn't need to be named but if > you > >>> know the volume v then it must be named. > >>> > >>> > >>> water_level <- function(l, v, level = 1240, volume = 7e6) { > >>> if(missing(v)) { > >>> volume * l / level > >>> } else level * v / volume > >>> } > >>> > >>> lev <- 1250 > >>> vol <- 14e6 > >>>...