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Full_Name: Wacek Kusnierczyk Version: 2.8.0 and 2.10.0 r48242 OS: Ubuntu 8.04 Linux 32 bit Submission from: (NULL) (80.202.30.36) The following raises an error: if (as.raw(1)) 1 # error: unimplemented type 'raw' in 'asLogical' However, ?'if' says: " Arguments: cond: A l...

...04 day 22 svn rev 45424 language R version.string R version 2.7.0 (2008-04-22) vQ -- ------------------------------------------------------------------------------- Wacek Kusnierczyk, MD PhD Email: waku at idi.ntnu.no Phone: +47 73591875, +47 72574609 Department of Computer and Information Science (IDI) Faculty of Information Technology, Mathematics and Electrical Engineering (IME) Norwegian University of Science and Technology (NTNU) Sem Saelands vei 7, 7491 Tron...

I was wondering why the following doesn't work: > a=c(1,2) > names(a)=c("one","two") > a one two 1 2 > > names(a[2]) [1] "two" > > names(a[2])="too" > names(a) [1] "one" "two" > a one two 1 2 I must not be understanding some basic concept here. Why doesn't the 2nd name change to

I was wondering why the following doesn't work: > a=c(1,2) > names(a)=c("one","two") > a one two 1 2 > > names(a[2]) [1] "two" > > names(a[2])="too" > names(a) [1] "one" "two" > a one two 1 2 I must not be understanding some basic concept here. Why doesn't the 2nd name change to

Following Duncan's suggestion, I forward the below to R-devel. vQ -------- Original Message -------- Subject: Re: [R] Randomly remove condition-selected rows from a matrix Date: Fri, 02 Jan 2009 10:34:52 -0500 From: Duncan Murdoch <murdoch at stats.uwo.ca> To: Wacek Kusnierczyk <Waclaw.Marcin.Kusnierczyk at idi.ntnu.no> CC: R help <R-help at stat.math.ethz.ch> References: <79CAFBDD-4BB8-4C9D-A0E9-54E280458510 at gmail.com> <8b356f880812300920o19d18aeo47dc31f087c3f36 at mail.gmail.com> <DA6ECC19-C786-4C02-B246-4B613726BC7F at gmail....

It was recently pointed out by Wacek Kusnierczyk that although one is prevented from doing FALSE <- TRUE one *can* do assign("FALSE",TRUE) and have an object named ``FALSE'' with value TRUE in one's workspace. This apparently has no deleterious effects; e.g. doing sample(1:7,replace=FALSE) gives a ra...

m = matrix(1:4, 2) apply(m, 1, cat, '\n') # 1 2 # 3 4 # NULL why the null? vQ

the following is a trivialized version of some functional code i tried to use in r: (funcs = lapply(1:5, function(i) function() i)) # a list of no-parameter functions, each with its own closure environment, # each supposed to return the corresponding index when applied to no arguments sapply(funcs, function(func) func()) # supposed to return c(1,2,3,4,5) there is absolutely nothing unusual in

Full_Name: Wacek Kusnierczyk Version: 2.10.0 r48269 OS: Ubuntu 8.04 Linux 32 bit Submission from: (NULL) (129.241.199.164) In the following example (and many other cases): quote(a=1) # 1 the argument matching is apparently incorrect wrt. the documentation (The R Language Definition, v 2.8.1, sec. 4.3.2, p...

Full_Name: Wacek Kusnierczyk Version: 2.10.0 r48365 OS: Ubuntu 8.04 Linux 32bit Submission from: (NULL) (129.241.110.141) sprintf has a documented limit on strings included in the output using the format '%s'. It appears that there is a limit on the length of strings included with, e.g., the format '...

Full_Name: Wacek Kusnierczyk Version: 2.8.0 and 2.10.0 r48242 OS: Ubuntu 8.04 Linux 32 bit Submission from: (NULL) (129.241.110.161) In the following code: duplicated(data.frame(), incomparables=NA) # Error in if (!is.logical(incomparables) || incomparables) .NotYetUsed("incomparables != FALSE")...

Hello! I have the problem that in my function the passed variable is not used, but the variable name of the dataframe itself?- difficult to explain, but an easy example: TestFunc<-function(df, group) { ??? print(names(subset(df, select=group))) } df1<-data.frame(group="G1", visit="V1", value=0.9) TestFunc(df1, c("group", "visit")) Result: [1]

...e in just one place instead of four locations in the code should make it simpler to understand, maintain, and further extend the code. The patch was made based on the src/main/character.c file in R-devel_2009-01-20. Patched code was successfully compiled and tested on 32bit Ubuntu 8.04. Regards, Wacek -- ------------------------------------------------------------------------------- Wacek Kusnierczyk, MD PhD Email: waku at idi.ntnu.no Phone: +47 73591875, +47 72574609 Department of Computer and Information Science (IDI) Faculty of Information Technology, Mathematics and Electrical Engineeri...

Full_Name: Wacek Kusnierczyk Version: 2.8.0 and 2.10.0 r48231 OS: Ubuntu 8.04 Linux 32 bit Submission from: (NULL) (80.202.30.36) According to the R Language definition (sec. 3.4.3), [.data.frame has the following properties: "if two indices are supplied (even if one is empty) it creates matrix-like indexin...

i wonder about the following examples showing incoherence in how type conversions are done in r: x = TRUE x[2] = as.raw(1) # Error in x[2] = as.raw(1) : # incompatible types (from raw to logical) in subassignment type fix it seems that there is an attempt to coerce the raw value to logical here, which fails, even though as.logical(as.raw(1)) # TRUE likewise, x[2]

i wonder about the following examples showing incoherence in how type conversions are done in r: x = TRUE x[2] = as.raw(1) # Error in x[2] = as.raw(1) : # incompatible types (from raw to logical) in subassignment type fix it seems that there is an attempt to coerce the raw value to logical here, which fails, even though as.logical(as.raw(1)) # TRUE likewise, x[2]

...orwarded message ---------- > From: "Tena Sakai" <tsakai at gallo.ucsf.edu> > To: <ted.harding at manchester.ac.uk>, <r-help at r-project.org> > Date: Tue, 28 Apr 2009 15:04:53 -0700 > Subject: Re: [R] Newbie R question PART2 > Hi, > > Many thanks to Wacek Kusnierczyk and Ted Harding. > > I learned 3 new tricks. (Not bad for a newbie?) > > $ R --silent --no-save < barebone.R > $ R --quiet --no-save < barebone.R > $ R --slave < barebone.R > > With slight differences, they all do what I wanted. > > Moving righ...

Dear all, let's assume I have a vector of character strings: x <- c("abcdef", "defabc", "qwerty") What I would like to find is the following: all elements where the word 'abc' does not appear (i.e. 3 in this case of 'x'). Since I am not really experienced with regular expressions, I started slowly and thought I find all word were

the man page for relational operators (see, e.g., ?'<') says: " Binary operators which allow the comparison of values in atomic vectors. Arguments: x, y: atomic vectors, symbols, calls, or other objects for which methods have been written. " it is somewhat surprizing that the following works: '<'(1) # logical(0) '<'() #

the man page for relational operators (see, e.g., ?'<') says: " Binary operators which allow the comparison of values in atomic vectors. Arguments: x, y: atomic vectors, symbols, calls, or other objects for which methods have been written. " it is somewhat surprizing that the following works: '<'(1) # logical(0) '<'() #