search for: visitation

Hi, Could someone help with coding this in R? I need to select one row per patient i in clinic j. The data is organized similar to that shown below. Two columns - patient i in column j identify each unique patient. There are two columns on outcome. Some patients have multiple rows with each row representing one visit, coded for in the column, visit. Some patients have just one row indicating

Hi! I have a table with visits with a visited_at: attribute which is a datetime field. They seem to be stored as UTC. Now I want to count all visits each day and return something like: { 2013-01-01: 8, 2013-01-02: 4, 2013-01-07: 9, ... } So, I did it like this which kind of works...: def self.total_grouped_by_day(start_date, end_date) visits = where(visited_at:

R friends, I am using R 2.1.0 in a Win XP . I have a problem working with lists, probably I do not understand how to use them. Lets suppose that a set of patients visit a clinic once a year for 4 years on each visit a test, say 'eib' is performed with results 0 or 1 The patients do not all visit the clinic the 4 times but they missed a lot of visits. The test is considered positive if it

Hallo! I have data of the following design: NSubj were measured at Baseline (visit 1) and at 3 following time points (visit 2, visit 3, visit 4). There is or is not a treatment. Most interesting is the question if there is a difference in treatment between the results of visit 4 and baseline. (The other time points are also of interest.) The level of significance is alpha=0.0179 (because of an

I am logging web visits with a before_filter on the application controller. The issue I''m having is that the initial visit does not return a session id. I''m using the SqlSessionStore and the function MysqlSession.find_session(session.session_id) to retrieve the session id. If it doesn''t exist I use a -1. So looking in my visits table the initial visit always has -1 for

I have a class that has_many :visits, I want to search through the visits to get only ones that are committed: I thought it would be as easy as: ================== visits.find_all do |visit| visit.coming? end ================= but this always returns the entire list of visits. The only way to get it to work is to put the visits into a new array first: =================

Dear R-Community! For example I have a study with 4 treatment groups (10 subjects per group) and 4 visits. Additionally, the gender is taken into account. I think - and hope this is a goog idea (!) - this data can be analysed using lme as below. In a balanced design everything is fine, but in an unbalanced design there are differences depending on fitting y~visit*treat*gender or

On Thu, Jun 16, 2016 at 11:12 AM, Sanjoy Das <sanjoy at playingwithpointers.com > wrote: > Hi Sean, > > On Thu, Jun 16, 2016 at 4:48 AM, Sean Silva via llvm-dev > <llvm-dev at lists.llvm.org> wrote: > > One question is what invariants we want to provide for the visitation. > > > > For example, should a CGSCC pass be able to assume that all "child" SCC's > > (SCC's it can reach via direct calls emanating from the SCC being > visited) > > have already been visited? Currently I don't think it can, and IIRC from > the...

...passes" stuff interesting? >>>>>> Because LLVM can do inlining on an SCC (often just a single function) and >>>>>> then run function passes to simplify the function(s) in the SCC before it >>>>>> tries to inline into a parent SCC. (the SCC visitation order is post-order) >>>>>> For example, we may inline a bunch of code, but after inlining we can >>>>>> tremendously simplify the function, and we want to do so before considering >>>>>> this function for inlining into its callers so that we ge...

Hi Everyone, Good Day! I wanna to add to my blog a counter for displaying, how many times was my website visited. I would like to solve it through ruby (not GA or something like that). Is available any gem that do this task (also with checking IP address,the time of latest visited and visited count). Please Advice. Thank You. -- You received this message because you are subscribed to the

...>> sanjoy at playingwithpointers.com> wrote: >> >>> Hi Sean, >>> >>> On Thu, Jun 16, 2016 at 4:48 AM, Sean Silva via llvm-dev >>> <llvm-dev at lists.llvm.org> wrote: >>> > One question is what invariants we want to provide for the visitation. >>> > >>> > For example, should a CGSCC pass be able to assume that all "child" >>> SCC's >>> > (SCC's it can reach via direct calls emanating from the SCC being >>> visited) >>> > have already been visited? Curren...

...ndirect callees), a callee node may be visited later. The analysis will just have to punt when a special edge to 'external' node is seen. David > > -Hal > > Consider the pipeline `cgscc(function(...simplifications that can > devirtualize...),foo-cgscc-pass)`. A possible visitation is as follows: > > 1. Visit SCC {S,T} and run `function(...simplifications that can > devirtualize...)`. This reveals the call edge T->Y. > 2. We continue visiting SCC {S,T} and run foo-cgscc-pass on SCC {S,T}. > 3. Visit SCC {X,Y} and run `function(...simplifications that can &gt...

HI All, Can any anyone please help me with attached screenshot. Actually i am not able to lauch puppet dashboard and when i have tried to running below command ,getting error. puppet resource service puppet ensure=running enable=true -- Thanks and Regards, Mamta Garg -- You received this message because you are subscribed to the Google Groups "Puppet Users" group. To unsubscribe

Is it possible to format the x axis, so that days are spaced proportionately? i.e. a larger space between 50 & 100, than 0 and 5? Have not had any luck with axis.POSIXct(). Many thanks Murray try <- structure(list(visit = structure(as.integer(c(1, 2, 3, 4, 5, 1, 2, 3, 4, 5, 1, 2, 3, 4, 5, 1, 2, 3, 4, 5, 1, 2, 3, 4, 5, 1, 2, 3, 4, 5)), .Label = c("Screening", "0",

Hello, Is there anyone porting R data to VisIt (http://www.llnl.gov/visit/)? Altough VisIt accepts 5 dozen of data formats, I can't get my data into VisIt. I currently ran a simulation which gave me a data frame, which I wanted to import into VisIt to further explore the dataframe. Let's say I have a data frame as follows: dat <- data.frame(cbind( 1, 1:10),X3=

What is the best and easy''t way to let all nodes ssh passwordless to each other ? -- You received this message because you are subscribed to the Google Groups "Puppet Users" group. To unsubscribe from this group and stop receiving emails from it, send an email to puppet-users+unsubscribe@googlegroups.com. To post to this group, send email to puppet-users@googlegroups.com.

...; >>>>> Hi Sean, >>>>> >>>>> On Thu, Jun 16, 2016 at 4:48 AM, Sean Silva via llvm-dev >>>>> <llvm-dev at lists.llvm.org> wrote: >>>>> > One question is what invariants we want to provide for the >>>>> visitation. >>>>> > >>>>> > For example, should a CGSCC pass be able to assume that all "child" >>>>> SCC's >>>>> > (SCC's it can reach via direct calls emanating from the SCC being >>>>> visited) >>&gt...

Hi I am saving password with hashed_password and salt in table. Now I need to send those passwords via SMS can it be possible.Kindly give me some suggestion plz . Thanks in advance Cheers -- You received this message because you are subscribed to the Google Groups "Ruby on Rails: Talk" group. To unsubscribe from this group and stop receiving emails from it, send an email to

dear List I have a dataset with blood measurements at 5 points in TIME (0,30,60,90,120) taken on 3 VISITS (same subjects). the interest is to compare these measurements between Visits, overall and at the different time points. I have problems setting up repeated measures ANOVA with 2 repeated measures (VISIT and TIME) (and then doing post hoc testing) or doing it with a linear mixed model ( both

I'm trying to add a set of reference lines to a multipanel xyplot xyplot(y ~ x | Visit, panel = function(x, y, ...){ panel.xyplot(x, y, ...) abline(v = c(0.5, 1)) }) However, the reference lines are different for different visits. For example, for the first 2 visits, I'd like vertical lines at x = 0.5 and 1. For visits 3 and four, I'd like vertical lines at x = 1 and 1.5. I can