search for: vishwanath

Hi R, If x=c(1,3,5) y=c(2,4,6) I need a vector which is c(1,2,3,4,5,6) from x and y. How do I do it? I mean the best way.... Thanks, Shubha This e-mail may contain confidential and/or privileged i...{{dropped:13}}

Hi R, I need to generate 50 random numbers (preferably poisson), such that their sum is equal to 100. How do I do this? Thank you, Shubha This e-mail may contain confidential and/or privileged i...{{dropped:13}}

Hi R, This is a very trivial one.... C=0.1 I want to check whether my value of C is between 0 and 1 exclusively.... I don't want to use (C>0 & C<1). And I can't use a single statement like (0<C<1). Is there a between function? Or how do we specify from 0 to 1? Does %in% help me? Many Thanks, Shubha This e-mail may contain confidential and/or

Hi, I am Vishwanath, I got one requirement from our clients regarding remote authentication. In which all users info present in remote user database. Currently using openssh for SSH connections. To open a new remote session via SSH, the openssh will look into the /etc/passwd file. If user present then it will allow t...

...column called AGE. Now I call the function c = a_fn(AGE); When a_fn is called, AGE is received in arg1. My question is, how do I access the actual name of the argument arg1? i.e, inside the function, i need to know that the actual name of arg1 is "AGE" in this case. Thanks in advance, Vishwanath

Hi R, Please solve my problem........... I am extracting Bloomberg data from R, in a loop. R is getting fatigued by doing this process and gives some errors. I introduced sleep function. Doing this sometimes I get the results and sometimes not. I even noticed that if I give complete rest for R (don't open R window) for 1 day and then run my code with the sleep function, then the

Hi R, Let, x=1:80 I want to sum up first 8 elements of x, then again next 8 elements of x, then again another 8 elements..... So, my new vector should look like: c(36,100,164,228,292,356,420,484,548,612) I used: aggregate(x,list(rep(1:10,each=8)),sum)[-1] or rowsum(x,group=rep(1:10,each=8)) But without grouping, can I achieve the required? Any other ways of doing

Hi, Thanks for the replay. This is the platform which we are using. Distributor ID: Debian Description: Debian GNU/Linux 8.2 (jessie) Release: 8.2 Codename: jessie Regards, Vishwanath KC +918892599848. On Tue, Jan 24, 2017 at 11:16 AM, Darren Tucker <dtucker at zip.com.au> wrote: > On Tue, Jan 24, 2017 at 4:17 PM, Vishwanath KC <vicchi.cit at gmail.com> > wrote: > [...] > > But in my case all user info is present in remote database and > > auth...

Hi R, A quick question: How do we find the number of words in a string? Example: C="Have a nice day" And the number of words should be 4. any built in function or?... Thanks, Shubha Shubha Karanth | Amba Research Ph +91 80 3980 8031 | Mob +91 94 4886 4510 Bangalore * Colombo * London * New York * San José * Singapore * www.ambaresearch.com This e-mail may contain

Hi, Suppose a=matrix(1:9,3,3) > a [,1] [,2] [,3] [1,] 1 4 7 [2,] 2 5 8 [3,] 3 6 9 Now, > class(a[1:2,]) [1] "matrix" > class(a[1:3,]) [1] "matrix" > class(a[,1:2]) [1] "matrix" > class(a[,1:3]) [1] "matrix" But, > class(a[1,]) [1] "integer" > class(a[,1]) [1]

Hi R, I have a vector V1 of unknown length, say n. I need to convert this into a matrix C of row size=5, and accordingly the column should be updated. I tried with: C=as.matrix(V1,5,n/5) But it is not working...Could somebody help me on this? Thanks in advance... [[alternative HTML version deleted]]

Hi R, I have a list, l=list(list(c(1,2),c(4,5),c(6,7)),list(c(11,22,33),c(44,55,66))) > l [[1]] [[1]][[1]] [1] 1 2 [[1]][[2]] [1] 4 5 [[1]][[3]] [1] 6 7 [[2]] [[2]][[1]] [1] 11 22 33 [[2]][[2]] [1] 44 55 66 How do I know the dimensions of this list?... In other words, how many sub-lists, sub-sub-lists etc...are there in l? How do I know this?

...pecified. I tried setting the "dev" attribute of source tag, but it doesn't look like that is being parsed and stored either. Regards, Harish On Fri, Oct 30, 2015 at 8:32 PM, Martin Kletzander <mkletzan@redhat.com> wrote: > On Fri, Oct 30, 2015 at 08:16:33PM +0530, Harish Vishwanath wrote: > >> Hello >> >> I am trying to create interfaces within an LXC container with specific >> name. I am using the following XML: >> >> <interface type='network' name='blah'> >> <source network='dpbr_n_0'/>...

On 5/13/2008 10:27 AM, Yukihiro Ishii wrote: > Hi Rusers! > > I am ashed of asking such a simple question. > > X<-matrix(rnorm(24), 4) > X0<-apply(X,2,mean) > > What I want is a matrix which consists of colums such as X[,1]--X0[1]. > > X-X0 doesn't work. > > Perhaps apply function? scale(X, scale=FALSE) ?scale > Thanks in advance. > >

Hi R, This is a cross tabulation question. Suppose that, > d=read.table("clipboard",header=F) > d V1 V2 V3 A One Apple A One Cake A One Cake B One Apple B One Apple B One Apple > table(d$V2,d$V3) Apple Cake One 4 2 But, I don't want the count to be like the above. Here, it is counting the

Hi, I wanted the DICE coefficient (similarity measure for binary variables) to be calculated in R and found that the "igraph" package has the option of "similarity.dice" to do this. But, for this command, the input object should be an igraph object. But, I have a dataframe of columns containing 1's and 0's. Can I convert this dataframe into an igraph object, so that

...them will return a functional virConnect instance. I'm not sure this segfault is worth to fix since instantiate a virConnect directly is not an expected usage. Hope this information will help you. Best Regards, Hao Liu +86-010-62608262 ----- Original Message ----- > From: "Harish Vishwanath" <harish.shastry@gmail.com> > To: "libvirt-users" <libvirt-users@redhat.com> > Sent: Friday, March 20, 2015 1:11:53 PM > Subject: Re: [libvirt-users] libvirt-python Segfaults > > Trying again. > > Is there another mailer list for libvirt-python rela...

Hi R, I am trying to download the data from R. I give the below command. > library(fImport) > yahooSeries("IBM") trying URL 'http://chart.yahoo.com/table.csv?s=IBM&a=7&b=08&c=2007&d=7&e=07&f=2008& g=d&x=.csv' Error in download.file(url = url, destfile = file, method = method) : cannot open URL

Hi R, I have a list of matrices. I need to get the sum of all the matrices in the list. Example: a=b=c=d=matrix(1:4,2,2) l=list(a,b,c,d) I need: > a+b+c+d [,1] [,2] [1,] 4 12 [2,] 8 16 Something like do.call("+",l) is not working...why is this? I may not be knowing the number of matrices in the list... Thanks, Shubha This e-mail

Hi, Could anyone tell me what is the command used in R to do 1. Differentiation 2. Newton Raphson method (Numerical Analysis in general...) Are there any packages separately for this? Thanks for your help! BR, Shubha [[alternative HTML version deleted]]