search for: vickythakr

Hi, I am trying to send an email through gmail or outlook from my Windows PC and finding trouble to send the email. The code which I am using is given below: Code : library("sendmailR") from <- "abcd@outlook.com" to <- <mailto:efgh@gmail.com> efgh@gmail.com subject <- "Run at" mailControl = list(smtpServer="blu-m.hotmail.com")

Hi Team, Need your guidance in building SPDF objects from Latitude, Longitude Information available. I am using package "plotGoogleMaps" which is really awesome but it requires SPDF objects to build the maps. I have a data frame which have Latitude and Longitude information and wanted to convert it in SPDF for making maps. Please help me to find suitable package or function to convert

Hi Team, I am trying to very simple plot with command plot. Question : I am trying to plot (x,y) based on the value of Column e. If column e value is greater than 0 then plot(x,y) otherwise do not plot it. Data : structure(list(x = c(1, 1, 1, 2, 2, 2, 3, 3, 3), y = c(1, 2, 3, 1, 2, 3, 1, 2, 3), e = c(0, -1, -2, 1, 0, -1, 2, 1, 0)), row.names = c(NA, -9L), .Names = c("x",

HI Team, I am currently working on problem and stumped on "for" loop. Data: structure(list(Coutry = structure(c(3L, 3L, 3L, 3L, 2L, 2L, 1L, 1L), .Label = c("J", "M", "U"), class = "factor"), State = structure(c(1L, 1L, 4L, 2L, 5L, 5L, 3L, 6L), .Label = c("A", "C", "K", "O", "S",

Hi Everyone, I am trying to run a time based query and need some of your help. Not much of data or packages. Just a simple one. Query I am trying to execute. ifelse ((as.numeric(as.POSIXct("2012-10-01 20:38:00"))), (rnorm(1,2,1)),(Sys.sleep())) Note. Why I am using as.numeric is as I have a list of time at which I wanted to run the command. Something like 1349142243 1349138667

Hi, I am currently working in Linux server and wanted to play with our beautiful R software over there. However as its a company server and have lots of restrictions so I am thinking to install it in my home directory. I have three questions in this regard. 1. Is it possible. 2. Is it safe for me and my company data. 3. How can I do that. Please help me to solve this questions and thanking you

Hi List, I am trying to build an animation and facing problem as animation is not coming "live". The goal is to build "heart beats" like diagram for the data given below. data : structure(list(date = 1971:1991, x = c(41L, 60L, 41L, 61L, 22L, 83L, 31L, 55L, 22L, 14L, 38L, 6L, 29L, 17L, 10L, 99L, 88L, 32L, 68L, 78L, 26L)), .Names = c("date", "x"), class =

Hi, Being a novice this is my first usage of R. I am trying to use rpart for building a decision tree in R. And I have the following dataframe Outlook Temp Humidity Windy Class Sunny 75 70 Yes Play Sunny 80 90 Yes Don't Play Sunny 85 85 No Don't Play Sunny 72 95 No Don't Play Sunny 69 70 No Play Overcast 72 90 Yes Play Overcast 83 78 No Play Overcast 64 65 Yes Play Overcast 81 75

Hi List Members, This is a very stupid problem but I am not able to know what the solution can be. I am trying to run a query like below *Program Flow :* 1. a <- data.frame(table( cut( Sys.time() + seq(0,82800,3600), "60 mins") )) # It generates the 60 minute intervals. Thanks David 2. b <- data.frame(a$Var1) # To extract only First Column i.e.

Hi Team, I am not sure how to run some r queries in continuos time interval for say in each 30 minutes. Will be very grateful if some one can give me some heads up in good direction. Unfortunately I dont have any query written or data which I can share and I know most of the respected people will not like it but it's kind of a thought which is perturbing me from some days. Thanks in

Hi List, This is kind of very simple but I am not able to understand how it works... I have a sentence like "Even in the mid-west spring is hardly for 3 weeks, while @south the scenario is different." There are some more example of the same nature and don't know the source yet. What i want to do is remove word after "@".. Solution i think of. 1.

Hi Everyone, I am trying a very simple task to append the Timestamp with a variable name so something like a_2012_09_27_00_12_30 <- rnorm(1,2,1). Tried some commands but it doesn't work out well. Hope someone has some answer on it. Session Info R version 2.15.1 (2012-06-22) Platform: i386-apple-darwin9.8.0/i386 (32-bit) locale: [1]