Displaying 5 results from an estimated 5 matches for "vect2".
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2006 Jul 04
1
Problems when computing the 1rst derivative of mixtures of densities
...t distribution).
To determine the maximum likelihood estimator I use the Newton-Rapdon
Iteration. But when
computing the first derivative I get a none linear function (with several
asymptotes) which is completely
absurd.
This is my function to compute the first derivative:
phy=function(teta,vect1,vect2){
return( sum(( vect2 - vect1) / (( 1 - teta) * vect1 + teta * vect2)))
}
note: vect1 and vect2 contains values of the two distributions computed
from sample previously extracted.
Beside, vect2 - vect1 is constant and ( 1 - teta) * vect1 + teta * vect2) is
linear and always defined so I am...
2011 Mar 29
3
Reversing order of vector
Dear R helpers
Suppose I have a vector as
vect1 = as.character(c("ABC", "XYZ", "LMN", "DEF"))
> vect1
[1] "ABC" "XYZ" "LMN" "DEF"
I want to reverse the order of this vector as
vect2 = c("DEF", "LMN", "XYZ", "ABC")
Kindly guide
Regards
Vincy
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2008 Nov 18
4
How do I generate multiple (similar) objects within R?
Hi,
I wonder if anyone knows how to generate a list of objects, e.g. ten
vectors with names: vect1, vect2, ... , vect10.
My own idea was to use something like:
for (i in 1:10)
print(paste("vect", i,"<-NULL",sep=""))
but the result is:
"vect1<-NULL"
...
"vect10<-NULL"
and not
vect1<-NULL
...
vect10<-NULL
as I would like. Does...
2011 Mar 15
2
Matching two vectors
...s
Suppose I have a vector as
vect_1 = c("AAA", "AA", "A", "BBB", "BB", "B", "CCC")
vect_1_id = c(1:length(vect_1))
Through some process I obtain
vect_2_id = c(2, 3, 7), then I need a new vector say vect_2 which will give me
vect2 = ("AA", "A", "CCC") i.e. I need the subset of vect_1 as per vect_2_id.
Thanking in advance
Regards
Vincy
[[alternative HTML version deleted]]
2009 Sep 01
3
data frame
HI, R user,
I generate the vectors with the same length. I want to put each vector into each column of data frame. Why it doesnt work`?
rm<-data.frame()
for(a in 1:6){
rm[,a]<-getmeasure(p1,a,speech)
}
thanks a lot
Tammy
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