Displaying 15 results from an estimated 15 matches for "var9".
Did you mean:
var
2011 Jun 23
2
Merging multiple data sets
...0 1
3 1 0 1
4 0 1 1
5 0 1 1
> dat1
id var4 var5 var6
2 1 0 1
3 1 0 1
6 0 1 1
7 0 1 1
> dat2
id var7 var8 var9
2 1 0 1
5 1 0 1
6 0 1 1
8 0 1 1
Basically what I'd like to do is combine these variables on id and create
one large data frame that looks like the following.
> dat3
id var1 var2 var3 var4...
2010 Jan 25
5
Data transformation
Dear all,
I have a dataset that looks like this:
x <- read.table(textConnection("col1 col2
3 1
2 2
4 7
8 6
5 10"), header=TRUE)
I want to rewrite it as below:
var1 var2 var3 var4 var5 var6 var7 var8 var9 var10
1 0 1 0 0 0 0 0 0 0
0 2 0 0 0 0 0 0 0 0
0 0 0 1 0 0 1 0 0 0
0 0 0 0 0 1 0 1 0 0
0 0 0 0 1 0...
2009 Dec 15
1
Changing Column names in (Output) csv file
...<- c(0.44,0.07,0.49)
range_prob[[8]] <- c(0.54,0.06,0.40)
range_prob[[9]] <- c(0.26,0.62,0.12)
range_prob[[10]] <- c(0.65,0.19,0.16)
pdf <- expand.grid(range_prob)
data_lab$probs <- apply(pdf, 1, prod)
joint_probs = xtabs(probs ~ Var1 + Var2+Var3+Var4+Var5+Var6+Var7+Var8+Var9+Var10, data = data_lab)
write.csv(data.frame(joint_probs), 'joint_probs.csv', row.names = FALSE)
ONS = read.csv('joint_probs.csv')
Names = NULL
for (i in 1:length(joint_probs))
{
Names[i] = paste(ONS$Var1[i], ONS$Var2[i], ONS$Var3[i], ONS$Var4[i], ONS$Var5[i], ONS$Va...
2010 Jan 26
6
Help
> Dear All
>
> I have data as follows.
>
> D T M L
> 0.20 1 03 141
> 0.32 1 07 62
> 0.50 1 05 49
> 0.80 1 04 46
> 0.20 2 14 130
> 0.32 2 17 52
> 0.50 2 13 41
> 0.80 2 14 36
> 0.20 3 24 120
> 0.32
2007 Nov 07
2
creating a dynamic output vector
Let's say I have a program that returns variables whose names may be any
string within the vector
NAMES=c("varA","varB","varC","varD","varE","varF"..."varZ"), but I do
not ever know which ones have actually been created. So in one example
output, "varA", "varC", and "varD" could exist, but
2008 Mar 07
0
linear discriminant analysis / search
...7 7 12 12 12 9 6 6
var4 4 5 4 10 12 9 2 2 2
var5 4 5 4 10 9 10 3 2 3
var6 5 4 5 2 3 2 1 3 5
var7 5 4 5 7 7 7 3 3 3
var8 3 4 3 10 10 8 4 2 4
var9 3 4 3 2 2 2 2 2 2
var10 3 3 3 4 4 4 3 1 2
Table 2
unknown
var1 23
var2 4
var3 7
var4 4
var5 4
var6 6
var7 5
var8 3
var9 3
var10 3
Thanks
RS
[[alternative HTML version deleted]]
2008 Mar 07
0
linear discriminant analysis
...7 7 12 12 12 9 6 6
var4 4 5 4 10 12 9 2 2 2
var5 4 5 4 10 9 10 3 2 3
var6 5 4 5 2 3 2 1 3 5
var7 5 4 5 7 7 7 3 3 3
var8 3 4 3 10 10 8 4 2 4
var9 3 4 3 2 2 2 2 2 2
var10 3 3 3 4 4 4 3 1 2
Table 2
unknown
var1 23
var2 4
var3 7
var4 4
var5 4
var6 6
var7 5
var8 3
var9 3
var10 3
Thanks
RS
[[alternative HTML version deleted]]
2009 Jul 15
1
Averaging dataframes that are stored in a list
Dear R-helpers,
I have a list containing 5000 elements, each element is a dataframe
containing one ID column (identical over the 5000 dataframes) and 9 numeric
variables, e.g.
ID VAR1 VAR2 VAR3 ... VAR9
I would like to create a new dataframe containing the ID column and the mean
values of the 9 numeric variables. So, the structure of this new dataframe
would be identical to the structure of the dataframes stored in my list (and
the ID column would also be identical) but the values would be mean v...
2011 Nov 04
1
How to use 'prcomp' with CLUSPLOT?
...using pca. I have tried using CLUSPLOT(), but that only allows for 'princomp' where I need 'prcomp' as I do not want to reduce my columns. Is there a way to edit the CLUSPLOT() code to use 'prcomp', please?
# sample of my data
PRVID,VAR1,VAR2,VAR3,VAR4,VAR5,VAR6,VAR7,VAR8,VAR9,VAR10,VAR11
PRV1,0,54463,53049,62847,75060,184925,0,0,0,0,0
PRV2,0,2100,76,131274,0,0,0,0,0,0,18
PRV3,967,0,0,0,0,0,0,0,0,3634,0
PRV4,817,18344,3274,9264,1862,0,0,141,0,0,0
PRV5,0,0,0,0,0,0,29044,0,0,0,0
PRV6,59,6924,825,3008,377,926,0,0,10156,0,5555
PRV7,11,24902,36040,47223,20086,0,0,749,415,0,0...
2012 Oct 25
1
cut point in ROC
var1
var2
var3
var4
var5
var6
var7
var8
var9
var10
gold
2
3
1
2
4
0
1
4
4
3
2
2
4
2
4
3
4
2
4
4
4
2
3
3
0
0
4
1
0
2
4
4
2
1
4
0
3
2
0
0
2
4
4
2
3
4
0
2
2
0
0
0
3
4
2
2
2
3
2
2
0
0
0
2
4
2
2
4
1
1
2
0
0
3
3
3
2
3
4
1
4
0
0
0
0
3
4
2
3
1
0
2
2
1
0...
2004 Jan 08
1
(no subject)
...rting a character string to a R object. Let me describe this by an example;
> dim(a)
[1] 270 14
> dim("a")
NULL
> names(a)
[1] "Var1" "Var2" "Var3" "Var4" "Var5" "Var6" "Var7" "Var8" "Var9"
[10] "Var10" "Var11" "Var12" "Var13" "Var14"
> names("a")
NULL
I realise that the character string lacks both a dimension and any column names; my question is how to make R understand that I look for the object a when I write &q...
2004 Jan 08
0
(no subject)
...describe this by an example;
>
> > dim(a)
> [1] 270 14
> > dim("a")
> NULL
>
> > names(a)
> [1] "Var1" "Var2" "Var3" "Var4" "Var5" "Var6" "Var7"
> "Var8" "Var9"
> [10] "Var10" "Var11" "Var12" "Var13" "Var14"
> > names("a")
> NULL
>
> I realise that the character string lacks both a dimension
> and any column names; my question is how to make R understand
> that I...
2004 Feb 13
3
Calculate Closest 5 Cases?
...all percents, so they are easy comparable.
Is there any way to do this in R?
Below is a small sample of the data (from SPSS) and the desired output.
Thanks,
Danny
*Sample Data.
DATA LIST LIST /id(F8) var1(F8.2) var2(F8.2) var3(F8.2) var4(F8.2) var5
(F8.2) var6(F8.2) var7(F8.2) var8(F8.2) var9(F8.2) var10(F8.2) var11(F8.2).
BEGIN DATA.
10170069 3.51 4.02 6.53 11.05 6.53 8.04 13.57 20.10 11.05 8.55
7.04
10190229 1.89 5.66 4.61 7.62 8.45 13.21 9.50 20.82 16.07 9.36
3.77
10540023 3.40 5.08 3.39 4.52 10.18 14.71 13.56 16.38 9.60 7.89
11.85
10650413 6.64 6.64 3.73 4.70 3.78 13.23 19.82 15....
2012 Sep 27
1
List of Variables in Original Order
I am trying to Sweave the output of calculating correlations between one
variable and several others. I wanted to print a table where the
odd-numbered rows contain the variable names and the even-numbered rows
contain the correlations. So if VarA is correlated with all the variables in
mydata.df, then it would look like
var1 var2 var3
corr1 corr2 corr3
var4 var5
2006 Feb 21
6
How to sum values across multiple variables using a wildcard?
I have a dataframe called "data" with 5 records (in rows) each of
which has been scored on each of many variables (in columns).
Five of the variables are named var1, var2, var3, var4, var5 using
headers. The other variables are named using other conventions.
I can create a new variable called var6 with the value 15 for each
record with this code:
> var6=var1+var2+var3+var4+var5