Displaying 20 results from an estimated 23 matches for "var8".
Did you mean:
var
2012 May 09
0
serie de tiempo incompleta: rellenar sólo fechas (claudiomet)
...ay discontinuidades. No me interesa llenar los vacÃos
> en las variables, sólo las fechas y dejar las variables en blanco ¿es
> posible hacerlo en R?. Mi serie de tiempo es del tipo (con fecha en formato
> dd-mm-yyyy hh:mm):
>
> 01-01-2011 00:00 var1 var2 var3 var4 var5 var6 var7 var8
> 01-01-2011 00:01 var1 var2 var3 var4 var5 var6 var7 var8
> 01-01-2011 00:02 var1 var2 var3 var4 var5 var6 var7 var8
> 01-01-2011 00:03 var1 var2 var3 var4 var5 var6 var7 var8
> 01-01-2011 00:04 var1 var2 var3 var4 var5 var6 var7 var8
> 01-01-2011 00:07 var1 var2 var3 var4 var5 var6...
2010 Nov 08
2
Several lattice plots on one page
...rying (!!!) to generate pdfs that have 8 plots on one page:
df = data.frame(
day = c(1,2,3,4),
var1 = c(1,2,3,4),
var2 = c(100,200,300,4000),
var3 = c(10,20,300,40000),
var4 = c(100000,20000,30000,4000),
var5 = c(10,20,30,40),
var6 = c(0.001,0.002,0.003,0.004),
var7 = c(123,223,123,412),
var8 = c(213,123,234,435),
all = as.factor(c(1,1,1,1)))
pdf("test1.pdf", width=20, heigh=27, paper="a4")
print(plot(groupedData(var1 ~ day | all, data = df), main = "var1", xlab="", ylab=""), split=c(1,1,2,4), more=TRUE)
print(plot(groupedData...
2010 Dec 03
2
Add columns of dataset
Dear all,
I have a dataset that looks like
id var1 var2 var4 var7 var8
1 0.0 0.1 0.3 0.9 0.0
2 0.4 0.6 0.0 0.0 0.2
3 0.0 0.0 0.0 0.8 0.7
Some columns are missed, for example, here the fourth (var3), sixth(var5)
and seventh (var6) columns. I want to first determine which columns are
missed in a huge dataset and th...
2011 Jun 23
2
Merging multiple data sets
...1 0 1
3 1 0 1
4 0 1 1
5 0 1 1
> dat1
id var4 var5 var6
2 1 0 1
3 1 0 1
6 0 1 1
7 0 1 1
> dat2
id var7 var8 var9
2 1 0 1
5 1 0 1
6 0 1 1
8 0 1 1
Basically what I'd like to do is combine these variables on id and create
one large data frame that looks like the following.
> dat3
id var1 var2 var3...
2010 Jan 25
5
Data transformation
Dear all,
I have a dataset that looks like this:
x <- read.table(textConnection("col1 col2
3 1
2 2
4 7
8 6
5 10"), header=TRUE)
I want to rewrite it as below:
var1 var2 var3 var4 var5 var6 var7 var8 var9 var10
1 0 1 0 0 0 0 0 0 0
0 2 0 0 0 0 0 0 0 0
0 0 0 1 0 0 1 0 0 0
0 0 0 0 0 1 0 1 0 0
0 0 0 0 1 0...
2008 Apr 28
1
error in summary.Design
...h the Design package (stored as "mymodel") I
try running a summary, but I get the following error:
dim(mydata)
[1] 235 9
names(mydata)
[1] "id" "VAR1" "VAR2" "VAR3" "VAR4" "VAR5" "VAR6" "VAR7" "VAR8"
summary(mymodel)
Error in `contrasts<-`(`*tmp*`, value = "contr.treatment") :
contrasts can be applied only to factors with 2 or more levels
but,
VAR1 is my dependent
> nlevels(factor(VAR1))
[1] 2
VAR2 is continuous
> summary(psa)
Min. 1st Qu. Median Mean 3rd...
2009 Dec 15
1
Changing Column names in (Output) csv file
...[7]] <- c(0.44,0.07,0.49)
range_prob[[8]] <- c(0.54,0.06,0.40)
range_prob[[9]] <- c(0.26,0.62,0.12)
range_prob[[10]] <- c(0.65,0.19,0.16)
pdf <- expand.grid(range_prob)
data_lab$probs <- apply(pdf, 1, prod)
joint_probs = xtabs(probs ~ Var1 + Var2+Var3+Var4+Var5+Var6+Var7+Var8+Var9+Var10, data = data_lab)
write.csv(data.frame(joint_probs), 'joint_probs.csv', row.names = FALSE)
ONS = read.csv('joint_probs.csv')
Names = NULL
for (i in 1:length(joint_probs))
{
Names[i] = paste(ONS$Var1[i], ONS$Var2[i], ONS$Var3[i], ONS$Var4[i], ONS$Var5[i], O...
2010 Jan 26
6
Help
> Dear All
>
> I have data as follows.
>
> D T M L
> 0.20 1 03 141
> 0.32 1 07 62
> 0.50 1 05 49
> 0.80 1 04 46
> 0.20 2 14 130
> 0.32 2 17 52
> 0.50 2 13 41
> 0.80 2 14 36
> 0.20 3 24 120
> 0.32
2010 Dec 31
3
Changing column names
...ntry = c("US", "France", "UK", "NewZealand", "Germany", "Austria", "Italy", "Canada")
Through some other R process, the result.csv file is generated as
result.csv
var1 var2 var3 var4 var5 var6 var7 var8
1 25 45 29 92 108 105 65 56
2 80 132 83 38 38 11 47 74
3 135 11 74 56 74 74 74 29
I need the country names to be column heads i.e. I need an output like
> result_new
US Fran...
2007 Nov 07
2
creating a dynamic output vector
Let's say I have a program that returns variables whose names may be any
string within the vector
NAMES=c("varA","varB","varC","varD","varE","varF"..."varZ"), but I do
not ever know which ones have actually been created. So in one example
output, "varA", "varC", and "varD" could exist, but
2008 Mar 07
0
linear discriminant analysis / search
...5 4 9 8 9 10 9 10
var3 7 7 7 12 12 12 9 6 6
var4 4 5 4 10 12 9 2 2 2
var5 4 5 4 10 9 10 3 2 3
var6 5 4 5 2 3 2 1 3 5
var7 5 4 5 7 7 7 3 3 3
var8 3 4 3 10 10 8 4 2 4
var9 3 4 3 2 2 2 2 2 2
var10 3 3 3 4 4 4 3 1 2
Table 2
unknown
var1 23
var2 4
var3 7
var4 4
var5 4
var6 6
var7 5
var8 3
var9 3
var10 3
Thanks
RS
[[alternat...
2008 Mar 07
0
linear discriminant analysis
...5 4 9 8 9 10 9 10
var3 7 7 7 12 12 12 9 6 6
var4 4 5 4 10 12 9 2 2 2
var5 4 5 4 10 9 10 3 2 3
var6 5 4 5 2 3 2 1 3 5
var7 5 4 5 7 7 7 3 3 3
var8 3 4 3 10 10 8 4 2 4
var9 3 4 3 2 2 2 2 2 2
var10 3 3 3 4 4 4 3 1 2
Table 2
unknown
var1 23
var2 4
var3 7
var4 4
var5 4
var6 6
var7 5
var8 3
var9 3
var10 3
Thanks
RS
[[alternat...
2011 Nov 04
1
How to use 'prcomp' with CLUSPLOT?
...that using pca. I have tried using CLUSPLOT(), but that only allows for 'princomp' where I need 'prcomp' as I do not want to reduce my columns. Is there a way to edit the CLUSPLOT() code to use 'prcomp', please?
# sample of my data
PRVID,VAR1,VAR2,VAR3,VAR4,VAR5,VAR6,VAR7,VAR8,VAR9,VAR10,VAR11
PRV1,0,54463,53049,62847,75060,184925,0,0,0,0,0
PRV2,0,2100,76,131274,0,0,0,0,0,0,18
PRV3,967,0,0,0,0,0,0,0,0,3634,0
PRV4,817,18344,3274,9264,1862,0,0,141,0,0,0
PRV5,0,0,0,0,0,0,29044,0,0,0,0
PRV6,59,6924,825,3008,377,926,0,0,10156,0,5555
PRV7,11,24902,36040,47223,20086,0,0,749,415...
2012 Oct 25
1
cut point in ROC
var1
var2
var3
var4
var5
var6
var7
var8
var9
var10
gold
2
3
1
2
4
0
1
4
4
3
2
2
4
2
4
3
4
2
4
4
4
2
3
3
0
0
4
1
0
2
4
4
2
1
4
0
3
2
0
0
2
4
4
2
3
4
0
2
2
0
0
0
3
4
2
2
2
3
2
2
0
0
0
2
4
2
2
4
1
1
2
0
0
3
3
3
2
3
4
1
4
0
0
0
0
3
4
2
3
1
0
2
2...
2009 Nov 10
1
Data transformation
...7 0.9
2 1 8 0.4
2 6 2 0.2
2 4 3 0.6
3 5 6 0.7
3 7 5 0.9
I just want to rewrite it as this (vertical to horizontal):
id var1 var2 var3 var4 var5 var6 var7 var8
1 0 0 0 0.1 0.9 0 0.9 0.1
2 0.4 0.2 0.6 0.6 0 0.2 0 0.4
3 0 0 0 0 0.8 0.7 0.9 0
For the third subject, there are two values being equal to 5 in code1 and
code2, but different values in p: 0.7 and 0.9...
2004 Jan 08
1
(no subject)
...have trouble converting a character string to a R object. Let me describe this by an example;
> dim(a)
[1] 270 14
> dim("a")
NULL
> names(a)
[1] "Var1" "Var2" "Var3" "Var4" "Var5" "Var6" "Var7" "Var8" "Var9"
[10] "Var10" "Var11" "Var12" "Var13" "Var14"
> names("a")
NULL
I realise that the character string lacks both a dimension and any column names; my question is how to make R understand that I look for the object...
2004 Jan 08
0
(no subject)
...ject.
> Let me describe this by an example;
>
> > dim(a)
> [1] 270 14
> > dim("a")
> NULL
>
> > names(a)
> [1] "Var1" "Var2" "Var3" "Var4" "Var5" "Var6" "Var7"
> "Var8" "Var9"
> [10] "Var10" "Var11" "Var12" "Var13" "Var14"
> > names("a")
> NULL
>
> I realise that the character string lacks both a dimension
> and any column names; my question is how to make R unders...
2004 Feb 13
3
Calculate Closest 5 Cases?
...he data are all percents, so they are easy comparable.
Is there any way to do this in R?
Below is a small sample of the data (from SPSS) and the desired output.
Thanks,
Danny
*Sample Data.
DATA LIST LIST /id(F8) var1(F8.2) var2(F8.2) var3(F8.2) var4(F8.2) var5
(F8.2) var6(F8.2) var7(F8.2) var8(F8.2) var9(F8.2) var10(F8.2) var11(F8.2).
BEGIN DATA.
10170069 3.51 4.02 6.53 11.05 6.53 8.04 13.57 20.10 11.05 8.55
7.04
10190229 1.89 5.66 4.61 7.62 8.45 13.21 9.50 20.82 16.07 9.36
3.77
10540023 3.40 5.08 3.39 4.52 10.18 14.71 13.56 16.38 9.60 7.89
11.85
10650413 6.64 6.64 3.73 4.70 3.78 13.2...
2008 Oct 08
1
Error in spdep: system is computationally singular
...ot;var2"=~1+tmax+poly(tmax,2)+poly(tmax,3),"var3"=~1+mdr+poly(mdr,2)+poly(mdr,3),"var4"=~1+twq+poly(twq,2)+poly(twq,3),"var5"=~1+tmin+poly(tmin,2)+poly(tmin,3),"var6"=~1+pdq+poly(pdq,2)+poly(pdq,3),"var7"=~1+trng+poly(trng,2)+poly(trng,3),"var8"=~1+mdr+poly(mdr,2)+poly(mdr,3))
final.glm1<-step.gam(glm1,glm.scope,direction="back")
**I want to estimate the spatial simultaneous autoregressive error model**
res20<-errorsarlm(finalglm1, listw=nb20.w, zero.policy=TRUE)
But here I receive the following error message:
Err...
2012 Sep 27
1
List of Variables in Original Order
I am trying to Sweave the output of calculating correlations between one
variable and several others. I wanted to print a table where the
odd-numbered rows contain the variable names and the even-numbered rows
contain the correlations. So if VarA is correlated with all the variables in
mydata.df, then it would look like
var1 var2 var3
corr1 corr2 corr3
var4 var5