search for: var2

Dear List, I have Multi-level Data i= Indivitual Level g= Group Level var1= First Variable of interest var2= Second Variable of interest and I want to count the frequency of "var1" and "var2" on the group level. I found a way, but there must be a much simpler way. data.ml <- data.frame(i=c(1:8),g=as.factor(c(1,1,1,2,2,3,3,3)),var1=c(3,3,3,4,4,4,4 ,4), var2=c(8,8,8,2,2,4,4,4)) t...

Hi, I am using R 1.9.1 on on i686 PC with SuSE Linux 9.0. I have a data.frame, e.g.: > myData <- data.frame( var1 = c( 1:4 ), var2 = c (5:8 ) ) If I add a new column by > myData$var3 <- myData[ , "var1" ] + myData[ , "var2" ] everything is fine, but if I omit the commas: > myData$var4 <- myData[ "var1" ] + myData[ "var2" ] the name shown above the 4th column is not &quot...

Hello, I would like to know if this behaviour in R is as expected. I have a data frame 'dat' with column var1 being character (and not factor). Then I create a new column 'var2' by: > dat[,"var2"] <- dat$var1; Column var2 is now a factor. But if I do: > dat$var2 <- dat$var1; Then column var2 is character (and not factor). I don't want to have var2 as factor by doing the first assignment. I tried using 'as.character(dat$var1)'...

Hi all, I have been trying to solve this problem and have had no luck so far. I have numeric vectors VAR1, VAR2, and VAR3 which I am trying to cbind. I also have a character vector "VAR1,VAR2,VAR3". How do I manipulate this character vector such that I can input a transformed version of the character vector into cbind and have it recognize that I'm trying to refer to my numeric vectors VAR1, VA...

Buenos días. Hoy ando un poco (o bastante) espeso y no doy con la tecla de una cosa que seguro que es muy simple.. Pongo un ejemplo. var1 <- c(rep(0,3),rep(1,2)) var2 <- c(rep(1,2),0,0,1) var3 <- c(rep(1,2),rep(0,3)) var4 <- c(rep(1,2),rep(0,3)) datos <- data.frame(fila=1:5,var1, var2, var3, var4) datos datos fila var1 var2 var3 var4 1 1 0 1 1 1 2 2 0 1 1 1 3 3 0 0 0 0 4 4 1 0 0 0 5 5...

Hi, I think this is a very simple question, and it must just be missing something. I am looking for find out how to assign a constant integer value to the variable in llvm ir. The following returns 12, and %var2 = 12. ; ModuleID = 't.c' target datalayout = "e-p:64:64:64-i1:8:8-i8:8:8-i16:16:16-i32:32:32-i64:64:64-f32:32:32-f64:64:64-v64:64:64-v128:128:128-a0:0:64-s0:64:64-f80:128:128-n8:16:32:64-S128" target triple = "x86_64-pc-linux-gnu" define i32 @test() nounwind readnone {...

Hi everybody, I'm trying to analyse a set of data with a non-normal response, 2 fixed effects and 1 nested random effect with strong heteroscedasticity in the model. I planned to use the function lmer : lmer(resp~var1*var2 + (1|rand)) and then use permutations based on the t-statistic given by lmer to get p-values. 1/ Is it a correct way to obtain p-values for my variables ? (see below) 2/ I read somewhere that lme is more adequate when heteroscedasticity is strong. Do I have to use lme instead of lmer ? 3/ It...

hi, this may be trivial, but we can't seem to find anything adequate, (although there is a work around with match() ). We are looking for something along the lines of plot(table1[table1$var2==or("a","b","c","d"),"var1"]) would be handy, with the potential or() function leading to what plot(table1[table1$var2=="a" | table1$var2=="b" | table1$var2=="c" | table1$var2=="d","var1"]) wou...

...e variables from two or more variables in a small R data.frame. I am trying to reproduce the SAS statements from a Proc Sort with Nodupkey for those familiar with SAS. Here's my example data : test <- read.csv("test.csv", sep=",", as.is=TRUE) > test date var1 var2 num1 num2 1 28/01/11 a 1 213 71 2 28/01/11 b 1 141 47 3 28/01/11 c 2 867 289 4 29/01/11 a 2 234 78 5 29/01/11 b 2 666 222 6 29/01/11 c 2 912 304 7 30/01/11 a 3 417 139 8 30/01/11 b 3 108 36 9 30/01/11 c 2 288 96 I am tryi...

...tring. I have tried as.symbol and as.name but it doesnt work for what I'd like to do Essentially, I'd like to feed the function below with two variables. This works fine in the bit working out number of elements in each variable. In the print(sprintf("OK with %s and %s\n", var1, var2)) line I would like var1 and var2 to be magically substituted with a string containing the name of var1 and name of var2. Thanks in advance Paolo haveSameLength <- function(var1, var2) { if (length(var1)==length(var2)) { print(sprintf("OK with %s and %s\n", var1, var2)) }...

...or 4 times. I need to aggregate this data to maintain only one unit by row. But I need to do that based on a comparison between the values of such units. I can't find a function to help me on that. I appreciate any help. Below I provide an example of what I want: This is my data: Units Var1 Var2 Var3 1 B 2 2 1 C 1 3 2 D 3 3 2 C 2 1 2 A 1 2 3 C 2 1 3 A 1 3 4 B 3 3 4 C 2 2 4 A...

Can someone please give me a clue how to 're'write this so I dont need to use loops. a<-ts(matrix(c(1,1,1,10,10,10,20,20,20),nrow=3),names=c('var1','var2','var3')) b<-ts(matrix(c(2,2,2,11,11,11,21,21,21),nrow=3),names=c('var1','var2','var3')) c<-ts(matrix(c(3,3,3,12,12,12,22,22,22),nrow=3),names=c('var1','var2','var3')) data<-list(a,b,c) I now want to find the means of all vector...

R users, I don't know if I can make myself clear but I'll give it a try. I have a data.frame like this x <- "var1,var2,var3,var4 a,b,b,a b,b,c,b c,a,a,a a,b,c,c b,a,c,a c,c,b,b a,c,a,b b,c,a,c c,a,b,c" DF <- read.table(textConnection(x), header=T, sep=",") DF and I would like to sum all the combinations/occurences by a factor (letter in this case) between variables and produce a list of "oc...

Estimados Estoy entrenando hacer funciones que respondan a comandos, en esta caso en la salida gráfica se observa que dice : Exposure=var3 y outcome=var 1 quisiéramos que se reflejan los nombres de la base de datos : var1=estado, var2=cake, var3=chocolate Espero haberme explicado adecuadamente Adjunto tabla con datos #################################### #Comando que llama a una función rm(list=ls()) #setwd("D:/DEMO_new/demo_scripts/OR/") #setwd("D:/Public/Documents/R/EPICALC/funciones/OR/")...

Buenas noches Javier y José, Estoy en contra de usar attach(), asi que propongo la siguiente alternativa con with(): # paquete require(epicalc) # los argumentos en ... pasan de epicalc:::cc # ver ?cc para mas informacion foo <- function(var1, var2, var3, ...){ or1 <- cc(var1, var2, ...) or2 <- cc(var1, var3, ...) list(or1 = or1, or2 = or2) } # datos x <- read.csv("~/Downloads/OR.csv") head(x) # resultados SIN graficas with(x, foo(estado, cake, chocolate, graph = FALSE)) Saludos, Jorge.- 2014-08-21 12:40 GMT+10:00 J...

...h needs to pay attention to the indices of the output...this is to say, the "create an array" function of tapply doesn't quite work because an array is not quite what we want. Consider this data set: df <- data.frame(var1= factor(rep(rep(1:5,25*5),10)), var2= factor(rep(rep(1:5,each=25*5),10), trial= rep(rep(1:25,25),10), id= factor(rep(1:10,each=5*5*25)), score= rnorm(n=5*5*25*10) ) ...this is to say, each of 10 ids has scores for 5 different levels of var1 and 5 different levels of var2...across...

I have a data frame whose first colum contains the names of the variables and whose second colum contains the values to assign to them: : kkk <- data.frame(vars=c("var1", "var2", "var3"), vals=c(10, 20, 30), stringsAsFactors=F) If I do : assign(kkk$vars[1], kkk$vals[1]) it works : var1 [1] 10 However, if I try with mapply this is what I get: : mapply(assign, kkk$vars, kkk$vals) var1 var2 var3 10 20 30...

Suppose I have a dataframe as follows: dat <- data.frame(id = c(1,1,2,2,2), var1 = c(10,10,20,20,25), var2 = c('foo', 'foo', 'foo', 'foobar', 'foo')) Now, if I were to subset by id, such as: > subset(dat, id==1) id var1 var2 1 1 10 foo 2 1 10 foo I can see that the elements in var1 are exactly the same and the elements in var2 are exactly the same....

-- Eredeti üzenet -- Feladó: Dévaványai Agamemnón &lt;devavanyai@citromail.hu&gt;Címzett: r-hel@r-project.org, r-hel@r-project.orgElküldve: 2010. július 29. 16:29Tárgy : duplicates Sorry! I try it again Dear R Users! I have a dataframe with duplicatecases. Var1 duplicated by var2. var1 var2 var3 var4 var5 1 4 500 1 2 1 3 200 2 5 1 8 125 1 9 2 2 120 2 52 2 6 22 1 20 2 9 400 1 22 3 1 100 2 8 3 2 200 5 40...

Hi: I'm sure this is a very easy problem. I've consulted Data Manipulation With R and the R Book and can't find an answer. Sample list of data frames looks as follows: .xx<-list(df<-data.frame(Var1=rep('Alabama', 400), Var2=rep(c(2004, 2005, 2006, 2007), 400)), df2<-data.frame(Var1=rep('Tennessee', 400), Var2=rep(c(2004,2005,2006,2007), 400)), df3<-data.frame(Var1=rep('Alaska', 400), Var2=rep(c(2004,2005,2006,2007), 400)) ) I would like to accomplish the following two tasks. First, I'd like...