search for: value2

How to read xml in UTF-8 format. I have one XML file but i want to read it in UTF-8 format. How this is possible? <barplot> <cd> <name>?</name> <value1>3</value1> <value2>2.9</value2> </cd> <cd> <name>?</name> <value1>3.3</value1> <value2>3</value2> </cd> <cd> <name>??<...

Hi I have found a little problem with an R script. I am trying to merge some data and am finding something unusual going on. As shown below I am trying to assign (MatchedValues[Value2,Value]) to (ClusteredData[k,Value]) which are two separate dataframes. 1) By the following command you can see that the value im transferring is 481844.03 > MatchedValues[Value2,Value] [1] 481844.03 6618 Levels: 1.00E+07 1.01E+07 1.02E+07 1.04E+07 1.05E+07 1.06E+07 ... Raw 2) But when I t...

Dear R helpers I have one data as given below. date                     value1          value2             value3 30-Nov-2010           100                 40                 61 25-Nov-2010           108                 31                 88 14-Sep-2010            11                 180               56 I want the following output date                 name       amount 30-Nov-2010      val...

...t; 1 1 2 3 (and in general warnings make for unpleasant debugging so I prefer when we don't add new ones if avoidable) playing a bit more with it, it would make sense to me that the following have the same output: coefficient <- 3 data.frame(value1 = 5) |> transform(coefficient, value2 = coefficient * value1) #> value1 X3 value2 #> 1 5 3 15 data.frame(value1 = 5, coefficient) |> transform(value2 = coefficient * value1) #> value1 coefficient value2 #> 1 5 3 15 [[alternative HTML version deleted]]

I am writing a simple R program to execute a t-test repeatedly on data contained in a data frame. My data looks like this: Category Value1 Value2 1 .5 .8 1 .3 .9 . . . . . . . . . 2 1.4 1.3 2 1.3...

Dear R users, I want to remove zero's or NA values after this model. year value1 value2 1854 0 12 1855 0 13 1866 12 16 1877 11 24 year value1 value2 1 12 12 2 11 13 3 16 4 24 Thank you! -- --- Catalin-Constantin ROIBU Forestry engineer, PhD Forestry Faculty of Suceava Str. Universitatii no. 13, Suceava, 720229, Romania office phone +4 0230 52 29 78, ext. 531 mobile phone +4...

...ggregate formula (its "cbind" part) to be able to use my "myvars" object. Is it possible? Thanks for your help! Dimitri Reproducible example: mydate = rep(seq(as.Date("2008-12-01"), length = 3, by = "month"),4) value1=c(1,10,100,2,20,200,3,30,300,4,40,400) value2=c(1.1,10.1,100.1,2.1,20.1,200.1,3.1,30.1,300.1,4.1,40.1,400.1) example<-data.frame(mydate=mydate,value1=value1,value2=value2) example$group<-c(rep("group1",3),rep("group2",3),rep("group1",3),rep("group2",3)) example$group<-as.factor(example$group) (...

...asant in practice when debugging, myself, but that may be a personal preference. > > > playing a bit more with it, it would make sense to me that the following > have the same output: > > > coefficient <- 3 > > > data.frame(value1 = 5) |> transform(coefficient, value2 = coefficient * > value1) > > #> value1 X3 value2 > > #> 1 5 3 15 > > > data.frame(value1 = 5, coefficient) |> transform(value2 = coefficient * > value1) > > #> value1 coefficient value2 > > #> 1 5 3 15 > >...

Dear R-community, my data set looks like 'mat' below. Plant<-c(NA,1,1,1,NA,NA,NA,NA,NA,1); Value1<-rnorm(1:10); Value2<-rnorm(1:10); mat<-cbind(Plant,Value1,Value2); I receive data from two different sites. One site is identified by an interger number, the other site has no data in column Plant=NA. My pb: I'm trying to assign labels "A" or "B" to these 2 sites into a new column, but...

Dear R experts, I am a beginner with R and I have a question regarding the output of a function. Basically, I created 2 functions, value1 and value2, that calculate two values, and I would like to print those two values to an output datafile. I tryed the following function: function (x) {write.table(data.frame(value1(x),value2(x)),file=output.txt)} My problem is that I would like to calculate those values for different values of x and to get...

...m the residuals I get after having applied a linear regression to each column of a data frame, but I don't know how to create this data frame from the resulting list since the list has differing numbers of rows. So for example: age<- c(5,6,10,14,16,NA,18) value1<- c(30,70,40,50,NA,NA,NA) value2<- c(2,4,1,4,4,4,4) df<- data.frame(age, value1, value2) #Run linear regression to adjust for age and get residuals: lm_f <- function(x) { x<- residuals(lm(data=df, formula= x ~ age)) } resid <- apply(df,2,lm_f) resid<- resid[-1] Then resid is a list with different row numbers:...

Hi, Is there an easy way to remove dataframe rows without duplicated values of a specified column ('id')? e.g., dat <- data.frame(id = c(1,1,1,2,3,3), value = c(5,6,7,4,5,4), value2 = c(1,4,3,3,4,3)) dat id value value2 1 1 5 1 2 1 6 4 3 1 7 3 4 2 4 3 5 3 5 4 6 3 4 3 This is sample data and the real data has hundreds of rows. In this case, only row 4 does not have a duplicated id and I would like to remove it wit...

...t defining the series location within plotCI. For example the tool “boxplot” contains the “at” argument. I found examples of plotCI where a vertical shift is realized (e.g.  “x=means+1e5”), never a horizontal shift. Here you find data information: ##data value1<-c(1,2,1,2,1,3,4,2,6,1,3,4,2,6) value2<-c(1,5,1,2,4,4,4,3,3,1,3,4,9,8) typo<-c("C","C","C","C","A","A","A","A","A","B","B","B","B","B") tab1<-data.frame(data=cbind(value1,value2,typo)) coln...

Dear list, I'll try to be more clear in explaining my problem. I have a data frame like this called X: CLUSTER YEAR variable value1 value2 M1 2005 EC01 NA NA M1 2006 EC01 2 5 M1 2007 EC01 4 5 M2 2005 EC01 NA...

Hi, I have a data fram like this: date column1 column2 column3 value1 value2 value3 1-1 A B C 10 5 2 2-1 A B D 5 2 0 3-1 A B E 17 10 7 How can I reshape it to: date column1 column2 column3 v x 1-1 A B C value1 10 1-1 A B C value2 5 1-1 A B C value3 2 2-1 A B D value1 5 2-1 A B D value2 2 2-1 A B D value3 0 3-1 A B E value1 17 3-1 A B E value2 10 3-1 A B E value3 7 Thx!...

...ion from: (NULL) (193.174.73.34) Hi, The pdf file R-intro descripe on page 27 that lists can be extended by adding numbers. Unfortunately, it's not working ## example : # if i did not declare the variable an error occurs : object not found mylist <- list() mylist[1] <- list(value1=3, value2=5) ## Error Can you please help me Thank you Regards Frank Wagner

...ing to generate a link to external site with GET parameters ( in new window). I tried following code, but it does not produce any parameters. <%=link_to "Open New Page", "https://www.foo.com/page/", {:popup => true}, {:param1 => "value1", :param2 => "value2"}%> and <%=link_to "Open New Page", url_for("https://www.foo.com/page/", {param1 => "value1", :param2 => "value2"}) , {:popup => true}%> Can anyone tell me what is wrong with my code or there is a alternative way? Thanks in advance...

Hi all R users Ive got a file that contains diffrent settings in the manor of: setting1="value1" setting2="value2" setting3="value3" setting4="value4" . . . What I want to do is open the file and change the value of a specific setting like wanna change setting4="value4" -> setting4="value5" and then save the file again. setting1="value1" setting2=&quo...

...a variation which includes parenthesis seems to fail, in that it returns hits which should be excluded by the NOT term. This is surprising because in this simple case, the parenthesis shouldn''t change the Boolean evaluation ... any pointers? Working Query: field1:value1 AND NOT field2:value2 Failing Query: field1:value1 AND ( NOT field2:value2 ) Kind Regards Neville

I'm a bit of an amateur R programmer. I can do simple R scenarios but my handle on complex grammatical issues isn't steady. I have 12 CSV files that I've read into dataframes. Each has 8 columns and over 2000000 rows. Each dataframe has data associated by time component and a date component in the format of: X.DATE and then X.TIME X.DATE is in the format of MMDDYYYY and X.TIME is