search for: value1

....frame(a = 1, 2, 3) #> a X2 X3 #> 1 1 2 3 (and in general warnings make for unpleasant debugging so I prefer when we don't add new ones if avoidable) playing a bit more with it, it would make sense to me that the following have the same output: coefficient <- 3 data.frame(value1 = 5) |> transform(coefficient, value2 = coefficient * value1) #> value1 X3 value2 #> 1 5 3 15 data.frame(value1 = 5, coefficient) |> transform(value2 = coefficient * value1) #> value1 coefficient value2 #> 1 5 3 15 [[alternative HTML versio...

How to read xml in UTF-8 format. I have one XML file but i want to read it in UTF-8 format. How this is possible? <barplot> <cd> <name>?</name> <value1>3</value1> <value2>2.9</value2> </cd> <cd> <name>?</name> <value1>3.3</value1> <value2>3</value2> </cd>...

...gt; I find silence to be much more unpleasant in practice when debugging, myself, but that may be a personal preference. > > > playing a bit more with it, it would make sense to me that the following > have the same output: > > > coefficient <- 3 > > > data.frame(value1 = 5) |> transform(coefficient, value2 = coefficient * > value1) > > #> value1 X3 value2 > > #> 1 5 3 15 > > > data.frame(value1 = 5, coefficient) |> transform(value2 = coefficient * > value1) > > #> value1 coefficient value2 > > #&...

Dear R helpers I have one data as given below. date                     value1          value2             value3 30-Nov-2010           100                 40                 61 25-Nov-2010           108                 31                 88 14-Sep-2010            11                 180               56 I want the following output date                 name       amount 30-N...

I am writing a simple R program to execute a t-test repeatedly on data contained in a data frame. My data looks like this: Category Value1 Value2 1 .5 .8 1 .3 .9 . . . . . . . . . 2 1.4 1.3 2...

Dear R users, I want to remove zero's or NA values after this model. year value1 value2 1854 0 12 1855 0 13 1866 12 16 1877 11 24 year value1 value2 1 12 12 2 11 13 3 16 4 24 Thank you! -- --- Catalin-Constantin ROIBU Forestry engineer, PhD Forestry Faculty of Suceava Str. Universitatii no. 13, Suceava, 720229, Romania office phone +4 0230 52 29 78, ext. 531 mobile pho...

...ar2","var3") I'd like my aggregate formula (its "cbind" part) to be able to use my "myvars" object. Is it possible? Thanks for your help! Dimitri Reproducible example: mydate = rep(seq(as.Date("2008-12-01"), length = 3, by = "month"),4) value1=c(1,10,100,2,20,200,3,30,300,4,40,400) value2=c(1.1,10.1,100.1,2.1,20.1,200.1,3.1,30.1,300.1,4.1,40.1,400.1) example<-data.frame(mydate=mydate,value1=value1,value2=value2) example$group<-c(rep("group1",3),rep("group2",3),rep("group1",3),rep("group2",3)...

Dear R-community, my data set looks like 'mat' below. Plant<-c(NA,1,1,1,NA,NA,NA,NA,NA,1); Value1<-rnorm(1:10); Value2<-rnorm(1:10); mat<-cbind(Plant,Value1,Value2); I receive data from two different sites. One site is identified by an interger number, the other site has no data in column Plant=NA. My pb: I'm trying to assign labels "A" or "B" to these 2 sites...

Dear R experts, I am a beginner with R and I have a question regarding the output of a function. Basically, I created 2 functions, value1 and value2, that calculate two values, and I would like to print those two values to an output datafile. I tryed the following function: function (x) {write.table(data.frame(value1(x),value2(x)),file=output.txt)} My problem is that I would like to calculate those values for different values of x...

...am trying to create a data frame from the residuals I get after having applied a linear regression to each column of a data frame, but I don't know how to create this data frame from the resulting list since the list has differing numbers of rows. So for example: age<- c(5,6,10,14,16,NA,18) value1<- c(30,70,40,50,NA,NA,NA) value2<- c(2,4,1,4,4,4,4) df<- data.frame(age, value1, value2) #Run linear regression to adjust for age and get residuals: lm_f <- function(x) { x<- residuals(lm(data=df, formula= x ~ age)) } resid <- apply(df,2,lm_f) resid<- resid[-1] Then resid is...

...uot;B") +assert B values = [ { "key": "Key1", "t": 3, "value": "ABC" }, { "key": "Key2", "t": 3, "value": "DEF" } ] -h.node_set_values (b, values) +h.node_set_values (B, values) value1 = { "key": "Key3", "t": 3, "value": "GHI" } -h.node_set_value (b, value1) +h.node_set_value (B, value1) value1 = { "key": "Key1", "t": 3, "value": "JKL" } -h.node_set_value (b, value1) +h.node_set...

...m trying to use tapply to find group means in a function. It works outside of a function, but I get the error message from the following code: "Error in tapply(index, cluster, mean) : arguments must have same length." Any suggestions? Thanks. eric d <- data.frame(cbind(cluster=1:2, value1=1:10, value2=11:20)) d FindClusterTraits <- function(framename, index){ MeanCluster <- with(framename, tapply(index, cluster, mean)) return(MeanCluster) } d2 <- FindClusterTraits(d, 'value1') [[alternative HTML version deleted]]

...argument works well. Is there any argument defining the series location within plotCI. For example the tool “boxplot” contains the “at” argument. I found examples of plotCI where a vertical shift is realized (e.g.  “x=means+1e5”), never a horizontal shift. Here you find data information: ##data value1<-c(1,2,1,2,1,3,4,2,6,1,3,4,2,6) value2<-c(1,5,1,2,4,4,4,3,3,1,3,4,9,8) typo<-c("C","C","C","C","A","A","A","A","A","B","B","B","B","B") tab1<-data....

Hi all, I am trying to replace all uses of a value1 *inside of a given function* to use value2. My strategy was to iterate all the basic blocks, again iterating all the instructions in each basic block, and using replaceUsesOfWith(value1, value2) for every instruction. This used to work all right, but now I am finding some problems. There are instr...

Dear list, I'll try to be more clear in explaining my problem. I have a data frame like this called X: CLUSTER YEAR variable value1 value2 M1 2005 EC01 NA NA M1 2006 EC01 2 5 M1 2007 EC01 4 5 M2 2005 EC01...

Hi, I have a data fram like this: date column1 column2 column3 value1 value2 value3 1-1 A B C 10 5 2 2-1 A B D 5 2 0 3-1 A B E 17 10 7 How can I reshape it to: date column1 column2 column3 v x 1-1 A B C value1 10 1-1 A B C value2 5 1-1 A B C value3 2 2-1 A B D value1 5 2-1 A B D value2 2 2-1 A B D value3 0 3-1 A B E value1 17 3-1 A B E value2 10 3-1 A B E value3 7...

...ws Submission from: (NULL) (193.174.73.34) Hi, The pdf file R-intro descripe on page 27 that lists can be extended by adding numbers. Unfortunately, it's not working ## example : # if i did not declare the variable an error occurs : object not found mylist <- list() mylist[1] <- list(value1=3, value2=5) ## Error Can you please help me Thank you Regards Frank Wagner

Hello. I have tested such form: <form method=''POST''> <input type=''hidden'' name=''myfield'' value=''value1''> <input type=''hidden'' name=''myfield'' value=''value2''> <input type=''submit'' name=''_submit'' value=''OK''> </form> ================ After submitting my form: &l...

...l per group for this data.frame: df <- data.frame(site = c("a", "a", "a", "b", "b", "b"), gr = c("total", "x1", "x2", "x1", "total","x2"), value1 = c(212, 56, 87, 33, 456, 213)) df calcPercent <- function(df) { df <- transform(df, pct_val1 = ave(df[, -c(1:2)], df$gr, FUN = function(x) x/df[df$gr == "total", "value1"]) ) } # This works as intended....

Hi all R users Ive got a file that contains diffrent settings in the manor of: setting1="value1" setting2="value2" setting3="value3" setting4="value4" . . . What I want to do is open the file and change the value of a specific setting like wanna change setting4="value4" -> setting4="value5" and then save the file again. setting1=&quo...