search for: unsorting

I believe the performance of isUnsorted() in sort.c could be improved by calling REAL() once (outside of the for loop), rather than calling it twice inside the loop. As an aside, it is implemented in the faster way in doSort() (sort.c line 401). The example below shows the performance improvement for a vectors of double of moving REAL() outside the for loop. # example as implemented in

Hi, I've read ?is.unsorted and searched. Have found a few items but nothing close, yet. Is the following expected? > is.unsorted(data.frame(1:2)) [1] FALSE > is.unsorted(data.frame(2:1)) [1] FALSE > is.unsorted(data.frame(1:2,3:4)) [1] TRUE > is.unsorted(data.frame(2:1,4:3)) [1] TRUE IIUC, is.unsorted is intended for atomic vectors only (description of x in ?is.unsorted). Indeed

Hi, In the man page for is.unsorted(): Value: A length-one logical value. All objects of length 0 or 1 are sorted: the result will be ?NA? for objects of length 2 or more except for atomic vectors and objects with a class (where the ?>=? or ?>? method is used to compare ?x[i]? with ?x[i-1]? for ?i? in ?2:length(x)?). This contains many incorrect

Hi, Couldn't is.unsorted() bail out immediately here (after comparing the first 2 elements): > x <- 20000000:1 > system.time(is.unsorted(x), gcFirst=TRUE) user system elapsed 0.084 0.040 0.124 > x <- 200000000:1 > system.time(is.unsorted(x), gcFirst=TRUE) user system elapsed 0.772 0.440 1.214 Thanks! H.

I've just realized that it could be handy to have a 'decreasing' argument in 'is.unsorted'. And I'm cheekily hoping someone else will implement it. It is easy enough to work around (with 'rev'), but would be less hassle with an argument. The case I have in mind uses 'is.unsorted' in 'stopifnot'. Pat -- Patrick Burns pburns at pburns.seanet.com

Hi all, This must be such a beginner''s problem, but I can''t figure it out. I''m pulling two integers out of a database, and i want to divide one value with the other, but i keep getting an error about operating on strings. Here''s the code - low_freq = unsorted.last.freq high_freq = unsorted.first.freq divider = high_freq / low_freq In my view, if i display

https://bugzilla.samba.org/show_bug.cgi?id=7861 Summary: documentation: files-frombehaves badly on unsorted input Product: rsync Version: 3.0.5 Platform: x64 OS/Version: Linux Status: NEW Severity: minor Priority: P3 Component: core AssignedTo: wayned at samba.org ReportedBy: rlpowell at

Hi, Background: I''m writing a piece of code to display etsy.com items in a squidoo module. Squidoo provide a module development kit which uses ajax and php. See the example here: http://www.demido.co.uk/etsy (Currently only works in FF). The user enters a valid etsy userID, hit go, an ajax.updater passes the userid to a php script the php script goes off and finds the items returns

Dear friends, My dataset is like the following: x y mcpvalue 0.4603578 0.6247629 1.001 0.4603715 0.6247788 1.001 0.4603852 0.6247948 1.001 0.4110561 0.5664841 0.995 The x and y variables are unsorted. I use the function image(x,y,mcpvalue) to generate a plot, but the error is that "increasing 'x' and

Hi, Some 'bibentry' methods have the side effect of changing the default bibstyle. Background: tools::bibstyle() defines and registers bibtex styles for formatting 'bibentry' objects. It optionally (and by default) sets a default style. It is also used to get a particular style. The last feature of bibstyle() is used in 'bibentry' methods defined in packages

Hi list, I'm struggling with plotting a 3d data set. I have a data frame with x,y and z values. They occur in no particular order (ie x and y are not ordered). However, I want to visualize the data using a contour plot. Now, the x,y and z data going into contour() are supposed to be ordered. My question is: Is their a quick way to re-arrange my data such that it can be fed to contour()?

https://bugzilla.samba.org/show_bug.cgi?id=10074 Summary: rsync reorders --from-files alphabetically Product: rsync Version: 3.0.6 Platform: All OS/Version: All Status: NEW Severity: enhancement Priority: P5 Component: core AssignedTo: wayned at samba.org ReportedBy: nicholas.man at

Hi there R-Helpers, Does anyone know if it is possible to sort a dataframe? I.e. Sort alphabetically column 1 ( which has some reocurring elements) then sort alphabetically column2 but keeping the order of column 1 constant; much the same way that the sort function works in Excel. Regards, Wayne Dr Wayne R. Jones Statistician / Research Analyst KSS Group plc St James's Buildings 79

Dear all, I want to replace an (unsorted) id variable in a large dataset by a running number without changing the order of the cases. E.g., y <- c(4,4,4,2,45,12,12) should be replaced by something like x <- c(1,1,1,2,3,4,4) Sorry for this simple question & thank you very much for your help! [[alternative HTML version deleted]]

Hi, This looks OK: > x <- c("_1_", "1_9", "2_9") > rank(x) [1] 1 2 3 But this does not: > xa <- paste(x, "a", sep="") > xa [1] "_1_a" "1_9a" "2_9a" > rank(xa) [1] 2 1 3 Cheers, H. > sessionInfo() R version 2.14.0 (2011-10-31) Platform: x86_64-unknown-linux-gnu (64-bit) locale: [1]

Hi Brian and Uwe, Given my package passes all checks but I have received no further responses since your initial reply, I assume you are no longer interested in the package Rigroup-0.84.0. Your concerns about my chosen license being too vague "GPL | LGPL" is in direct contradiction to what your own documents say about not changing your license after a package has been accepted at CRAN.

For some reason this didn't make the list and I got no approval message... this time I'll force the From to be my subscribed address. Bug in Monty's new filtering system? Anyway, here goes again. ----- Forwarded message from ----- Date: Thu, 1 Aug 2002 10:24:46 -0400 To: vorbis-dev@xiph.org Subject: Re: [vorbis-dev] [fwd] CVS: ogg123 rocks! vcut no so much so... (from:

I am wondering why sieve-filter is so slow compared to gnu sieve. I run mpop (like getmail) to download from a pop3 server to a local mbox file: ~/mail/email-incoming-unsorted This step is very fast. The next step, I throw the email-incoming-unsorted mbox file at a sieve processor, to sort the emails from that mbox, into other mboxes, according to the sieve rules file. Up until a couple days

I am backing up files from Linux to a NTFS using rsync. I have the NTFS mounted on Linux via CIFS. I am discovering errors while attempting to backup files with restricted NTFS characters, like : [colon]. For example, I am unable to backup my crucial maildirs, as a colon is encoded in each Linux file path. Is there a solution to rsync Linux file paths with restricted NTFS characters, to NTFS?

I did a search on www.rseek.org to look for the function to test if a vector is ordered or not. But I don't find it. Could somebody let me know what function I should use?