search for: unsort

I believe the performance of isUnsorted() in sort.c could be improved by calling REAL() once (outside of the for loop), rather than calling it twice inside the loop. As an aside, it is implemented in the faster way in doSort() (sort.c line 401). The example below shows the performance improvement for a vectors of double of moving RE...

Hi, I've read ?is.unsorted and searched. Have found a few items but nothing close, yet. Is the following expected? > is.unsorted(data.frame(1:2)) [1] FALSE > is.unsorted(data.frame(2:1)) [1] FALSE > is.unsorted(data.frame(1:2,3:4)) [1] TRUE > is.unsorted(data.frame(2:1,4:3)) [1] TRUE IIUC, is.unsorted is inte...

Hi, In the man page for is.unsorted(): Value: A length-one logical value. All objects of length 0 or 1 are sorted: the result will be ?NA? for objects of length 2 or more except for atomic vectors and objects with a class (where the ?>=? or ?>? method is used to compare ?x[i]? with ?x[i-1]? for ?...

Hi, Couldn't is.unsorted() bail out immediately here (after comparing the first 2 elements): > x <- 20000000:1 > system.time(is.unsorted(x), gcFirst=TRUE) user system elapsed 0.084 0.040 0.124 > x <- 200000000:1 > system.time(is.unsorted(x), gcFirst=TRUE) user system elapsed 0....

I've just realized that it could be handy to have a 'decreasing' argument in 'is.unsorted'. And I'm cheekily hoping someone else will implement it. It is easy enough to work around (with 'rev'), but would be less hassle with an argument. The case I have in mind uses 'is.unsorted' in 'stopifnot'. Pat -- Patrick Burns pburns at pburns.seanet.com twit...

Hi all, This must be such a beginner''s problem, but I can''t figure it out. I''m pulling two integers out of a database, and i want to divide one value with the other, but i keep getting an error about operating on strings. Here''s the code - low_freq = unsorted.last.freq high_freq = unsorted.first.freq divider = high_freq / low_freq In my view, if i display the contents of low_freq or high_freq there is indeed an integer in there. Can someone help a newb? cheers -- Posted via http://www.ruby-forum.com/.

https://bugzilla.samba.org/show_bug.cgi?id=7861 Summary: documentation: files-frombehaves badly on unsorted input Product: rsync Version: 3.0.5 Platform: x64 OS/Version: Linux Status: NEW Severity: minor Priority: P3 Component: core AssignedTo: wayned at samba.org ReportedBy: rlpowell at digitalkingdom.org...

...uot;, I remove the element using Element.remove, i then recall the function to create the lists again and put the serialised lists again into the two hidden elements. This was the only way I could work out how to remove an item. Questions: 1. Is there away to make just one li within the ul element unsortable, and removed from the list for when i call sortable.serialise? (I don''t mean sortable.destroy, I tried this and it makes the ul element unsortable, not a specific li). 2. I call the ajax.updater and then the function sortable.create, but "sometimes" when the go button is hi...

Dear friends, My dataset is like the following: x y mcpvalue 0.4603578 0.6247629 1.001 0.4603715 0.6247788 1.001 0.4603852 0.6247948 1.001 0.4110561 0.5664841 0.995 The x and y variables are unsorted. I use the function image(x,y,mcpvalue) to generate a plot, but the error is that "increasing 'x' and 'y' values are expected". So i use image(x=seq(min(x),max(x)), y=seq(min(y),max(y)),z=as.matrix (result$mcpvalue)) to do it again, but there is still an error "...

...id", "R."), "Cox")), year = 1964, title = "An Analysis of Transformations", journal = "Journal of the Royal Statistical Society, Series B", volume = 26, pages = "211-252")) bibstyle("unsorted", sortKeys = function(refs) seq_along(refs), fmtPrefix = function(paper) paste0("[", paper$.index, "]"), .init = TRUE) ======================= As expected, the bibstyle() call sets "unsorted" as default bibstyle but here is how calls to so...

Hi list, I'm struggling with plotting a 3d data set. I have a data frame with x,y and z values. They occur in no particular order (ie x and y are not ordered). However, I want to visualize the data using a contour plot. Now, the x,y and z data going into contour() are supposed to be ordered. My question is: Is their a quick way to re-arrange my data such that it can be fed to contour()?

https://bugzilla.samba.org/show_bug.cgi?id=10074 Summary: rsync reorders --from-files alphabetically Product: rsync Version: 3.0.6 Platform: All OS/Version: All Status: NEW Severity: enhancement Priority: P5 Component: core AssignedTo: wayned at samba.org ReportedBy: nicholas.man at

Hi there R-Helpers, Does anyone know if it is possible to sort a dataframe? I.e. Sort alphabetically column 1 ( which has some reocurring elements) then sort alphabetically column2 but keeping the order of column 1 constant; much the same way that the sort function works in Excel. Regards, Wayne Dr Wayne R. Jones Statistician / Research Analyst KSS Group plc St James's Buildings 79

Dear all, I want to replace an (unsorted) id variable in a large dataset by a running number without changing the order of the cases. E.g., y <- c(4,4,4,2,45,12,12) should be replaced by something like x <- c(1,1,1,2,3,4,4) Sorry for this simple question & thank you very much for your help! [[alternative HTML ve...

Hi, This looks OK: > x <- c("_1_", "1_9", "2_9") > rank(x) [1] 1 2 3 But this does not: > xa <- paste(x, "a", sep="") > xa [1] "_1_a" "1_9a" "2_9a" > rank(xa) [1] 2 1 3 Cheers, H. > sessionInfo() R version 2.14.0 (2011-10-31) Platform: x86_64-unknown-linux-gnu (64-bit) locale: [1]

...etter handle very very large datasets (ala BigData) more effieciently. That is assuming there is not some other package that does this that I am unaware of or that a similar capability hasn't already been added to R-3.X since 2006. The primary idea is simple and time worn ... Given a large unsorted vector of data whose elements have been assigned to n groups and whose group membership is represented by a second vector of equal length whoses values are members of {1,...,n}, you can easily calculate multiple group statistics for all n groups in just one pass through the unsorted data vector b...

...enames with '\0' instead of '\n' or ' '. The tr command makes newlines into '\0' for playlists that delimit by newline. Everything should be standard for any Unix system and should run in any POSIX-compliant shell (if not, yell at me): 1. All oggs under '.', unsorted: find . -name '*.ogg' -print0 | xargs -0 ogg123 2. All oggs under '.', sorted by name: find . -name '*.ogg' -print0 | sort -z | xargs -0 ogg123 3. All oggs under '.', sorted by starting number find . -name '*.ogg' -print0 | sort -z -n | xargs -0 og...

I am wondering why sieve-filter is so slow compared to gnu sieve. I run mpop (like getmail) to download from a pop3 server to a local mbox file: ~/mail/email-incoming-unsorted This step is very fast. The next step, I throw the email-incoming-unsorted mbox file at a sieve processor, to sort the emails from that mbox, into other mboxes, according to the sieve rules file. Up until a couple days ago I was using Gnu sieve. Gnu sieve balks on emails which have no x-messa...

I am backing up files from Linux to a NTFS using rsync. I have the NTFS mounted on Linux via CIFS. I am discovering errors while attempting to backup files with restricted NTFS characters, like : [colon]. For example, I am unable to backup my crucial maildirs, as a colon is encoded in each Linux file path. Is there a solution to rsync Linux file paths with restricted NTFS characters, to NTFS?

I did a search on www.rseek.org to look for the function to test if a vector is ordered or not. But I don't find it. Could somebody let me know what function I should use?