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nresponse
2002 Dec 06
2
Fitting 2D vs. 2D data with nls()
Dear R-experts!
I have y(x) data, dim(y) == dim(x) == c(2000, 2)
I'd like to fit them with nls:
fit.result <- nls ( y ~ f(x, p1, p2, p3),
start = list(p1 = ... , p2 = .. , p3 = ..)
)
Actually I want to fit y[,1] ~ x[,1] and y[,2] ~ x[,2]
*simulaneously*, with the same parameters set {p1, p2, p3}.
I tried to feed R tha above formula, R errors with: