search for: uniquely

Hi, all together. I have - a maybe trivial - problem with aggregating a list of weights. Here is the problem: - At first I have set of nodes (X/Y-coordinates) and associated weights, where the set of nodes is typically not unique - I want to get a set of unique nodes and the sum of associated weights I am grateful for any help See for example: # weights: w <- c(1, 1, 1, 1, 1) #

https://bugs.freedesktop.org/show_bug.cgi?id=87775 Bug ID: 87775 Summary: [ALL] WARNING: value %x not uniquely defined Product: Mesa Version: git Hardware: Other OS: All Status: NEW Severity: normal Priority: medium Component: Drivers/DRI/nouveau Assignee: nouveau at lists.freedesktop.org Reporter: i...

In > R.version.string [1] "R Under development (unstable) (2011-12-15 r57901)" section 1.6.6 of 'Writing R Extensions' says Note that exporting methods on a generic in the namespace will also export the generic, and exporting a generic in the namespace will also export its methods. and Note that importMethodsFrom will also import any generics defined in

The source of the incompatibility: In S-PLUS 6.2: > methods("unique") splus splus menu splus "unique.data.frame" "unique.default" "unique.name" "unique.rowcol.names" In R-1.9.1: > methods("unique") [1] unique.array unique.data.frame unique.default unique.matrix

I have problems converting my dataset from long to wide format. Previous attempts using reshape package and aggregate function were unsuccessful as they took too long. Apparently, my simplified solution also lasted as long. My complete codes is given below. When sample.size = 10000, the execution takes about 20 seconds. But sample.size = 100000 seems to take eternity. My actual sample.size is

Yesterday I posted the following question (my apologies for not putting a subject line): =================question====================== Hello -- I would like to know of a more efficient way of writing the following piece of code. Thanks. options(stringsAsFactors=FALSE) orig <- c(rep('11111111',100000),rep('22222222',200000),rep('33333333'

Hi, I've had this problem for a while and tackled it is a quite dirty way so I'm wondering is a better solution exists: If we have two vectors: v1 = c(0,1,2,3,4) v2 = c(5,3,2,1,0) How to remove one instance of the "3,1" / "1,3" double? At the moment I'm using the following solution, which is quite horrible: v1 = c(0,1,2,3,4) v2 = c(5,3,2,1,0) ft <-

Hey all, I''ve been staring at the pickaxe, experimenting, and looking through some of the Rails API but I can''t put this simple thing together. I want to create a method that can have zero or more parameters and some of those are symbols. A very simple example would look something like this: find(options = {}) if options[:unique] puts ''Do the unique

Hi, The man page for base::unique.matrix() and base::unique.array() says that MARGIN is expected to be a single integer. OTOH the code in charge of checking the user supplied MARGIN is: if (length(MARGIN) > ndim || any(MARGIN > ndim)) stop(gettextf("MARGIN = %d is invalid for dim = %d", MARGIN, dx), domain = NA) which doesn't really make sense. As

I have a data frame with two factors (sampling 'unit', 'species'). I want to calculate the number of unique 'species' per 'unit.' I can calculate the number of unique values for each variable separately, but can't get a count for each ?unit?. > data=read.csv("C:/Desktop/sr_sort_practice.csv") > attach(data) > data[1:10,] unit species 1

I would like to efficiently find the first index of each unique value in a very large vector. For example, if I have a vector A<-c(9,2,9,5) I would like to return not only the unique values (2,5,9) but also their first indices (2,4,1). I tried using a for loop with which(A==unique(A)[i])[1] to find the first index of each unique value but it is very slow. What I am trying to do is easily

Dear R-helpers, I know how to use unique to select unique rows, e.g. unique.rows<-unique(dataframe) but I would like to select those rows that are unique only only TWO of my dataframe's columns (so, two rows with the same value on these two columns would not be kept, even if they had different values in other columns). For example, I have a dataframe with 10 columns, two of which are

Dear list, I would like to extract from a matrix all those rows, that are unique. By unique, I don't mean the unique that is accomplished by the function unique(), though... Consider the following example: > h [,1] [,2] [1,] 4 4 [2,] 1 4 [3,] 4 1 Now unique(h) returns exactly the same - because 1 4 and 4 1 is not the same for that function. What I would like to

Hi, I have a dataset which has both numeric and character values with dupllicates. For example: 155 A 138 A 138 B 126 C 126 D 123 A 103 A 103 B 143 D 111 C 111 D 156 C How can I count the number of unqiue entries without counting duplicate entries. Also can I extract the list in a object. What I mean is Col1 unique count = 8 Unique Elements are :

Dear R-devel, May I suggest that a new feature be added to a couple of unique() methods? Sometimes it's useful to have the indices of the original data that the unique elements come from, so that the original data can be recreated from the unique()ed data. I suggest that an `index' argument be added for unique. Below is a suggested patch against R/src/library/base/R/duplicated.R: ***

In 2.8.0/Windows Vista: When 'unique' gives a type error message, it prints out even if errors are being caught: > try(unique(quote(hello)),silent=TRUE) hello This comes from the .Internal unique routine: > try(.Internal(unique(quote(hello),NULL,NULL)),silent=TRUE) hello I guess it is using the internal equivalent of print rather than the internal equivalent of stop.

Yesterday I spend the whole day struggling on how to get the maximum value of "y" for every unique value of "x" from the dataframe "test". In the R Book (Crawley, 2007) an example of this can be found on page 121. I tried to do it this way, but I failed. In the end, I figured out how to get it working (first order, and afterwards use !duplicated()). My question

PkgA wishes to write a method for 'unique' on S4 class 'A'. ?Methods indicates that one should setGeneric("unique") setClass("A") unique.A <- function(x, incomparables=FALSE, ...) {} setMethod(unique, "A", unique.A) Both S3 and S4 methods need to be exported in the NAMESPACE import(methods) S3method(unique, A)

Hi I have a list. Two of the elements of this list are "Name" and "Address", both of which are character vectors. Name and Address are linked, so that the same "Name" always associates with the same "Address". What I want to do is pull out the unique values, as a new list of the same format (ie two elements of character vectors). Now I've worked out

Hi everybody I have found something (for me at least) strange with duplicated(). I will first provide a replicable example of a certain kind of behaviour that I find odd and then give a sample of unexpected results from my own data. I hope someone can help me understand this. Consider the following # this works as expected ex=sample(1:20, replace=TRUE) ex duplicated(ex) ex=sort(ex) ex