search for: unimodality

Displaying 20 results from an estimated 41 matches for "unimodality".

Did you mean: bimodality
2010 Aug 30
4
getNodeSet - what am I doing wrong?
Hi, Why is the following retuning a nodset of length 0: > library(XML) > test <- xmlTreeParse( > "http://www.unimod.org/xml/unimod_tables.xml",useInternalNodes=TRUE) > getNodeSet(test,"//modifications_row") Thanks for any hint. Joh
2007 Jan 31
1
Estimation of discrete unimodal density
Dear All, A method for the estimation is univariate unimodal densities (with unknown mode) is described in "Statistical Inference under Order Restrictions" by Barlow et al.. Would anyone know whether there is an R-implementation (preferably with reference) for the estimation of univariate discrete unimodal densities (with unknown mode)? Thanks in advance for your help. Kind
2012 Nov 09
1
Duda sobre modas en un distribución
...onen la existencia o no de unimodalidad/multimodalidad. Una parte de la salidad de diptest es la que pego a continuación (el resto esta en el fichero adjunto con las distribuciones kernels y las soluciones gráficas). *Distribución #1(suponía que hay más de una moda)* Hartigans' dip test for unimodality data: Datos8$V2 D = 0.0432, p-value = 0.3501 alternative hypothesis: non-unimodal, i.e., at least bimodal *Distribución #2* dip.test(Datos9$V2) Hartigans' dip test for unimodality data: Datos9$V2 D = 0.0667, p-value = 1.535e-06 alternative hypothesis: non-unimodal, i.e., at...
2009 Aug 28
1
breaking multi-modal histograms down into combinations of unimodal distributions
Dear All, Does anybody know if there is a functionality in R to break histograms that show a clear bi-modal (or multi-modal) distribution into a series of unimodal histograms that added up result in the original histogram? I was thinking of using QQ-plots (for which tools are available in R), and then observing the number of times the observed quantiles cross the 1:1 line, but this only gives an
2009 May 28
1
optima in unimode
Dear all i could not estimate the optima value or range value in unimodal plot in glm please help me out thanking you regard madan _________________________________________________________________ Hotmail® has a new way to see what's up with your friends. orial_WhatsNew1_052009 [[alternative HTML version deleted]]
2003 Jul 11
1
unimodality test
Dear R users, I am interested in uni- bi- multimodality tests, for analysing reaction times data. I was lead to Hartigan's dip test (Ann. Statistics, 13, 1985, pp. 70-84, Applied Statistics, 34, 1985, 320-325). Not being a programmer I am unable to translate the Fortran code given in ref. 2 into a R function. I'd be glad to learn that someone already did it, or has devised a better
2004 Mar 29
1
calculate length of gradient ?
Content-Type: text/plain; charset="iso-8859-1" Content-Transfer-Encoding: 7bit X-Virus-Scanned: by amavisd-new X-Spam-Checker-Version: SpamAssassin 2.63 (2004-01-11) on hypatia.math.ethz.ch X-Spam-Level: **** X-Spam-Status: No, hits=4.2 required=5.0 tests=MSGID_FROM_MTA_HEADER,RCVD_IN_BL_SPAMCOP_NET autolearn=no version=2.63 Dear r-help list, my question is about ordination technics:
2004 Oct 22
1
p-values for the dip test
Hi all, I am using Hartigan & Hartigan's [1] "dip test" of unimodality via the diptest package in R. The function dip() returns the value of the test statistic but I am having problems calculating the p-value associated with that value. I'm hoping someone here is familiar with this process and can explain it. In the original article there is an example using...
2009 Aug 30
3
test for bimodality&In-Reply-To=
Has a test for bimodality been implemented in R? Thanks, John NIWA is the trading name of the National Institute of Water & Atmospheric Research Ltd.
2010 Dec 20
4
Time Series of Histograms
Dear List, I have a set of distributions recorded at an equal interval of time and I would like to plot them as series of horizontal histograms (with the x-axis representing time, and y-axis representing the bins) since the distribution shifts from unimodal to multimodal in several occasions. What I would like to see is something close to a violinplot, but I do not want a kernel density
2009 Feb 03
1
testing for bimodal distribution
I'm not sure where to begin with this, but I was wondering if someone could refer me to an R package that would test to see if a distribution fits a bimodal distribution better than a unimodal distribution. Thanks, Andrew [[alternative HTML version deleted]]
2009 May 24
1
using optimize() correctly ...
Hi, I am trying to use the optimize function to optimize a function. The results I am getting don't agree with what I compute on my own and when I look at the graph of f(x) = 100 + ((x-10)**2 + (x-10)) * cos(x-10), where -10 <= x <= 10 in gnuplot. I suspect I am making a mistake in the usage of the R optimize function, perhaps someone could point out where? >
2013 Jan 17
2
Explore patterns with GAM
Dear all, I new to r and I would like your help. I want to explore the patterns (unimodal, monotonically increased/decreased) of species richness~altitude using GAM in R. Although I run the gam function in mgcv package I do not know how to manually define knots and degrees of freedom. Any help would be greatly appreciated. Spyros -- View this message in context:
2012 Apr 06
2
Bayesian 95% Credible interval
Hi all, I have the data from the posterior distribution for some parameter. I want to find the 95% credible interval. I think "t.test(data)" is only for the confidence interval. I did not fine function for the Bayesian credible interval. Could some one suggest me? Thanks [[alternative HTML version deleted]]
2009 Apr 06
3
how to subsample all possible combinations of n species taken 1:n at a time?
Hello I apologise for the length of this entry but please bear with me. In short: I need a way of subsampling communities from all possible communities of n taxa taken 1:n at a time without having to calculate all possible combinations (because this gives me a memory error - using combn() or expand.grid() at least). Does anyone know of a function? Or can you help me edit the combn or
2016 Dec 21
2
different compilers and mzR build fails
I'm not sure if I should bother you team with this, apologies in case it's a bother. I'm trying gcc 6.2.1 (from devtoolset-6) with R, everything seems to work just fine, except for mzR. Here is failed build: g++ -m64 -shared -L/usr/lib64/R/lib -Wl,-z,relro -o mzR.so cramp.o ramp_base64.o ramp.o RcppRamp.o RcppRampModule.o rnetCDF.o RcppPwiz.o RcppPwizModule.o RcppIdent.o
2009 Oct 10
2
[R-SIG-Mac] rnorm.halton
Hi all, I need to transform classic 32bit Fortran code to 64bit Fortran code, see the discussion [R-SIG-Mac] rnorm.halton. But I'm clearly a beginner in Fortran... Does someone already do this for his package? From here, http://techpubs.sgi.com/library/tpl/cgi-bin/getdoc.cgi?coll=linux&db=bks&fname=/SGI_Developer/Porting_Guide/ch03.html , I identify the following changes
2004 Mar 17
1
ANCOVA when you don't know factor levels
Hello people I am doing some thinking about how to analyse data on dimorphic animals - where different individuals of the same species have rather different morphology. An example of this is that some male beetles have large horns and small wings, and rely on beating the other guys up to get access to mates, whereas others have smaller horns and larger wings, and rely on mobility to
2001 Oct 31
0
isotonic regression
Dear R-users Do you know of an easy way in R of performing "isotonic (unimodal)" regression ala BBBB, Barlow, Bartolomew, Brenner and Brunk. best regards Helgi -- Helgi Tomasson FAX: 354-552-6806 University of Iceland PHONE:354-525-4571 Faculty of Economics and Business Administration email:helgito at
2005 Nov 03
1
multidimensional integration not over a multidimensionalrectangle
Hi, anyone knows about any functions in R can get multidimensional integration not over a multidimensional rectangle (not adapt). For example, I tried the following function f(x,n)=x^n/n! phi.fun<-function(x,n) { if (n==1) { x }else{ integrate(phi.fun, lower=0, upper=x, n=n-1)$value } } I could get f(4,2)=4^2/2!=8, but failed in f(4,3)=4^3/3! Thanks Best, Lynette