search for: unambiguously

Hello, I was hoping for advice regarding resolving the above error. I have a csv file that contains the following variable: $ Order.Made.Date : Factor w/ 299 levels "1-Apr-08","1-Aug-05",..: 278 285 91 286 159 132 108 261 282 147 ... I want to calculate a variable named F.length, which is today's date minus the values contained in the variable:

Hi I have lots of issues when I try to install R 3.3.3 during the "make check" step. Every time a call to as.POSIXct is done in test scripts, I got the same error message: e.g. x <- as.POSIXct("2002-02-02 02:02") Error in as.POSIXlt.character(x, tz, ...) : character string is not in a standard unambiguous format It looks to be linked to localtime but when I compiled

This patch changes the date format for Time, Date and DateTime #to_json from the ambiguous 10/01/2007 ...to the unambiguous 2007/10/01 http://dev.rubyonrails.org/ticket/9750 --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Ruby on Rails: Core" group. To post to this group, send email to

Full_Name: Michael Jacob Version: 1.4.1 OS: Windows 2000 SP2 Submission from: (NULL) (195.27.237.226) Hi, there seems to be a bug in julian(): > Sys.getlocale() [1] "LC_COLLATE=English_United States.1252;LC_CTYPE=English_United States.1252;LC_MONETARY=C;LC_NUMERIC=C;LC_TIME=English_United States.1252" > julian(Sys.time()) Error in fromchar(x) : character string is not in a

Hi folks, I have been tormented for some time by Excel's habit of exporting dates to CSV files as mm/dd/yyyy format even if the dates are formatted dd/mm/yyyy in the display. What's worse, if there are dates that are of ambiguous (6/6/2011) and unambiguous (16/6/2011) format in the same column, Excel reformats the unambiguous dates and leaves the ambiguous ones as they were! Yesterday

R 3.1.0 OS X Colleagues, I recently updated to 3.1.0 and I have encountered Warning messages: ... Name partially matched in data frame when I do something like: DATAFRAME$colname where colname is actually something longer than that (but unambiguous). I have much appreciated the partial matching capabilities because it fits with my workflow. I often receive updated data months after the

Hi Ben Thanks for your answer I have already tried this, as well as x <- as.POSIXct(strptime("2002-02-02 02:02", "%Y-%m-%d %H:%M")) It works! But it does not fix it widely for all tests used during the "make check" step at compile time. Unless I patch all of them. There is something with localtime but I cannot find what. On another machine with another

On Mon, Jun 29, 2020 at 9:43 PM Mehdi AMINI via llvm-dev < llvm-dev at lists.llvm.org> wrote: > Hey Duncan, > > On Mon, Jun 29, 2020 at 8:28 PM Duncan Exon Smith via llvm-dev < > llvm-dev at lists.llvm.org> wrote: > >> To facilitate collaboration on an upstreaming effort (see "More context" >> below), we'd like to *push a branch* (with history)

Passing in two dates to a sql statement (sqldf). Is returning a factor. Tried setting back to a Date via as.Date, but get an error the error: character string is not in a standard unambiguous format. Any thoughts appreciated. Code/Results listed below: > summary(df.possible.combos) Date Hour Min. :2011-03-01 Min. : 0.00 1st Qu.:2011-03-23 1st Qu.: 5.75

Dear R users, I have a column with dates (character) in a data frame: 12-Jan-01 11-Jan-01 10-Jan-01 9-Jan-01 8-Jan-01 5-Jan-01 and I need to convert them to (Julian) dates so that I can sort the whole data frame by date. I thought it would be very simple, but after checking the documentation and the list I still don't have something that works. 1. as.Date returns the error below. What am I

hey I am trying to turn a dataframe into xts with the function: as.xts, but it returns the error: Error in as.POSIXlt.character(x, tz, ...) : character string is not in a standard unambiguous format could someone give me some pointers please the data is coming from a spreadsheet via the excel, and has 5 columns of data (date (with the date and time), open, high, low, close) (excel format) ela

Dear All, I installed R 2.7.0 and tried to call a dataset i had ealier own called on R2.6.2 but i keep on getting an error: use("maltreat.dta") Error in fromchar(x) : character string is not in a standard unambiguous format Tried doing the same with R2.7.1 but i get the same error. However if i call the same on R 2.6.2, there is no error: use("maltreat.dta") > des()

Dear Brian, I dont understand what you mean. The thread was about the as.Date which you suggested to be used instead of the as.date. Following your advice I tried the as.Date and have questions about the observed behaviour, which was surprising to me. Is this what you call hijacking? Do you mean I ought start a new thread instead? I thought my question were relevant to the threads'

Full_Name: Arto Luoma Version: 1.3.1 OS: Windows 98 Submission from: (NULL) (153.1.53.119) Hi! The function get.hist.quote in the package tseries (Version 0.7-6) does not work in my computer. I found that it uses the function strptime which did not "understand" English month names in my Finnish locale (see bug report 811). I changed the regional settings to be English (UK) and

Dear all, I import my data from a csv-file containing one row with date-entries. How can I tell R to treat this data as dates? I've tried to bring it in character-format (as.charachter()) followed by as.POSIXlt() but I get an error message, that the character string is not in a standard unambiguous format, although the date is of format yyyy-mm-dd (what is standard format according to R

Hi All, I have an script in R which accepts user inputs for certain parameters, particularly dates, which the user inputs as character strings. eg: > date1 <- "2009-01-21" The script later parses the input via the as.Date function: > as.Date(date1) However, as.Date encounters an error when the string does not represent an actual date. eg: > date1 <-

Hey there all, Is there some way to tell rails or sql server to ignore the time in a datetime field when doing a comparison? For example, if I do something like select * from users where registration_date = ?, @date where @date might equal some user input like ''03/14/2006'' The result is nothing returned, because in my tables the datetime field looks like this: 3/14/2006

Hi all, It has been the case for quite a while that the master tree is unambiguously better than 6.03. I have thus tagged and pushed out a syslinux-6.04-pre2 release, however, due to the issues with continuing to keep the main archive on kernel.org, I have moved the release archive to: https://www.zytor.com/pub/syslinux/ Other than the URL, there is no difference from the kernel....

...CAUTION: This email originated from outside of the organization. Do not click links or open attachments unless you recognize the sender and know the content is safe. > > > > > > Hi all, > > > > It has been the case for quite a while that the master tree is > > unambiguously better than 6.03. I have thus tagged and pushed out a > > syslinux-6.04-pre2 release, however, due to the issues with continuing > > to keep the main archive on kernel.org, I have moved the release archive to: > > Please add a non ancient gnu-efi snapshot too. > > Jocke...

On Thu, Dec 13, 2018 at 7:18 AM Alex Bradbury via llvm-dev < llvm-dev at lists.llvm.org> wrote: > On Thu, 13 Dec 2018 at 15:07, Hans Wennborg via llvm-dev > <llvm-dev at lists.llvm.org> wrote: > > > > On Thu, Dec 13, 2018 at 3:34 PM James Y Knight <jyknight at google.com> > wrote: > > > > We don't *need* it, no. But it might be useful. >