search for: uglili

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2008 Dec 18
3
Parsing unusual date format
Hello, If I have a character string like d <- c("1990m3", "1992m8") #March 1990 and Aug 1992 what is the easiest way to convert it into any standard date form; for example, d <- c("01/03/1990", "01/08/1992") I looked at as.Date but it doesn't seem to address my problem as I have an "m" stuck in the middle of my character string