Displaying 5 results from an estimated 5 matches for "ughhhh".

2017 Aug 23

1

Getting all possible combinations

On Wed, Aug 23, 2017 at 12:35 PM, Bert Gunter <bgunter.4567 at gmail.com> wrote:
> ummm, Ista, it's 2^n.
ummm yes ughhhh.
My point is, if the number of groups is large, check it before hand.
If you can check it without embarrassing yourself in public like I did
that's even better.
Best,
Ista
>
> Cheers,
> Bert
>
>
> Bert Gunter
>
> "The trouble with having an open mind is that peop...

2017 Aug 23

1

Getting all possible combinations

> On 23 Aug 2017, at 20:51 , Ista Zahn <istazahn at gmail.com> wrote:
>
> On Wed, Aug 23, 2017 at 12:35 PM, Bert Gunter <bgunter.4567 at gmail.com> wrote:
>> ummm, Ista, it's 2^n.
>
> ummm yes ughhhh.
>
You didn't really say otherwise: sum(choose(n,0:n)) == 2^n by the binomial expansion of (1+1)^n (but you knew that)
This points to a different algorithm where you write 0:(2^n-1) as n-digit binary numbers and chose items corresponding to the 1s. That won't give the combinations sor...

2017 Aug 23

1

Getting all possible combinations

...gaard <pdalgd at gmail.com> wrote:
>
>> On 23 Aug 2017, at 20:51 , Ista Zahn <istazahn at gmail.com> wrote:
>>
>> On Wed, Aug 23, 2017 at 12:35 PM, Bert Gunter <bgunter.4567 at gmail.com> wrote:
>>> ummm, Ista, it's 2^n.
>>
>> ummm yes ughhhh.
>>
>
> You didn't really say otherwise: sum(choose(n,0:n)) == 2^n by the binomial expansion of (1+1)^n (but you knew that)
>
> This points to a different algorithm where you write 0:(2^n-1) as n-digit binary numbers and chose items corresponding to the 1s. That won't give...

2017 Aug 23

2

Getting all possible combinations

ummm, Ista, it's 2^n.
Cheers,
Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along
and sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Wed, Aug 23, 2017 at 8:52 AM, Ista Zahn <istazahn at gmail.com> wrote:
> On Wed, Aug 23, 2017 at 11:33 AM, Christofer Bogaso
>

2011 Aug 17

7

XCP GUI management

Xen List
After planning for a year to move my Xen 3.4 classrooms to XCP I''m now
making an effort. With the old system I wrote many lines of bash scripts
around the xm command to group and manage my VMs. I used sudo to grant
privileges for each student to start, stop, console into, reboot, and wipe
their VMs without any interaction from me. Now with XCP I had the hope of
moving to the