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Hi, Recently I have installed R version 2.14.1, after installation I am trying to install some packages and I get error message. even I tried install.packages("Rcmdr") but still I am unable to fix this problem. I would be very grateful if somebody can help me to fix this problem. install.packages("hdf5") Installing package(s) into

I have some data set which is available from 2005-2010 . I would like plot monthly maps out of it. So how I should write loop that can plot this yearly data to for every month and write title for individual months too. -- View this message in context: http://r.789695.n4.nabble.com/Plotting-monthly-maps-from-yearly-data-tp4391704p4391704.html Sent from the R help mailing list archive at

I would like to calculate vector from existing value e.g v <- 1000 s <- 30 d1 <- v-s d1 <- 970 d2 <- d1 -s d2 <- 940 d 3 <- d2-s d3 <- 910 : : d15 <- ..... so how I should get vector of length 15 d < - 970,940 , 910 , ....... -- View this message in context:

I have some data files e.g 100 . and after for loop I would like to save all data in one single data frame file_s <- list.files(path = ".", pattern = "v2.0.2.txt", all.files = FALSE, full.names = FALSE, recursive = FALSE, ignore.case = FALSE) for (i in 1:100){ data = read.table(file_s[i],header=TRUE) lat = data[,7] # latitude lon

I have 100 data files, which contains very huge data sets of location details ( e.g latitude, longitude, time, temp) Now I would like to save the all data of these 100 files in r object, so I can reload data any time. * Every file has different length of data latitude <- NULL longitude <- NULL time <- NULL temp <- NULL for ( i in 1:100) { data<-

I would like to plat some spaghetti plots from my data , ma data is as follows ak[1:3,] [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [1,] 0.3211745 0.4132568 0.5649930 0.6920562 0.7760113 0.8118568 0.8609301 0.9088819 0.9326736 [2,] 0.3159234 0.4071270 0.5579212 0.6844584 0.7684690 0.8243702 0.8677043 0.8931288 0.9261926 [3,] 0.3075260 0.3993699

I have two different datasets 1) is in monthly format (obs) 2) yearly format (model) in obs I have 84 files ( 2003:2009)for different months & in model I have 4 different files which has yearly data (2005:2008) So for calculating my requirement I need these both data sets. The sample calculations are as follows file_o<-list.files(path=' ', pattern="0.2.text") #

I got two .RData file e.g data.2005.RData & data.2006.RData I would like to combine these two different data set and make single RData file. in both file there are some NULL files are also available and I would like to clear this NULL files also. $ : NULL $ : NULL $ : num [1:43285, 1:8] -21.1 -21.1 -24.9 -24.9 -24.9 ... ..- attr(*, "dimnames")=List of 2 .. ..$ : NULL ..

I have some time data and which is in seconds time <-c( 126230400 126252000 126273600 126295200 126316800 126338400) now I wanted to convert this time to Y M D H M S format I have tried following codes but it does not give me the out put in Y M D H M S time_t1 <- as.POSIXlt(time, origin="2005-01-01", tz="GMT") & time_f <- as.POSIXct(time,

I have data that looks like this: > df1 group id 1 red A 2 red B 3 red C 4 blue D 5 blue E 6 blue F I want a list of the groups containing vectors with the ids. I am avoiding subset(), as it is only recommended for interactive use. Here's what I have so far: df1 <- data.frame(group=c("red", "red", "red", "blue",

I want to use spplot function for plotting data on wold map spplot.points(obj, zcol = names(obj), ..., names.attr, scales = list(draw = FALSE), xlab = NULL, ylab = NULL, aspect = mapasp(obj,xlim,ylim), panel = panel.pointsplot, sp.layout = NULL, identify = FALSE, formula, xlim = bbexpand(bbox(obj)[1, ], 0.04), ylim = bbexpand(bbox(obj)[2, ], 0.04)) in this function I would like to set

This moment I got stuck with one interpolation issue the sample data which I have is as follows pre1 <- c(10.34615 , 52.02116, 146.17357, 243.28644, 347.41504, 431.67105, 521.42712, 629.00446 ,729.95941, 827.86279, 921.55078, 956.44446) pre2 <- c( 983.4477692, 973.6199013, 958.0722141, 938.8194208 ,915.1833983, 852.1671089, 765.0037479,

I have some data set which has some values -999.000 & I would like to remove whole row of this kind of values. e.g a<-matrix(c(1,2,3,4,4,5,6,6,-999.99,5,9,-999.00),nrow=4) a<- [,1] [,2] [,3] [1,] 1 4 -999.99 [2,] 2 5 5.00 [3,] 3 6 9.00 [4,] 4 6 -999.00 expected answer [,1] [,2] [,3] [1,] 2 5 5.00 [2,] 3 6 9.00 I

I new in R programming language. I have some time data time [1] "2005-01-03 05:11:39 UTC" "2005-01-03 06:36:02 UTC" "2005-01-03 06:36:55 UTC" [4] "2005-01-03 06:37:00 UTC" "2005-01-03 06:38:04 UTC" "2005-01-03 06:38:04 UTC" [7] "2005-01-03 06:38:04 UTC" "2005-01-03 06:38:04 UTC" "2005-01-03 06:38:05

I would like to read data from two different folder and then combine this together the code which I have tried are as follows setwd("/Groups/data_first/") file_was <- list.files(path = ".", pattern = "v2.0.2.was", all.files = FALSE, full.names = FALSE, recursive = FALSE, ignore.case = FALSE) path<-c("/Groups/data_second/") file_wasaux2

I am using following codes to plot map library(sp) library(rgdal) library(maps) library(gplots) library(clim.pact) library(fields) source("/R/PlotGridded2DMap.R") source("/R/image.plot.fix.R") source("/R/image.plot.plt.fix.r") seasonal_plot<-function(input,lonll=-180,latll=-90,lonres=5.,latres=3.75,write_file=TRUE,The_title=NULL){ if(is.null(The_title)){